A Rich has been hooked and is puilling on the line as shown in the figure below.
RO
18
If the pole makes an angle of 25° with the horizontal, the distance between the point where the line is attached to the pole and the anglers hand is L. 2.45 m, and the fish
pulls on the line such that the tension in the line is T-166 Nat an angle 35.0 below the horizontal, determine the magnitude (in N.m) of the torque exerted by the fish
about an axis perpendicular to the page and passing through the angler's hand.
Nm

Answers

Answer 1

For the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand is mathematically given as

Z = 360.33Nm

What is the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand?

Generally, the equation for the Torque is mathematically given as

Z = force x perpendicular distance

Z = Tcos30° x L

Z = 166(0.886) x 2.45

Z = 360.33Nm

In conclusion s the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand

Z = 360.33Nm

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Related Questions

Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) + 3P4 (s) → 3P4O10 (s) + 10 KCI (s) How much of each reactant will be needed to produce 105.8 g of tetraphosphorus decaoxide (P4O10)?​

Answers

Answer:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)


Explanation:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

m(P4) = M(P4)*m(P4O10)/M(P4O10)
          = 123.90*105.8/283.89
          = 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
                = 10*122.55*105.8/283.89/3
                = 149 (grams).

149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .

What do you mean by reactant?

In a chemical equation, the substance or substances to the left of the arrow are referred to as reactants. A substance that is present when a chemical reaction first begins is known as a reactant.

Products refer to the material or substances to the right of the arrow. A substance that is present after a chemical reaction is complete is called a product.

Given Data:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)

Then it is given by:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

The equation becomes :

m(P4) = M(P4)*m(P4O10)/M(P4O10)

         = 123.90*105.8/283.89

         = 46.175 (grams)

2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)

               = 10*122.55*105.8/283.89/3

               = 149 (grams).

Thus, 149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .

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- A teenage male is removing clothes from the dryer and is having difficulty because the items are
sticking together.
-What force is causing the clothes to stick together?
-What two factors in the dryer operation has produced this situation?
-What will misting the clothes with a light spray of water do?

Answers

We can confirm that the clothes are sticking together due to static forces created by the heat and friction of the dryer.

How will water help with this situation?

The clothes are stuck together due to static forces that arise when these materials are heated and the friction from the dryer cycle. Adding a light spray of water can help with this situation given that water is a strong conductor of electricity, which will help to dispel the charges that hold the clothes together.

Therefore, we can confirm that clothes are sticking together due to static forces created by the heat and friction of the dryer, which a light spray of water can help to dispel and separate the clothes.

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can i get some help please

Answers

Answer:

B. They reproduce

Explanation:

Both arent made up of one cell, and both arent made up of mutliple cells. Only some unicellular and multicellular organisms are infectious.

Answer:

Your answer would be:
B.) They reproduce.

Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism, while multicellular organisms use many different cells to function. Multicellular organisms are composed of more than one cell, with groups of cells differentiating to take on specialized functions.

Unicellular organisms are made up of only one cell that carries out all of the functions needed by the organism. Multicellular organisms use many different cells to function.


Unicellular organisms are single-celled.

Multicellular organisms are multi-celled.
However, both reproduce.




Explanation:

Have a great rest of your day
#TheWizzer

how many snow leopards live together in the wild (give a number or tell if they are solitary?)

Answers

Snow leopards are solitary... If you ever see a two or more snow leopards together, consider yourself extremely lucky! Fun fact: There is no term for a group of snow leopards because it is so rare to see them in a group!

Your welcome!

A box weighing 8 newtons requires a force of 2 newtons to push it along the floor. The coefficient or friction Berween the box and the floor is_?​

Answers

I believe the answer is 16.

 Have a blessed day!

3. Hahn determined that barium (atomic number 56) was one of the elements created when a uranium atom (atomic number 92) split . Use a periodic table to determine the other element that was created during this process.​

Answers

According to a periodic table, Krypton was created during the fission of Uranium.

What is the atomic number?

Atomic number is a characteristic associated with an element and indicates its number of protons, when a fision occurs, the total number protons is conserved.

Thus, the fission of uranium is led by two elements with atomic numbers 56 and 36. According to a periodic table, those atomic numbers are associated to elements Barium (Ba) and Krypton (Kr), respectively.

According to a periodic table, Krypton was created during the fission of Uranium. [tex]\blacksquare[/tex]

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-What is the potential energy at point A?

-What is the kinetic energy at point A?

-What is the kinetic energy at point B?

-What is the potential energy at point D?

-What is the kinetic energy at point D?

Answers

Answer:

1560520156

Explanation:

Assuming there is no friction or other force involved, recall that energy is conserved in a system as long as no external force acts on the system.

Using the data from point C, we can find out that the total energy of the system is 156 because  [tex]E = K+Pe[/tex].

Since at point A the object doesn't move, it has Kinetic energy of 0, because [tex]K=\frac{1}{2} mv^2[/tex], therefore [tex]0=\frac{1}{2} m0^2[/tex]. However at point A it has maximum Potential energy, because [tex]Pe=mgh[/tex].

At point B, we can find the Kinetic energy by using [tex]E = K+Pe[/tex]. Substitute values:

[tex]156=104+K\\52=K[/tex]

At point D, the object has maximum kinetic energy and no potential energy, therefore it's the opposite of point A.

find the half life of a radioactive natural which decays to 6.25% of it's original no. of nuclei in 50 seconds.

Answers

Answer:

After 1 decay it has .9375 of its value left  

.9375^n = 1/2

What is the value of n (number of decays)

n log .9375 = -.693

n =.693 / .0645 = 10.7

After 10.7 periods of 50 sec it will have 1/2 of its original nuclei left

1/2 life = 10.7 * 50 sec = 537 sec = 8.95 min

The density of lead is 30.2g/cm^3.what is the value in kilograms per meter cube?

Answers

Answer:
11300 kgm3

Hope this helps

Mrs. dela Vega had 27 students in her class last year and this year she had 30 students in her math class. What is the percent of difference?

Answers

The class grew by (30-27) = 3 students.

3 is (3/27) = 1/9 of its original size.

The class grew by 1/9 or 11.1 % .

Yesterday you walked 20 meters to the right from your house to the bus stop, which took you 20 seconds. You waited at the bus stop for 1 minute before realizing you forgot your Mathematics homework at home. You ran back to your house in 5 seconds. It took you 10 seconds to find your homework, and then you ran back to the bus stop in 5 seconds just in time to catch the bus. What was your average velocity for the entire period of motion?



a.
0.2 m/s


b.
1 m/s

c.
100 m/s

d.
20 m/s

Answers

average velocity= tot displacement/total time

avg v = 20/(20+60+5+10+5)=20/100=0.2 m/s

I’ve tried my hardest n just keep blowing my head please help!!

Answers

Answer:

Forces

Explanation:

1) A Force

2) Balanced

3) Unbalanced

4) Any object moving at a constant speed, Any object in 0 motion, A balanced see-saw (no net torque/forces)

5) Any object accelerating, Someone pushing a box

A 0.60- m -tall barrel is filled with water (with a weight density of 9800 N/m3 ). Find the water pressure on the bottom of the barrel. Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

P =  ρ g H       explains the pressure of a uniform column of density ρ

P = ρ H            where ρ is given as a weight density

P = 9800 N/m^3 * .60 m = 5880 (5900) N / m^2

Note N/m^2 = Force / Area      the definition of pressure

A particle (q = +5.0 µC) is released from rest when it is 2.0 m from a charged particle which is held at
rest. After the positively charged particle has moved 1.0 m toward the fixed particle, it has a kinetic
energy of 50 mJ. What is the charge on the fixed particle?
a. –2.2 µC
b. +6.7 µC
c. –2.7 µC
d. +8.0 µC
e. –1.1 µC

Answers

The answer to your question is A. Have a great day

The kinetic energy of the charged particle is equal to the work done to bring it from the distance of 1 m. Hence, the total electric force here is 0.025 N. Therefore, the charge on the fixed particle is  approximately + 6.7 µC.

What is Coulomb's law ?

According Coulomb's law the electrostatic force between two charges is given by ,

F =  k q1 q2 /r²

Where q1 and q2 be the charges and r be the distance between them, k be the constant equal to 8 × 10⁹ N m²/C².

Given q1 = + 5  µC

r = 1 m.

the kinetic energy in bringing the charge of  5 µC from 2 m is given 50 mJ.

then F = 0.05 J/2 m = 0.025 N

Then q2 = F r²/ (q1 K)

q2  = 0.025 N / ( + 5  µC × 8 × 10⁹ N m²/C²)

      =  6 µC.

Therefore, option b is the approximate charge of the fixed particle.

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ture or false
A land breeze is when the cooler air over the ocean moves in toward land.

Answers

Answer:

False

Explanation:

A land breeze is when air flows from land to water. The question above is describing a sea breeze, which is when cool ocean air blows toward land.

help me solve the following question below in the attachment

Answers

Answer:

Explanation:

The point P is influenced by two electric fields, that are from Q1 and Q2. Because Q1 is a positive point charge, the E-fields is going to the right and the E-fields from Q2 is going to the left because of negative point charge. So:

[tex]E_{1}=\frac{kQ_{1}}{R_{1}^{2}}[/tex]

[tex]E_{2}=\frac{kQ_{2}}{R_{2}^{2}}[/tex]

Where R1 = 2 + 3 = 5 m, and R2 = 3 m. With k = [tex]k=9\times 10^{9}[/tex] in [tex]Nm^{2}/C^{2}[/tex], we can obtain:

[tex]E_{1}=(9\times 10^{9})\frac{500\times10^{-6}}{25}=180\times 10^{3}[/tex] N/C (+)

[tex]E_{2}=(9\times 10^{9})\frac{100\times 10^{-6}}{9}=100\times 10^{3}[/tex] N/C (-)

So: the Electric Field at P : [tex]E_{P}=E_{1}-E_{2}=(180-100)\times 10^{3}=8\times 10^{4}[/tex] N/C in magnitude

Find the Product or expression of: (4x-2)2​

Answers

Answer:

8x-4

Explanation:

Distributive property:

A(B+C)=AB+AC

(4x-2)2

Switch sides.

→ 2(4x-2)

Multiply.

⇒ 2*4x=8x

⇒ 2*2=4

Rewrite the problem down.

⇒ = 8x-4

[tex]\Longrightarrow: \boxed{\sf{8x-4}}[/tex]

Hence, the final answer is 8x-4.

I hope this helps you! Let me know if my answer is wrong or not.

Answer: 8x - 4

Explanation:

(4x -2)*2

apply distributive property

2* 4x - 2 * 2

Multiply the monomials = 8x

2*4x - 2*= 8x-2*2

calculate =

8x-4

Answer: 8x - 4

(a) In Coulomb scattering of 7.50-MeV protons by a target of 'Li, what is the energy of the elastically scattered protons at 90°? (b) What is the energy of the inelastically scattered protons at 90° when the 'Li is left in its first excited state (0.477 MeV)?

Answers

Answer:

First the charge is given 7.50×10^-6

Explanation:

so that we have

[tex]90 [/tex]

so that their is no cross sectional area of this angle

then the direction is one is left and other one is right so thats my hint

QUESTION 9
What determines the evolutionary path a star takes through its life?
O a. Diameter
O b. Who made it
O c. Color
O d. Mass

Answers

Answer:

Mass

Explanation:

In the core of the red giant, helium fuses into carbon. All stars evolve the same way up to the red giant phase. The amount of mass a star has determines which of the following life cycle paths it will take from there. The life cycle of a low mass star (left oval) and a high mass star (right oval).May 7, 2015

The answer would be mass

What is the magnitude of the electric field 3m away from the source if the electric potential is described by the function f(x)=2x+3, where x=2?

Answers

Hi there!

Recall the following relationship between the electric field and electrical potential:
[tex]E = -\frac{dV}{dx}[/tex]

Begin by taking the derivative of the electric potential function using basic power and constant rules.

Remember:
[tex]\frac{dy}{dx}x^n = nx^{n - 1}[/tex]

[tex]\frac{dy}{dx}(C) = 0[/tex]

Differentiate the function, and take its negative.

[tex]-\frac{dV}{dx} = -(2(1)(x^{1-1}) + 0 )\\\\-\frac{dV}{dx} = -2[/tex]

The magnitude is the absolute value, so:
[tex]|\frac{dV}{dx} = |-2| = \boxed{2 \frac{V}{m}}[/tex]

4. The 50-kg crate shown in Fig. rests on a horizontal surface for which the coefficient of
kinetic friction is u - 0.3. If the crate is subjected to a 400-N towing force as shown,
determine the acceleration of the crate.
your
P = 400 N
490.5 N
400 N
too

30
30°
+
F-0.3 Nc
Nc
ΣΕ = max
Σ F, = may
A. a = 4. 185 m/s2
B. a = 5. 185 m/s2
C. a = 6. 185 m/s2
D. The entire above are false

Answers

Answer:

5.057 m/s^2

Explanation:

Force of kinetic friction = .3  = F /normal force

  .3 = F /(50* 9.81)     F of friction = 147.15

Net force =   400 - 147.5  =  252.85  N

F = m * a

252.85 = 50 * a       a = 5.057 m/s^2

write about Archimedes principle​

Answers

Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially, is equal to the weight of the fluid that the body displaces. Archimedes' principle is a law of physics fundamental to fluid mechanics.

Answer:

When a body is immersed fully or partially in a fluid, it experience is an upward force that is equal to the weight of the fluid displaced by it.

Applications:In designing ships and submarines.Lactometers used to determine the purity of sample of milk.Hydrometer is used to determine the density of liquids.

The reasoning question please i need help

Answers

Answer:

speed of the friend that is 8m from the center:

0.8π m/s

the distance she will travel in one rotation is:

10

Her speed compared to you is faster because, she is farther away from the axis compared to you.

Explanation:

for the speed, it says the farther you are from the axis the greater your speed is, and for the person who was 4m from the axis of rotation their speed was 0.4 because they are closer to the axis so therefore their speed is slower. so for the friend that is 8m from the axis of rotation its most likely their speed would be 0.8 m/s.

in one revolution you travel 8m your original distance from the axis was 4m so, 8-4 = 4, which means one revolution is plus 4 to your original distance. since the question is asking for rotation and not revolution you can do 4 ÷ 2 which is 2, so for rotation you need to add 2 to your original distance, so 8 + 2 = 10

A single coil of wire, with a radius of 0.13 m is rotated in a uniform magnetic field such that the angle between the field vector and the area vector obeys θ=ωt. If the strength of the field is 3.746 T, and the angular frequency is 524.7 rad/s, what is the induced emf in the loop at t=1.16 s?

Answers

The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.


Induced emf

The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.

emf = N(dФ/dt)

where;

N is number of turns of the wireФ is magnetic flux

Ф = BA

where;

B is magnetic field strengthA is the area of the loop

emf = NBA/t

A = πr²

A = π x (0.13)²

A = 0.053 m²

emf = NBA/t

emf = (1 x 3.746 x 0.053)/(1.16)

emf = 0.171 V

Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.

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In a circuit, we are using conducting wires made from Manganese.
(i) If we assume there are 3 free electrons per an atom of manganese, what is its
electron density?
(ii) How much current flows through a cylindrical manganese wire of volume 27 cm3,
length 3cm if the circuit is switched on for 5 seconds?

Answers

i. The electron density of maganese is 2.44 × 10²⁸ electrons/m³

ii. The current that flows through a cylindrical manganese wire of volume 27 cm3 is 21.11 kA

To solve the question, we need to know what electron density is.

What is electron density?

This is the number of free electrons per unit volume of material.

To find electron density, we need to find the atom density which is the number of atoms per unit volume, n.

Atom density of manganese

So, the atom density of manganese is n = Nρ/A where

N = avogadro's number = 6.022 × 10²³ atoms/mol, ρ = density of manganese = 7430 kg/m³ and A = atomic mass of manganese = 0.0594 kg/mol

So, n = Nρ/A

n = 6.022 × 10²³ atoms/mol × 7430 kg/m³/0.05494 kg/mol

n = 44743.46 × 10²³ atoms/mol × kg/m³/0.05494 kg/mol

n = 81440.59 × 10²³ atoms/m³

n = 8.144059 × 10²⁷ atoms/m³

n ≅ 8.14 × 10²⁷ atoms/m³

i. Electron density of manganese

The electron density of maganese is 2.44 × 10²⁸ electrons/m³

So, the electron density of manganese n' = n" × n where

n" = number of free electrons per atom = 3 and n = atom density = 8.14 × 10²⁷ atoms/m³

So, n' = n" × n

= 3 electrons per atom × 8.14 × 10²⁷ atoms/m³

= 24.42 × 10²⁷ electrons/m³

= 2.442 × 10²⁸ electrons/m³

≅ 2.44 × 10²⁸ electrons/m³

So, the electron density of maganese is 2.44 × 10²⁸ electrons/m³

ii. How much current flows through the cylindrical maganese wire?

The current that flows through a cylindrical manganese wire of volume 27 cm3 is 21.11 kA

The current flowing through the wire is given by i = n'eV/t where

n = electron density = 2.44 × 10²⁸ electrons/m³, e = electron charge = 1.602 × 10⁻¹⁹ C, V = volume of wire = 27 cm³ = 27 × 10⁻⁶ m³ and t = time current flows = 5 s

So, substituting the values of the variables into the equation, we have

i = n'eV/t

i = 2.44 × 10²⁸ electrons/m³ × 1.602 × 10⁻¹⁹ C × 27 × 10⁻⁶ m³/5 s

i = 105.54 × 10³ C/5 s

i = 21.11 × 10³ C/s

i = 21.11 × 10³ A

i = 21.11 kA

So, the current that flows through a cylindrical manganese wire of volume 27 cm3 is 21.11 kA

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solve ~
[tex]13x - 26 + 39 = 0[/tex]

ty! :)

Answers

Explanation:

13x - 26 + 39 = 0

13x=26-39

13x=-13

x= -1

[tex]13x-26+39=0\\\\\implies 13x +13 = 0\\\\\implies 13x = -13\\\\\implies x = -\dfrac{13}{13}\\\\\implies x = -1[/tex]

A man is pushing a large box with a force of 44 newtons. He slides over a floor that has a sliding frictional force of 12 Newtons. What is the acceleration?

Answers

I’m sorry I was not texting lol but 12 subduing and I got a phone call back to you later on for your birthday 17 wyd

A steam engine is working. What is the transformation of energy?​

Answers

As its name suggests, the steam engine operates on the force of water vapor (steam) heated to high pressure. It is a technology that converts thermal energy (heat) to mechanical energy (work).

curd is made from milk... t or f​

Answers

Explanation:

Curd is made from milk . ( True )

Curd is made by bacterial fermentation of milk.

Answer:

very true

curd is made from warm milk and a bacterial youghurt starter and it aslo has been used for many years

pleaseee pretty please put me as brainliest

Problem 19: Oil with a density of 892 kg/m is flowing smoothly through a pipe, as
shown. In the lower portion, the oil is flowing at vi = 1.84 m/s, and the pressure gauge
indicates P, = 237 kPa. In the upper portion of the pipe, oil is flowing at V2 = 3.61 m/s at a
height that is 8.63 m above the lower portion.

Answers

The pressure of the oil with the given properties flowing in the horizontal pipe at the upper portion of the pipe is 157 kPa.

Pressure in the upper portion of the pipe

The pressure in the upper portion of the pipe is calculated by applying Bernoulli's equation,

P₁ + ¹/₂ρv₁² + ρgh₁ = P₂ + ¹/₂ρv₂² + ρgh₂

Given;

P₁  = 237 kPav₁ = 1.84 m/sh₁ = 0v₂ = 3.61 m/sh₂ = 8.63 mρ = 892 kg/m³P₂  = ?

Susbtsitute the given parameters and solve the for the pressure in the upper portion of the pipe.

237,000 + ¹/₂(892)(1.84)² + (892)(9.8)(0) = P₂ + ¹/₂(892)(3.61)² + (892)(9.8)(8.63)

238,509.9776 = P₂ + 81,252.325

P₂ = 238,509.9776 - 81,252.325

P₂ = 157,257.65 Pa

P₂ ≅ 157 kPa

Thus, the pressure of the oil with the given properties flowing in the horizontal pipe at the upper portion of the pipe is 157 kPa.

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