Hi there!
We can begin by using Coulomb's Law:
[tex]E = \frac{kq}{r^2}[/tex]
k = Coulomb's Constant (8.99 × 10⁹ Nm²/C²)
E = Electric field strength (N/C)
r = distance from point (m)
q = charge (C)
Since this is a continuous charge, we must use calculus.
We can express this as the following:
[tex]q = \lambda L[/tex]
λ = Linear charge density (C/m)
L = Length of rod (m)
Now, since this is an arc, L = s (arc length). Additionally, we must find the differential elements of each:
[tex]dq = \lambda ds\\\\dq = \lambda rd\theta[/tex]
Our new equation is:
[tex]dE = \frac{kdq}{r^2}\\\\dE = \frac{k\lambda rd\theta}{r^2}[/tex]
However, we will only take the cosine component of the electric field since the vertical components will cancel out. (Electric fields are a vector). Therefore:
[tex]dE = \frac{k\lambda rd\theta}{r^2}cos\theta\\\\dE = \frac{k\lambda}{r}cos\theta d\theta[/tex]
Integrate. For a semicircle, the bounds will be from -π/2 to π/2.
[tex]E = \frac{k\lambda}{r}\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}}} {cos\theta} \, d\theta\\\\E = \frac{k\lambda}{r}sin\theta\left \|{\frac{\pi}{2}} \atop {-\frac{\pi}{2}}} \right. \\\\E = \frac{k\lambda}{r}(1 - (-1)) = \frac{2k\lambda}{r}[/tex]
We need to solve for λ, which is Q/ L:
[tex]\lambda = \frac{3.10 \times 10^{-9} C}{\pi (0.05)} = 1.9735 \times 10^{-8} \frac{C}{m}[/tex]
Now, plug and solve for the electric field strength:
[tex]E = \frac{2(8.99\times 10^9)(1.9735\times 10^{-8})}{0.05} = \boxed{7096.783 \frac{N}{C}}[/tex]
**A diagram was not provided, but if the hemisphere's focus was to the right, the electric field would be to the right, and etcetera.
If a lever was a meter long and the fulcrum was placed at 50mm, what would the mechanical advantage be?
Please show work if possible
Answer:
The mechanical advantage would depend on where the load force and the balancing force were placed on the stick
MA = (50 - F) / (L - 50)
Supoose the balancing force was placed at zero and the load at 75 cm
then MA = (50 - 0) / (75 - 50) = 50 / 25 = 2
or the balancing force was applied at 10 cm and the load force was applied at 60 cm then
MA = (50 - 10) / (60 - 50) = 40 / 10 = 4
1. Discuss the two ways by which volcanoes are formed.
2. Does the theory of plate tectonics answer the question on why volcanoes erupt? Support your answer.
3. What are mantle plumes and where are they usually found?
4. What are the gases released by volcanoes in smaller amounts?
5. Extinct volcanoes may be classified as inactive volcanoes but this doest not mean they will not erupt again. Explain this statement.
Answer:
1.Divergent boundaries (crust moves apart, magma fills in) Convergent boundaries (magma fills when one plate goes beneath another) Hot spots (a large magma plume rises from mantle)
2.Some mountains are made of solid rock, like the Rocky Mountains or the Swiss Alps. But, some mountains are actually volcanoes.
3.an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma.
4.hydrogen sulfide, carbon monoxide, hydrogen chloride, hydrogen fluoride, and other minor gas species.
5.Extinct volcanoes are not expected to erupt in the future. Inside an active volcano is a chamber in which molten rock, called magma, collects. Pressure builds up inside the magma chamber, causing the magma to move through channels in the rock and escape onto the planet's surface.
Explanation:
hope its help:)
An object with a mass of 70.5 kg is placed on a 2-meter strand of metal (with a 2-millimeter radius) hanging from the ceiling. It stretches 1 millimeter. What is this strand made of?
Based on the value of the Young's modulus, the strand of the metal is made of copper.
Young's modulus of the metalThe Young's modulus of the metal is calculated as follows;
E = stress/strain
Stress of the metalThe stress of the metal is calculated as follows;
σ = F/A = mg/A
where;
A is area of the metal
A = πr²
A = π( 2 x 10⁻³)²
A = 1.257 x 10⁻⁵ m²
σ = (70.5 x 9.8) / (1.257 x 10⁻⁵)
σ = 5.5 x 10⁷ N/m²
Strain of the metalThe strain is calculated as follows;
strain = x/L
where;
x is extension
L is original length
strain = (1 x 10⁻³ m) / 2 m
strain = 5 x 10⁻⁴
Young's modulus of the metal
E = stress/strain
E = (5.5 x 10⁷ ) / (5 x 10⁻⁴)
E = 1.1 x 10¹¹ N/m²
E = 110 Gpa
The Young's modulus of copper metal is 110 Gpa
Thus, based on the value of the Young's modulus, the strand of the metal is made of copper.
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6. When can you say that an object is accelerating?
A. when the speed remains the same
B. When the speed is changing
C. when the instantaneous velocity is the same
D. When there is a uniform motion
give explanation
Answer:
When the speed is changing is the correct answer
Explanation:
Because acceleration is rate of change of velocity
PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE
[tex]Question: $x_{1}=\frac{5}{2}[\sin (2 \pi t)+\cos (2 \pi t)], x_{2}=5\left[\sin \left(2 \pi t+\frac{\pi}{4}\right)\right]$[/tex]
Find the ratio of the amplitude of the given motion?
Options:
[tex](a) $\sqrt{2}: 1$\\(b) $2: 1$\\(c) $1: \sqrt{2}$\\(d) $1: 2$[/tex]
Condense x₁ to get
sin(2πt) + cos(2πt) = √2 • (sin(2πt) + cos(2πt))/√2
… = √2 (cos(2πt) cos(π/4) + sin(2πt) sin(π/4))
… = √2 cos(2πt - π/4)
So the amplitude of x₁ is (5/2) • √2 = 5/√2, while the amplitude of x₂ is 5. The ratio between them is then 5/√2 : 5, or equivalently 1/√2 : 1 or 1 : √2.
The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast would it be traveling just before it landed?
Answer:
Explanation:
You can use that [tex]v = v_{o}+gt[/tex] or [tex]v^{2}=v_{o}^{2}+2gh=(25)^{2}+(2)(10)(381)=8245 \rightarrow v \approx 90.8[/tex] m/s.
6. A spring is originally 1.5 m long. It is stretched so that it is 1.8 m long. The spring constant is 50 N/m.
Find the potential energy stored in the spring.
Answer:
PE = 1/2 K X^2
K = 50 N/m
X = .3 m
PE = 1/2 * 50 * .3^2 = 2.25 Joules
What is the cycle of a breaststroke?
Answer:
Breaststroke can be divided up into 4 distinct phases, which consists of the out sweep, in sweep, breathing phase, and lunge, extension, or recovery phase.
Explanation:
pa follow po
For the statements based on whether they are described as outcomes of results from thermal energy being added or removed particles move faster particles move slower temperature increases temperature decreases kinetic energy increases kinetic energy decreases thermal energy added thermal energy removed
The two basic properties of all matter are ______ and ______.
options for first blank
a. length B. volume
options for second blank
a. density B. mass
Answer:
volume , mass
Explanation:
the 3 basic properties of a matter is volume, mass and shape.
Year
Carbon Dioxide (CO2) in Atmosphere (ppm*)
2010
2011
Copyright © Enginuity Inc.
Copyright © Enginuity Inc.
Global Temperature Change – Student Guide
2012
2013
2014
2015
2016
2017
Answer:
Theres a diagram missing for Q
Explanation:
What is all this?
Could you add a question so I can answer it :)
If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial speed of 5 m/s, the snowboarder is moving to the right on the upper level. His final speed in this case is 3 m/s. Suppose this situation is repeated on planet Epsilon, where gravity is less than gravity on earth.
A. Would the height of the hill on Epsilon cause a reduction in speed from 4 m/s to 0 greater than, less than, or equal to the height of the corresponding hill on earth? Explain.
B. Consider the hill on Epsilon discussed in part A. If the initial speed at the bottom of the hill is 5 m/s, will the final speed at the top of the hill be greater than, less than, or equal to 3 m/s? Explain.
(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
Conservation of mechanical energy
The effect of height and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;
ΔK.E = ΔP.E
¹/₂m(v²- u²) = mg(hi - hf)
¹/₂(v²- u²) = g(0 - hf)
v² - u² = -2ghf
v² = u² - 2ghf
where;
v is the final velocity at upper levelu is the initial velocityhf is final heightg is acceleration due to gravitywhen u² = 2gh, then v² = 0,
when gravity reduces, u² > 2gh, and v² > 0
Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
Final speedv² = u² - 2ghf
where;
u is the initial speed = 5 m/sg is acceleration due to gravity and its less than 9.8 m/s²v is final speedhf is equal heightSince g on Epislon is less than 9.8 m/s² of Earth;
5² - 2ghf > 3 m/s
Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
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Match the missions with their objectives.
NEAR
Lunar Prospector
Deep Impact
SETI
mapping the Moon's surface composition,
looking for possible deposits of polar ice,
and examining the Moon's resources,
structure, and origins
first space probe to orbit and perform
an in-depth Investigation of an asteroid
searching for extraterrestrial life in the universe
probing beneath the surface of a comet to
obtain clues about its internal composition
and structure
Matching the missions with their objectives
NEAR -------> First space probe to orbit and perform an in-depth Investigation of an asteroid. Lunar prospector ----- > mapping the Moon's surface composition,looking for possible deposits of polar ice,and examining the Moon's resources,structure, and origins.Deep Impact -------> probing beneath the surface of a comet to obtain clues about its internal composition and structureSETI -----> searching for extraterrestrial life in the universeThe Mission OverviewThe NEAR ( Near Earth Asteroid Rendezvous ) is a mission whose objective is to study origin and nature of objects near the earth such as asteroids and comets.
Lunar prospector was a mission designed to perform an orbit investigation of the moon.
The deep impact mission created by NASA was to probe beneath the comet and discover the structure and composition. The deep impact projected lasted for 9 years in space.
Hence we can conclude that the missions and their objectives are as listed above.
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Can someone help with this
Hi there!
A.
We can use the work-energy theorem to solve.
Initially, both blocks have gravitational potential energy, which is then converted to kinetic energy.
Recall:
[tex]U = mgh \\[/tex]
U = Potential Energy (J)
m = mass (kg)
g = acceleration due to gravity (m/s²)
h = height (m)
And at the end, block 2 has both kinetic and potential energy. Kinetic is defined as:
[tex]KE = \frac{1}{2}mv^2[/tex]
v = velocity (m/s)
We can do a summation of initial and final forces.
Initial:
[tex]E_i = m_2g\frac{h}{2} + m_1gh[/tex]
Final:
[tex]E_f = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2[/tex]
Set the two equal (no energy loss in this situation) and solve for velocity.
[tex]m_2g\frac{h}{2} + m_1gh = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2\\\\m_2g\frac{h}{2} + m_1gh - m_2g\frac{3h}{2} = \frac{1}{2}m_2 v^2 + \frac{1}{2}m_1 v^2\\\\v^2 = \frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}\\\\v = \sqrt{\frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}}\\\\v = \boxed{3.704 \frac{m}{s}}[/tex]
**This can be solved in a simpler way using a summation of forces.
B.
Now, we can do a summation of forces to solve. First, we must solve for the acceleration of the system now that we have found the velocity. Use the kinematic equation:
[tex]v_f^2 = v_i^2 + 2ad[/tex]
Initial velocity is 0 m/s, so:
[tex]v_f^2 = 2ad\\\\a = \frac{v_f^2}{2d} = \frac{(3.704^2)}{2(2.10)} = 3.267 \frac{m}{s^2}[/tex]
Now, we can use a summation of forces for any block. We can do block 1:
[tex]\Sigma F = m_1g - T[/tex]
Using Newton's Second Law:
[tex]m_1a = m_1g - T\\\\T = m_1g - m_1a \\T = m_1 (g - a) = 4.10(9.8 - 3.267) = \boxed{26.828 N}[/tex]
Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true? (1 point)
O Waves that make up the radiation collide with each other so that they add together or cancel each other out.
O Particles that make up the radiation collide with each other so that they add together or cancel each other out.
O Particles that make up the radiation collide with each other and scatter randomly.
O Waves that make up the radiation do not interact with each other.
Waves that make up the radiation collide with each other so that they add together or cancel each other out.
What is Interference?This is the phenomenon which occurs when two waves meet while traveling along the same medium.
In the double-slit test experiment, bright and dark fringes was observed which was caused by the superposition of overlapping light waves originating from the two slits which is why option A was chosen as the most appropriate choice.
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list down the general of the office of guardian and tutor
Answer:
legal guardians, the four types: personal guardians, financial guardians, conservators, and pet “guardians”
1) How many joules of heat are required to raise the temperature of 550 g of water from
12.7 °C to 28.8°C ? Specific heat of liquid water is 4.184 J/g °C.
Answer:
Explanation:
You can use [tex]Q = mc\Delta T=(550)(4.184)(28.8-12.7)=37049.32[/tex] joule.
Microphones are used to convert sound vibrations to electrical signals. In one kind of microphone, sound waves move a coil of wire up and down in a magnetic field, as shown in (Figure 1). The coil shown has a diameter of 1.4 cm and has 100 turns; the 0.010 T magnetic field points radially out from the north pole to the south.
If the microphone's emf at some instant is 10 mV , what is the speed of the coil?
The speed of coil of the microphone is 0.227 m/s
What is a Microphones?
A microphone is a device used to transmit sound energy through electrical energy. it makes use of magnetic fields whose strength is measures in Tesla
Given data
D = 1.4cm = 0.014m
N = 100
B = 0.010T
emf = 10mV
speed = dx / dt = ?
solution
emf = N dΦ / dt
Φ = BA
A = 2 pi R x
R = D / 2 = 0.014 / 2 = 0.007
emf = N d ( B 2 pi R x ) / dt
emf = N B 2 pi R dx / dt
and dx / dt = speed
speed = emf / N B 2 pi R
speed = 10 * 10 ^ -3 / ( 100 * 0.010 * 2 * 3.142 * 0.007)
speed = 10 * 10 ^ -3 / ( 0.043988 )
speed = 0.227 m/s
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ε = vLB
v - velocity = ?
ε - emf = 10mV = 0.01V
B - magnetic field = 0.010 T
L - length of wire = find
Find L
N - turns of wire = 100
d = diameter = 1.4 cm = 0.014 m
L = circumference of 1 turn of wire * # of turns of wire
L = 2πr * N
L = πdN
L = π * 0.014 m * 100
L = 1.4π m
Return to main equation
ε = vLB
[tex]v = \frac{\epsilon}{LB}[/tex]
[tex]v = \frac{0.01}{(1.4\pi)*(0.010)}[/tex]
v = 0.227 m/s
the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on the surface of its support.?
Answer:
your answer is here 180
Explanation:
900/2.5 * 2 = 180
Answer:
The answer is 180 Pa.
Explanation:
Given;Here, weight = thrust = 900 N,
dimensions are 2.5 m × 2 m × 1.2 m
To Find;Pressure exerted by the block on the surface of its support.Formula;Pressure = Thrust ÷ AreaWe know that, Pressure is inversely proportional to area. For the minimum pressure the area must be more.
So, if the block is resting with 2.5 m × 2 m surface on the support, the pressure will be minimum.
Pressure = 900 N ÷ 2.5 × 2.0 m² = 180 Pa
Thus, The pressure exerted by the block on the support is 180 Pa.
The measured value of mass M in an experiment is M = 0.743 ± 0.005kg. The error in 2M is
Select one:
dM
3dM
2.5 dM
2dM
Given the measured value of mass M in the experiment the error in 2M is ; dM
Given data :
Measured value of mass M = ( 0.743 ± 0.005 ) kg
The error in 2M in the measured valueThe error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM
Hence we can conclude that the measured value of mass M in the experiment the error in 2M is ; dM.
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What is the centripetal acceleration of 30 kg child standing 5 meters from the center of a
rotating carousel? The carousel is rotating at a linear velocity of 20 m/s.
Answer:
80m/s2
Explanation:
m=30kg. r = 5meter v = 20m/s2 a= ? centripetal acceleration = v*v/r
20*20/5=80m/s2
centripetal acceleration=80 m/s2
what are the four things that affect the resistance of a wire? A. length, diameter, material, and temperature B. weight, diameter, material, and temperature C. length, height, material, temperature D. length, weight, material, and temperature
Answer:
A. length, diameter, material, temperature
.
Which of the following is not true about the lymphatic system?
it drains white blood cells away from tissue
it brings nutrients to the tissue
it builds muscle cells
it fights infection
Answer:
it builds muscle cells
Explanation:
took test
is this right lol i think it is but im not so sure XD
[tex]\bold{Heya!}[/tex]
Yup. your answer is correct!
→ EXPLANATION :-1. just put the numbers in order [tex]^1^6^, ^1^8^,^2^3^,^2^4^,^2^9^,^3^0[/tex]2. Cross off high/low pairs, we left with the numbers :-[tex]23,24.[/tex]
3. Add the leftover numbers.[tex]23 \: + 24 = 47.[/tex]
Divide the sum of 2.[tex]\frac{47}{2} = 23.5[/tex]
Hopefully This Helps ! ~
#LearnWithBrainly
[tex]\underline{Answer :}[/tex]
Jaceysan ~
Answer:
GIVE HIM BRAINLEST
Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light? (1 point)
O 581 nm
O 420 nm
O 789 nm
O 591 nm
Answer:
The answer is 581
Explanation:
I just took the Quick Check and got it right.
1. A person walks 20 meters toward the east and then walks 30 meters toward the west. What is the total distance covered? What is the displacement? with explaination
2. What is the average speed of a car that travels 2000 meters in 5 minutes in meters/second? with explaination
Answer:
1.) 30 m is the total distance covered 10m is the displacement you
2.)24,000m/h (24km/h or 6.67m/s) Average speed is calculated by dividing the total distance that something has traveled by the total amount of time it took it to travel that distance
Explanation:
Which statement about the observed results of the double-slit experiment is true?
O Waves that are out of phase constructively interfere to create bright bands.
O Waves that are in phase destructively interfere to create bright bands.
O Waves that are in phase constructively interfere to create bright bands.
O Waves that are out of phase constructively interfere to create bright bands.
Waves that are in phase constructively interfere to create bright bands was observed in the double-slit experiment.
What is Interference?This is defined as the phenomenon which occurs when two waves meet while traveling along the same medium.
A wave when in phase undergoes constructive interference while out of phase undergoes destructive interference which is why option C was chosen as the most appropriate choice.
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Spring
The pulling force acting on an object is 350.0 N. It also is being affected by a 50.0 N
kinetic friction force. As a result, its acceleration is 3.0 m/s?, what is its mass?
A. 67 kg
B. 83 kg
C. 100 kg
D. 600 kg
E. 0.0 kg
If the gravitational force of the Farth nulling you"down" in th
Answer:
100 kg
Explanation:
Net force = 350 - 50 = 300 N
F= ma
300 N = m * 3 m/s^2
100 kg = mass
If a→=3i^-2j^-k^ and b→=i^+4j^+k^, find a unit vector n^ normal to the plane containing a→ and b→ such that a→, b→ and n^, in this order, form a right-handed system.
The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]
Given data :
The unit vectors
a→=3i^-2j^-k^ and b→=i^+4j^+k^
Determine the unit vector normal to the planeThe unit vector normal to the plane is calculated as
n = [tex]\frac{a*b}{|b*b|}[/tex] ---- ( 1 )
where ; a→ * b→ = 2i - 4j + 14k and |b * b| = [tex]\sqrt{216}[/tex]
back to equation ( 1 )
n = ( 2i - 4j + 14k ) / [tex]\sqrt{216}[/tex]
= [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]
Hence we can conclude that The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]
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Loosing weight without diet require moving to the top of a mountain explain using weight and gravitational force
Answer:
You would weigh very slightly more at sea level than at the top of a mountain, not enough for you to notice, but a measurable amount. Weight, which really means gravitational force, is proportional to the product of the masses of two objects acting on each other, in this case the giant earth and the minuscule you.
Explanation:
