Are constant functions periodic? The reason I ask this is because a function is periodic if it has a period but in a constant function the period could be infinitely small.

Answer:

p - 70

Step-by-step explanation:

70 less than p

Answer:

p - 70

Step-by-step explanation:

We're looking for the number of drawings Nora made, which is 70 fewer than Elise's, p. In instances like this, always subtract the number of less drawn from the quantity drawn by the other person, which is 70 - p. However, this would almost certainly result in a negative response, which isn't feasible. If you flip them over, you'll get p - 70.

Answer:

a. 5000 kg

b. 300 ml

c. 9 hours

hope it helps...!!!!

The probability that the number rolled is greater than 2 and the coin toss is heads is,

⇒  1/ 3

The term probability refers to the likelihood of an event occurring. Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one

Now, In probability theory, "AND" means multiplication and "OR" means "addition".

Hence, We can find the 2 probabilities separately and multiply them (as there is "AND")

So, Probability for number rolled greater than 2 = number of numbers that are greater than 2/total number of numbers

Since, There are 4 numbers greater than 2 in a die (3, 4, 5, 6) and total 6 numbers, so

P(number greater than 2) = 4/6 = 2/3

Now, Probability that heads come up in coin toss = 1/2 (there are 1 tail and 1 head in a coin)

Hence,

P(number greater than 2 and heads in coin) = 2/3 × 1/2 = 1/3

Thus, the probability that the number rolled is greater than 2 and the coin toss is heads is,

⇒  1/ 3

Learn more about the probability visit:

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Answer:

a. 6 kg.

b. 110 m long.

c. 60 ml of juice.

Step-by-step explanation:

b is the smallest and then a , d, c, e

Answer:  [tex]2^8 = 256[/tex]

Explanation:

The rule to use is

[tex]a^b \div a^c = a^{b-c}[/tex]

We subtract the exponents.

So in this case,

[tex]2^3 \div 2^{-5} = 2^{3-(-5)} = \boldsymbol{2^8} = \boldsymbol{256}[/tex]

Answer:

TRUE

Step-by-step explanation:

Do the pencil test . It doesnt have repeating X's.

Answer:

It is actually True so when you do it press true

Answer:

Step-by-step explanation:

Opposite angles of a cyclic quadrilateral sum to 180 so

m < x = 180-105 = 75 degrees

m < y = 180 - 95 = 85 degrees.

Step-by-step explanation:

A = 0.5(πr^2 )

A = 0.5(π × (20^2 ))

A = 628.32 units^2

Answer:

628.3 ft

Step-by-step explanation:

area of half circle = [tex]\frac{\pi r^{2}}{2}[/tex]

                             = [tex]\frac{\pi *20^{2} }{2}[/tex]

                             = 200[tex]\pi[/tex] = 628.3 ft

Answer: -1

Step-by-step explanation:

Answer: 3

Step-by-step explanation:

go in evenly

Answer:

im thinking that is 3/74 because i count them

Step-by-step explanation:

3/74 rhe answer but 3/77 are wrong he just thinking

Answer:

3 over 77, 3/77

Step-by-step explanation:

You add up all of the marbles. (including the blue ones)

30+28+13+6 = 77.

So. You have a 3/77 chance of pulling a blue marble.

Answer:

A. Similar triangles

Step-by-step explanation:

Triangle ABC

35° + 90° + x = 180°

125° + x = 180°

x = 180° - 125°

x = 55°

They are similar due to the occurrence in angles

Answer:

I think so none

answer to the following steps below:-

I hope my answer helps.

Answer:

yes,

Given value is Rational. The value is 0.6

Step-by-step explanation:

Step-by-step explanation:

in such cases we always try to split the complex figure into non-overlapping simple figures, calculate their areas and add them up.

what simple figures can we see here ?

I see a rectangle 80m × 130m.

and that leaves for me a right-angled triangle in the upper right corner with the legs of

250-80 = 170 m and 130-50 = 80 m

the area of a rectangle is

length × width

the area of a right-angled triangle is

leg1 × leg2 / 2

the individual areas are

80×130 = 10,400 m²

170×80/2 = 170×40 = 6,800 m²

and that gives us a total for the whole area

10400 + 6800 = 17,200 m²

Step-by-step explanation:

1) area = [tex]\pi[/tex] r^2

           = 3.14*(11)^2

           = 379.94inch

2)  area =  [tex]\pi[/tex]r^2

             = 3.14*(4)^2

             = 50.24/2 (semi circle)

             = 25.12yards square  

5. Let [tex]x = \sin(\theta)[/tex]. Note that we want this variable change to be reversible, so we tacitly assume 0 ≤ θ ≤ π/2. Then

[tex]\cos(\theta) = \sqrt{1 - \sin^2(\theta)} = \sqrt{1 - x^2}[/tex]

and [tex]dx = \cos(\theta) \, d\theta[/tex]. So the integral transforms to

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = \int \frac{\sin^3(\theta)}{\cos(\theta)} \cos(\theta) \, d\theta = \int \sin^3(\theta) \, d\theta[/tex]

Reduce the power by writing

[tex]\sin^3(\theta) = \sin(\theta) \sin^2(\theta) = \sin(\theta) (1 - \cos^2(\theta))[/tex]

Now let [tex]y = \cos(\theta)[/tex], so that [tex]dy = -\sin(\theta) \, d\theta[/tex]. Then

[tex]\displaystyle \int \sin(\theta) (1-\cos^2(\theta)) \, d\theta = - \int (1-y^2) \, dy = -y + \frac13 y^3 + C[/tex]

Replace the variable to get the antiderivative back in terms of x and we have

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\cos(\theta) + \frac13 \cos^3(\theta) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\sqrt{1-x^2} + \frac13 \left(\sqrt{1-x^2}\right)^3 + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = -\frac13 \sqrt{1-x^2} \left(3 - \left(\sqrt{1-x^2}\right)^2\right) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{1-x^2}} \, dx = \boxed{-\frac13 \sqrt{1-x^2} (2+x^2) + C}[/tex]

6. Let [tex]x = 3\tan(\theta)[/tex] and [tex]dx=3\sec^2(\theta)\,d\theta[/tex]. It follows that

[tex]\cos(\theta) = \dfrac1{\sec(\theta)} = \dfrac1{\sqrt{1+\tan^2(\theta)}} = \dfrac3{\sqrt{9+x^2}}[/tex]

since, like in the previous integral, under this reversible variable change we assume -π/2 < θ < π/2. Over this interval, sec(θ) is positive.

Now,

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = \int \frac{27\tan^3(\theta)}{\sqrt{9+9\tan^2(\theta)}} 3\sec^2(\theta) \, d\theta = 27 \int \frac{\tan^3(\theta) \sec^2(\theta)}{\sqrt{1+\tan^2(\theta)}} \, d\theta[/tex]

The denominator reduces to

[tex]\sqrt{1+\tan^2(\theta)} = \sqrt{\sec^2(\theta)} = |\sec(\theta)| = \sec(\theta)[/tex]

and so

[tex]\displaystyle 27 \int \tan^3(\theta) \sec(\theta) \, d\theta = 27 \int \frac{\sin^3(\theta)}{\cos^4(\theta)} \, d\theta[/tex]

Rewrite sin³(θ) just like before,

[tex]\displaystyle 27 \int \frac{\sin(\theta) (1-\cos^2(\theta))}{\cos^4(\theta)} \, d\theta[/tex]

and substitute [tex]y=\cos(\theta)[/tex] again to get

[tex]\displaystyle -27 \int \frac{1-y^2}{y^4} \, dy = 27 \int \left(\frac1{y^2} - \frac1{y^4}\right) \, dy = 27 \left(\frac1{3y^3} - \frac1y\right) + C[/tex]

Put everything back in terms of x :

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = 9 \left(\frac1{\cos^3(\theta)} - \frac3{\cos(\theta)}\right) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = 9 \left(\frac{\left(\sqrt{9+x^2}\right)^3}{27} - \sqrt{9+x^2}\right) + C[/tex]

[tex]\displaystyle \int \frac{x^3}{\sqrt{9+x^2}} \, dx = \boxed{\frac13 \sqrt{9+x^2} (x^2 - 18) + C}[/tex]

2(b). For some constants a, b, c, and d, we have

[tex]\dfrac1{x^2+x^4} = \dfrac1{x^2(1+x^2)} = \boxed{\dfrac ax + \dfrac b{x^2} + \dfrac{cx+d}{x^2+1}}[/tex]

3(a). For some constants a, b, and c,

[tex]\dfrac{x^2+4}{x^3-3x^2+2x} = \dfrac{x^2+4}{x(x-1)(x-2)} = \boxed{\dfrac ax + \dfrac b{x-1} + \dfrac c{x-2}}[/tex]

5(a). For some constants a-f,

[tex]\dfrac{x^5+1}{(x^2-x)(x^4+2x^2+1)} = \dfrac{x^5+1}{x(x-1)(x+1)(x^2+1)^2} \\\\ = \dfrac{x^4 - x^3 + x^2 - x + 1}{x(x-1)(x^2+1)^2} = \boxed{\dfrac ax + \dfrac b{x-1} + \dfrac{cx+d}{x^2+1} + \dfrac{ex+f}{(x^2+1)^2}}[/tex]

where we use the sum-of-5th-powers identity,

[tex]a^5 + b^5 = (a+b) (a^4-a^3b+a^2b^2-ab^3+b^4)[/tex]

Answer:

45

Step-by-step explanation:

Calculate the least common multiple LCM(9; 5)

LCM(9; 5) = 45

Find additional factors for each fraction, for this divide LCM by the denominators of each fraction:

45 : 9 = 5 (factor of 1 fraction)

45 : 5 = 9 (factor of 2 fraction)

We multiply the numerator and denominator of each fraction by an additional factor of this fraction:

6/9=6/9 ⋅ 5/5=30/45

1/5=1/9 ⋅ 9/9=9/45

Result

6/9=30/45

1/5=9/45

Hope this Helps!

Answer:

I can help!! answer in image

Step-by-step explanation:

Have a great day sir

Answer:

The answer is $1.85

Step-by-step explanation:

Now, we know that the cost of 5 chocolate bars are $5.75.

For 1 chocolate bar

5.75 ÷ 5 = $1.15

Here, we get the price of 1 chocolate bar

So, the cost of 2 chocolate bars and 3 packets of sweets are $7.85.

2 × chocolate bar = 2 × (1.15) = $2.3

Now, we want to find only the cost of one packet of sweets.

So,

7.85 – 2.3 = $5.55

3 packets of sweets cost $5.55

For 1 packets of sweets

5.55 ÷ 3 = $1.85

Thus, The cost of one packet of sweets = $1.85

Answer:

n=23

Step-by-step explanation:

a right angle measures 90

67+n=90

subtract 67 on both sides

n=23

Use angle addition postulate:

Substitute values to get the required equation and solve it for n:

The radius of the silo is the distance from its center to the outside wall

The radius of the silo is 7 3/8" or 7 3/8 inches

From the question, we have the following parameters:

The radius is then calculated as:

Radius = 0.5 * Diameter

This gives

Radius = 0.5 * 14 3/4"

Evaluate the product

Radius = 7 3/8"

Hence, the radius of the silo is 7 3/8" or 7 3/8 inches

Read more about radius at:

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Answer:

x=27 degrees

EAF=  27

Step-by-step explanation:

sorry if this isnt right i tried my best

Answer:

$20

Step-by-step explanation:

take 8 and multiply it by 2 and you get 16

then take half of 8 which is 4 and add it on

16+4=20

(h ◦ f)(x) is the composition of h(x) with f(x),

(h ◦ f)(x) = h(f(x))

which we can compute by simplying replacing in h(x) every instance of x with f(x) itself:

(h ◦ f)(x) = h(f(x))

(h ◦ f)(x) = h(5x - 1)

(h ◦ f)(x) = -(5x - 1) + 5

(h ◦ f)(x) = -5x + 1 + 5

(h ◦ f)(x) = -5x + 6

Then

(h ◦ f)(3) = -5 • 3 + 6

(h ◦ f)(3) = -15 + 6

(h ◦ f)(3) = -9

Answer:

The distance is 20 units

Step-by-step explanation:

Answer:

5/4

Step-by-step explanation:

csc theta is essentially 1/sintheta

so you can say that csc theta is 5/4.

another way to do this is to draw the right triangle and find the values of all the sides. this way you'll be able to find all the trig values of the triangle.

post a comment if you want any further guidance or help.