at the amusement park, janine bought a bottle of water for $2. she also bought game tickets for $0.50 each. janine spent a total of $15. which of the following equations can be used to find the number of $0.50 game tickets, g, janine bought?

1. 2g-0.50=15
2. 2g+0.50=15
3. 0.50g-2=15
4. 0.50g+2=15

Answers

Answer 1

Answer:

4. 0.50g+2=15

Step-by-step explanation:


Related Questions

using the definitions and diagram, determine which sets each number belongs to. circle the symbol if the number belongs to that set. the first one has been done for you as an example. g

Answers

The number 9 does not belong to the set g, so it does not get circled. The number 9 belongs to the set A, so it should be circled.

The number 9 does not belong to the set g, so it does not get circled. The number 9 belongs to the set A, so it should be circled.

g = {2, 4, 6, 8}

9

A: A

The number 9 does not belong to the set g, so it does not get circled. The number 9 belongs to the set A, so it should be circled.

The number 9 does not belong to the set g, which consists of the numbers 2, 4, 6, and 8. Instead, the number 9 belongs to the set A, so the symbol should be circled to indicate this. The set A includes all the numbers from 1 to 10, so the number 9 is included. This means that the circle should be placed around the symbol for set A to indicate that 9 belongs to this set.

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Two 3 x 4 rectangles overlap, as shown below. Find the area of the overlapping region (which is shaded).
Rectangles
The Area of a Rectangle
In geometry, a figure is defined as a rectangle if it is a quadrilateral and it has four right angles and two pairs of parallel sided. The area of such a figure is calculated as A=l w, where l represents the length and w represents the width.

Answers

719/64 unit²  is the area of the overlapping region (which is shaded)

Rectangles .

What is a rectangle, exactly?

A rectangle is a sort of quadrilateral with parallel sides that are equal to one another and four vertices that are all 90 degrees apart. Because of this, it is also known as an equiangular quadrilateral.

                         Because the opposite sides of a rectangle are equal and parallel, it can also be referred to as a parallelogram.

the Pythagorean theorem as follows to calculate the value of x .

  ( 4 - x )²  = 3² + x ²

16 - 8x  + x² =  9 + x²

       16 - 8x = 9

         16 - 9 = 8x

         7/8 = x

Thus, the area of the shaded region will be equal to the area of rectangle ABDC minus the area of the two triangles on the same rectangle. The area of rectangle ABDC is equal to

                  A = l * w

                     =  4 * 3

                  A = 12

The area of each of the two triangles is equal to

                 A = 1/2bh

                    = 1/2 ( 7/8) ( 7/8 )

                    = 49/128

The area of the two triangles is equal to

                   A = 2 * 49/128

                     A =  49/64

Therefore, the area of the shaded region is equal to

                         12 - 49/64  =  719/64 unit²

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12feet 4ft what’s the pitch

Answers

The area of the football pitch can be found to be 48 ft ²

How to find the area ?

The area of the scaled model of the football pitch can be found by using the formula for the area of a rectangle . This is because the scaled model of the pitch takes the form of a rectangle .

The area would therefore be :

= Length x Width

Length = 12 ft

Width = 4 ft

Area of the football pitch model is ;

= 12 x 4

= 48 ft ²

In conclusion, the area of the pitch is 48 ft ² .

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The full question is:

A scaled model of a football pitch measures 12 feet 4 ft. What's the pitch area?

Suppose that f(x) and g(x) are polynomials of degree 4 and 5 respectively. What is the degree of f(x^3) g(X^2)?

Answers

The degree of a polynomial is the highest exponent of its terms. Since f(x) and g(x) are both polynomials of degree 4 and 5 respectively, the degrees of f(x) and g(x) are 4 and 5 respectively.

The degree of f(x^3) g(X^2) is 14.

The degree of a polynomial is the highest exponent of its terms. Since f(x) and g(x) are both polynomials of degree 4 and 5 respectively, the degrees of f(x) and g(x) are 4 and 5 respectively. When we substitute x^3 for x in f(x) and x^2 for x in g(x), the highest exponent of the terms of f(x^3)g(x^2) is 3*4 + 2*5 = 14. Therefore, the degree of f(x^3) g(x^2) is 14.

The degree of f(x^3) g(x^2) is 14, which is calculated by multiplying the degree of f(x) and g(x) with the exponent of their respective terms. The degree of a polynomial is the highest exponent of its terms. Since f(x) and g(x) are both polynomials of degree 4 and 5 respectively, the degrees of f(x) and g(x) are 4 and 5 respectively.

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assuming that the curve is banked and the road is frictionless, determine the bank angle with respect to the horizontal.

Answers

The bank angle for a frictionless curved road can be calculated using the equations of motion.

The equation of motion for a particle in a curved road is given by F = mgsin(θ) where F is the centripetal force, m is the mass of the particle, g is the acceleration due to gravity and θ is the bank angle. Thus, the bank angle can be calculated by rearranging the equation to θ = arcsin(F/mg). For example, if the mass of the particle is 5kg, the centripetal force is 30N and the acceleration due to gravity is 9.8ms-2, then the bank angle would be θ = arcsin(30/5x9.8) =  20.7°. Thus, the bank angle with respect to the horizontal is 20.7°.

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Customer 1 and customer 2 each buy products X and Z.
Product Y is never sold to customers who buy product Z.
Conclusion:
Product Y is never sold to customers 1 and 2.
If the assumptions are true, is the conclusion
A) Correct
B) Cannot be determined based on the information available
C) Incorrect

Answers

If the assumptions are true, the conclusion is correct.

What assumptions are true?A statement that is included in an argument as an assumption is one whose truth value is (temporarily) accepted as True. The word "let" is frequently used in mathematics to indicate the introduction of an assumption. Let p, for instance (be true). An extreme circumstance is assumed to solve a problem using the Assumption Method (also known as the Supposition Method) in Singapore Math. Comparing this strategy to the Guess and Check method that primary school pupils learn in Primary 3, it is frequently thought of as a quicker substitute.

We are informed that

Each of customers 1 and 2 purchases products X and Z.

Customers who purchase product Z are never offered product Y.

The resulting conclusion is that Customers 1 and 2 are never sold Product Y.

According to the information provided, Customer 1 purchased Products X and Z.

Client 2 purchased Products X and Z.

Customers of product Z are unable to purchase product Y.

Therefore, it is obvious that neither customer can buy product Y when they both purchased Z.

Therefore, the conclusion is correct if the presumptions are true.

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so confused
DUE SOON PLEASE HELP IM SO CONFUSED ​

Answers

Answer:

1)  Mean = $75812.50

    Median = $74000

    Mode = $73100

2)  Mean = 24.5

     Median = 24.33333...

     Modal class = 29 - 33

Step-by-step explanation:

Definitions

The mode is the most frequently occurring data value.The median is the middle value when all data values are placed in order of size.The mean is the sum of all data values divided by the total number of data values.

Question 1

Given data:

71500, 74900, 69700, 82300, 78500, 73100, 73100, 83400

Mean

[tex]\begin{aligned}\textsf{Mean}&=\dfrac{71500+74900+69700+82300+78500+73100+73100+83400}{8}\\ &= \dfrac{606500}{8}\\&=75812.50\end{aligned}[/tex]

Median

Place the data values in order of size (smallest to largest):

69700, 71500, 73100, 73100, 74900, 78500, 82300, 83400

As there is an even number of data values, the median is the mean of the middle two values:

[tex]\implies \sf Median=\dfrac{73100+74900}{2}=74000[/tex]

Mode

The most frequently occurring data value is $73100.  Therefore:

[tex]\implies \textsf{Mode} = 73100[/tex]

Question 2

With grouped data, we can only estimate the mean and median.

Mean

To find an estimate of the mean, assume that every reading in a class takes the value of the class midpoint.

The number of days is the frequency (f).

Add a class midpoint (x) and an fx column to the table:

[tex]\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12} \sf Number\;of\;sales&\textsf{Number of days, $f$}&\textsf{Class midpoint, $x$}&fx\\\cline{1-4}\vphantom{\dfrac12}14-18&5&16&80\\\cline{1-4}\vphantom{\dfrac12}19-23&9&21&189\\\cline{1-4}\vphantom{\dfrac12}24-28&6&26&156\\\cline{1-4}\vphantom{\dfrac12}29-33&10&31&310\\\cline{1-4}\vphantom{\dfrac12}\sf Totals&\sum f=30&&\sum fx=735\\\cline{1-4}\end{array}[/tex]

[tex]\textsf{Mean}=\dfrac{\sum fx}{\sum f}=\dfrac{735}{30}=24.5[/tex]

Median

To find an estimate for the median, use linear interpolation.

Add a cumulative frequency column to the table:

[tex]\begin{array}{|c|c|c|}\cline{1-3}\vphantom{\dfrac12} \sf Number\;of\;sales&\textsf{Number of days}&\textsf{Culmulative frequency}\\\cline{1-3}\vphantom{\dfrac12}14-18&5&5\\\cline{1-3}\vphantom{\dfrac12}19-23&9&14\\\cline{1-3}\vphantom{\dfrac12}24-28&6&20\\\cline{1-3}\vphantom{\dfrac12}29-33&10&30\\\cline{1-3}\end{array}[/tex]

Find which class the median is in.

Since n/2 = 30/2 = 15, there are 15 values less than or equal to the median. This means the median must be in the 24-28 class.

Therefore:

[tex]a_1=m-23.5[/tex][tex]b_1=28.5-23.5=5[/tex][tex]a_2=15-14=1[/tex][tex]b_2=20-14=6[/tex]

To find the median, m:

[tex]\begin{aligned}\dfrac{a_1}{b_1}=\dfrac{a_2}{b_2} \implies \dfrac{m-23.5}{5}&=\dfrac{1}{6}\\\\ 6(m-23.5)&=5\\\\6m-141&=5\\\\6m&=146\\\\m&=24.3333...\end{aligned}[/tex]

Therefore, the median is 24.3333...

Mode

The modal class is the class with the highest frequency density.

As all the classes are the same width, this is the class with the highest frequency.

Modal class = 29 - 33

a researcher wants to conduct a study to determine whether a newly developed anti-tardy program is successful. two random groups of 100 students each, identified as control and treatment groups, are formed from 200 students who are repeatedly late to school. both groups receive a set of anti-tardy reading materials and a lecture from a teacher and a tardy-reformed student about the negative impacts of being late. in addition, the treatment group also receives materials from the newly developed program. thirty-three of the 100 students in the control and 35 of the 100 students in the treatment group are no longer late to school is recorded 6 months later. use the results to test the hypotheses h0: p1 = p2 and Ha: p1 ? p2 where p1 represents the proportion of students who succeed in the control program and p2 represents the proportion of students who succeed in the newly developed program.

Answers

To test the hypotheses h0: p1 = p2 and Ha: p1 ≠ p2, we can use a two-sample proportion test. This test compares the proportion of success (no longer being late to school) in the control group (p1) to the proportion of success in the treatment group (p2) to determine if there is a statistically significant difference between the two proportions.

Here are the steps to perform the test:

State the hypotheses:

h0: p1 = p2 (the proportion of success in the control group is equal to the proportion of success in the treatment group)

Ha: p1 ≠ p2 (the proportion of success in the control group is not equal to the proportion of success in the treatment group)

Select a significance level (alpha): usually, it is set as 0.05

Calculate the test statistic:

p = (p1n1 + p2n2) / (n1 + n2)

z = (p1 - p2) / sqrt(p*(1-p)*((1/n1)+(1/n2)))

Find the p-value:

Using the z-score, look up the probability in a standard normal table.

Make a decision:

Compare the p-value to the significance level. If the p-value is less than or equal to the significance level, then reject the null hypothesis. If the p-value is greater than the significance level, then fail to reject the null hypothesis.

Conclusion:

Interpret the results in terms of the research question. If the null hypothesis is rejected, then the results suggest that there is a statistically significant difference in the proportion of success between the control group and the treatment group

The question is incomplete, the complete question is:

__"'A researcher wants to conduct a study to determine whether a newly developed anti-tardy program is successful. Two random groups of 100 students each, identified as control and treatment groups, are formed from 200 students who are repeatedly late to school. Both groups receive a set of anti-tardy reading materials and a lecture from a teacher and a tardy-reformed student about the negative impacts of being late. In addition, the treatment group also receives materials from the newly developed program. Thirty-three of the 100 students in the control and 35 of the 100 students in the treatment group are no longer late to school is recorded 6 months later.

Use the results to test the hypotheses H0: p1 = p2 and Ha: p1 ≠ p2 where p1 represents the proportion of students who succeed in the control program and p2 represents the proportion of students who succeed in the newly developed program.

What can you conclude using the significance level α = 0.05?""__

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students want to verify that the centripetal acceleration of an object undergoing uniform circular motion with tangential speed vv and radius rr can be described by the equation ac

Answers

Yes, this is correct. The centripetal acceleration of an object undergoing uniform circular motion with tangential speed v and radius r can be described by the equation a_c = v^2/r.

The centripetal acceleration of an object undergoing uniform circular motion with tangential speed v and radius r can be calculated using the equation a_c = v^2/r.

The centripetal acceleration of an object undergoing uniform circular motion with tangential speed v and radius r can be described by the equation a_c = v^2/r. This equation shows that the acceleration of an object in uniform circular motion is proportional to the square of the velocity and inversely proportional to the radius of the circle. This equation is a result of Newton's second law, which states that the sum of the forces acting on an object is equal to the mass of the object multiplied by its acceleration. The centripetal acceleration is the acceleration of an object towards the center of the circle and is perpendicular to the direction of motion. In order to calculate the centripetal acceleration of an object, the velocity and radius of the circle must be known. The equation a_c = v^2/r can then be used to calculate the centripetal acceleration of the object.

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Find an expression which represents the difference when (2x + 4) is subtracted
from (4x + 2) in simplest terms.

Answers

Answer:

(-2x+2) is the difference

Step-by-step explanation:

Shown above

The average temperature during the winter in three states is given.
• Maine: 8.4°C below zero
• Minnesota: 10.9°C below zero •Georgia: 8.8°C

Part A Order these temperatures from least to greatest. Select your answers from the drop-down lists. Least to Greatest:

Part B Explain how you determined the order of the temperatures.​

Answers

Answer:

10.9 8.4 8.8

Step-by-step explanation:

Both 10.9C and 8.4C are below zero. We can identify both are in negative temperatures. 8.8C was not labeled as below zero, which indicates a positive unit.

Find the volume of a cone that has a radius of 8 inches and a slant height of 10 inches. Round your answer to the nearest tenth of a cubic inch.

Answers

Answer:

401.9 in³

------------------------------------

Volume of the cone:

V = πr²h/3

We have a slant height and radius. They represent a hypotenuse and one of the legs of the right triangle.

Use Pythagorean to find the other leg, the height h of the cone:

[tex]h = \sqrt{10^2-8^2}=\sqrt{100-64} =\sqrt{36}=6\ in[/tex]

Find the volume:

V = 3.14*8²*6/3 = 401.92 ≈ 401.9 in³

The volume of the cone is calculated as: 671.0 cubic inches.

How to Find the Volume of a Cone?

The volume of a cone can be found using the formula:

V = (1/3) * pi * r^2 * h

Where V is the volume, pi is approximately 3.14, r is the radius of the base, and h is the height (or slant height) of the cone.

In this case, the radius of the base is 8 inches and the slant height is 10 inches. So, the volume of the cone can be found by:

V = (1/3) * pi * 8^2 * 10

V = (1/3) * 3.14 * 64 * 10

V = (1/3) * 201.12 * 10

V = 671.04 cubic inches

Rounding the answer to the nearest tenth of a cubic inch, the volume of the cone is approximately 671.0 cubic inches.

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Determine whether the following system of linear equations have no solution, infinitely many solution or unique solutions.x+2y=3,2x+4y=15A.No solutionB.Infinitely many solutionC.Unique solutionD.Cannot be determined

Answers

C. Unique solution. The system of linear equations have a unique solution because the equations are consistent and have the same number of variables and equations.

 

The given system of linear equations is x+2y=3 and 2x+4y=15. To determine whether the system of linear equations have no solution, infinitely many solution or unique solutions, we need to solve the system of equations. Firstly, we expand and simplify both equations to get x+2y=3 and 2x+4y=15. Then, we compare the coefficients of the equations to determine if the system of equations is consistent, inconsistent or dependent. Since the equations are consistent and have the same number of variables and equations, we can solve the system of equations. By isolating the variables and using the substitution method, we can solve the system of equations to get x=3 and y=3. This means that the system of linear equations have a unique solution.

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HELP ASAP!!!! NO LINKS OR SPAM


Willa earns a bi-weekly gross income of $2,417.00 and has total monthly debt payments of $1,623.00. Determine Willa's current debt-to-income ratio. Round the final answer to the nearest whole percent. (2 points)

28%

31%

34%

35%

Answers

Willa's debt to income ratio is 34%.

What is Debt to Income Ratio?

Debt to income ratio is usually calculated as a percentage of the gross monthly debt payments divided by the gross monthly income.

Given that,

Willa earns a bi-weekly gross income of $2,417.00

Monthly gross income = 2 × $2,417.00 = $4834

Monthly debt payments = $1,623.00

Debt to income ratio = $1,623.00 / $4834.00

                                   = 0.3357

                                   = 33.57%

                                   = 34%

Hence the debt to income ratio of Willa is 34%.

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The radioactive substance cesium-137 has a half-life of 30 years. The amount A(t) (in grams) of a sample of cesium-137 remaining after t years is given by the following exponential function.

A(t)=458(1/2 (is written as a fraction) t/3) also written as a fraction

Find the initial amount in the sample and the amount remaining after 50 years.
Round your answers to the nearest gram as necessary.

Answers

Answer:

1818886278282871728282882

Kazuko says the expressions 5x and 6 - x are equivalent expressions, because you
can substitute 1 for x in both expressions and get the same result. Is Kazuko's
reasoning correct? Explain.

Answers

Yes Kazuko's reasoning is  correct the expressions 5x and 6 - x are equivalent expressions

How do you determine whether two phrases are equal?

When two expressions can be reduced to a single third expression or when one of the expressions can be expressed in the same way as the other, they are said to be equivalent. When values are replaced for the variable and both expressions yield the same result, you may also tell if two expressions are equal.

X-terms and constants should be combined with any other like terms on either side of the equation. Put the terms in the same sequence, with the x-term generally coming before the constants. The two phrases are equal if and only if each of their terms is the same.

5x and 6 - x

5x +  6 - x

2 (2 x + 3)

4 x + 6

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which point represents the center of the circle shown below?
O A Point M
• B. Point K
• C. Point R
• D. Point T

Answers

Point K is the point that marks the centre of the circle depicted below. This is due to the fact that the centre of a circle is the place from which all of its points are equally far. As a result, Point K is the circle's midpoint and consequently its centre.

What is a Circle?

To put it simply, a circle is a spherical shape without any edges or line segments. In geometry, it has the shape of a closed curve. The circle's points are set apart from the center by a specified amount.

A circle is a closed, two-dimensional object in which all points in the plane are equally spaced apart from the center. The symmetry line of reflection is formed by each line that traverses the circle. Additionally, it is rotationally symmetric about the center for all angles.

A circle is a figure with a round shape, all of its points lying on the same plane and all of its points being equally spaced from the circle's center.

The center of the circle can be found by finding the midpoint of the diameter, which passes through points K and T.

The midpoint of the diameter can be found by taking the average of the x and y coordinates of points K and T.

Midpoint of AB = (x1+x2/2 , y1+y2/2)

Midpoint of K and T = ((-2 + 4)/2 , (1 + 7)/2)

Midpoint of K and T = (1 , 4)

Therefore, the center of the circle is point K.

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Assignment Scoring
Your best submission for each question part is used for your score.
4.
DETAILS AUFEXC4 10.4.025. 28/100 Submissions Used
Find the minimum or maximum value of the quadratic function.
f(x) = x² - 6x + 9
(-2,11)
x Your answer cannot be understood or graded. More Information
State whether the value is a minimum or a maximum.
minimum
O maximum
Submit Answer

Answers

The quadratic function f(x) = x² - 6x + 9 has a minimum at point (3,0).

What is a quadratic function?

A polynomial function with one or more variables, where the largest exponent of the variable is two, is referred to as a quadratic function. It is also known as the polynomial of degree 2 since the greatest degree term in a quadratic function is of second degree.

The given quadratic function is - f(x) = x² - 6x + 9.

Find the differentiation of f(x) -

dy/dx = d/dx (x² - 6x + 9)

d/dx (x²) - d/dx (6x) + d/dx (9)

2x - 6 + 0

2x - 6 = 0

For stationary values, dy/dx = 0

2x - 6 = 0

2x = 6

x = 6/2

x = 3

At x = 3 we get stationary values.

Now, d²y/dx² = 2x - 6

d/dx (2x - 6)

d/dx (2x) - d/dx (6)

2 - 0 = 0

2 = 0

(d²y/dx²) x=3 = 2 (positive)

Therefore, at x = 3 the function is minimum.

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2x+y=30
x+3y=36
by elmination methods

Answers

The solution to the system of equations 2x + y = 30 and 2x + 6y = 72 is (10.8, 8.4)

What is an equation?

An equation is an expression showing the relationship between numbers and variables.

Given the equations:

2x + y = 30     (1)

x + 3y = 36; multiplying by 2 gives:

2x + 6y = 72     (2)

To solve by elimination method, subtract equation 2 from 1, hence:

-5y = -42

Dividing by -5:

y = 8.4

Put y = 8.4 in equation 2:

2x + 6(8.4) = 72

2x = 21.6

x = 10.8

The solution is (10.8, 8.4)

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Repeated addition:

1 3 + 1 3 + 1 3= a b

a =

b =

Answers

Answer:

[tex]\frac{1}{3} + \frac{1}{3} + \frac{1}{3} = \frac{3}{3} = 1[/tex]

a=3

b=3

Third part

Commutative property

Fourth part

Inverse property

Fifth part

Identity property

Step-by-step explanation:

Answer:

1st part is a= 3

b= 9

Second part

x=16

y= -24

Third part

Commutative property

Fourth part

Inverse property

Fifth part

Identity property

Step-by-step explanation:

perpendicular to line y=1/2x-8 passes through (7,-6) point slope form

Answers

The equation of line is y = -2x + 8 and the slope is m = -2

What is an Equation of a line?

The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

And y - y₁ = m ( x - x₁ )

y = y-coordinate of second point

y₁ = y-coordinate of point one

m = slope

x = x-coordinate of second point

x₁ = x-coordinate of point one

The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given data ,

Let the equation of line be represented as A

Now , the value of A is

The equation of line perpendicular to the line is y = ( 1/2 )x - 8

Now , the slope of the line m₁ = 1/2

For perpendicular lines , the product of the slopes is -1

So , m₁ x m₂ = -1

So , the value of Slope m₂ = -2

And , the line passes through the point P ( 7 , -6 )

Now , the equation of line is y - y₁ = m ( x - x₁ )

Substituting the values in the equation , we get

y - ( -6 ) = ( -2 ) ( x - 7 )

On simplifying the equation , we get

y + 6 = -2x + 14

Subtracting 6 on both sides of the equation , we get

y = -2x + 8

Hence , the equation of line is y = -2x + 8

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Find the correct representation for the slope of the tangent line to the curve cosxy + 3sin2x + 2y.
a. sin xy (dx/dy +y) + 6 cos x+2
b. -sin xy (dx/dy +y) + 6 sin x cos x+ (2dy/dx)
c. -sin (xy) (x dy/dx) + 6 sin x + 2
d. sin (xy dy/dx +y) + 6cos x+ 2 dy/dx

Answers

The slope of the tangent line to the curve cos(xy) + 3sin^2(x) + 2y at a point (x,y) is -sin(xy) ( x * dy/dx + y) + 6*sin(x)*cos(x) + 2dy/dx.

So the option b is the correct representation for the slope of the tangent line to the curve.

The correct representation for the slope of the tangent line to the curve cos(xy) + 3sin^2(x) + 2y is c. -sin (xy) (x dy/dx) + 6 sin x + 2.

The slope of a tangent line to a curve at a point (x,y) is given by the derivative of the function with respect to x, evaluated at that point.

So to find the slope of the tangent line to the curve cos(xy) + 3sin^2(x) + 2y, we need to find the derivative of the function with respect to x.

The derivative of cos(xy) with respect to x is

-sin(xy) ( x * dy/dx + y)

The derivative of sin^2(x) with respect to x is

2*sin(x)*cos(x)

The derivative of y with respect to x is

dy/dx

So the derivative of the function with respect to x is:

-sin(xy) ( x * dy/dx + y) + 6*sin(x)*cos(x) + 2dy/dx

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A man cover 255 km in 6 hours on scooter at a uniform speed find his speed in kilometres per hour​

Answers

Answer:

The man's speed is 42.5 km/h.

You can find this by dividing the distance he traveled (255 km) by the time it took him to travel that distance (6 hours).

255 km / 6 hours = 42.5 km/h.

The formula to find speed is:

Speed = Distance / Time

In this case, the distance is 255 km and the time is 6 hours. So using the formula, we can calculate the speed as:

Speed = 255 km / 6 hours = 42.5 km/h

So the man's speed is 42.5 km/h.

1 point 8 divided by 0 point 6​

Answers

Answer:

3 is the answer

Step-by-step explanation:

1.8/0.6

example: see the image and follow how to do it

The correct answer is 3.

what is the slope through the line of (-8, -11) and (-1, -5)

Answers

The slope of the line through the points (-8, -11) and (-1, -5) is (y2 - y1)/(x2 - x1) = (-5 - (-11))/(-1 - (-8)) = -6/7 = -0.8571428571428571.

How many ways can you make change for 70 cents using only nickel dime and quarters

Answers

The number of ways to make a change of 70 cents using only nickel, dime and quarters is given as follows:

15 ways.

How to obtain the number of ways to make the change?

The value of each coin is given as follows:

Nickel: $5 cents.Dime: 10 cents.Quarters: 25 cents.

Hence the ways to make the change are given as follows:

2 quarters and 2 dimes.2 quarters and 4 nickels.2 quarters, 1 dime and 2 nickels.1 quarter, 1 nickel and 4 dimes.1 quarter, 3 nickels and 3 dimes.1 quarter, 5 nickels and 2 dimes.1 quarter, 7 nickels and 1 dime.7 dimes.6 dimes and 2 nickels.5 dimes and 4 nickels.4 dimes and 6 nickels.3 dimes and 8 nickels.2 dimes and 10 nickels.1 dime and 12 nickels.14 nickels.

Which combine to 15 ways.

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1.
If
z
y
=
x
, which of the following statements is true?

z - x = y

z - y = x

x · y = z

Answers

Answer:b

Step-by-step explanation:

The area of 755.9ft and 610ft

Answers

Answer: 460,874ft^2

Step-by-step explanation:

The area of a rectangle is calculated by multiplying the length by the width. In this case, the length is 755.9ft and the width is 610ft. Therefore, the area of the rectangle is: 755.9ft * 610ft = 460,874ft^2.

I hope this helps :)

Find the number of ways 66 identical coins can be separated into three nonempty piles so that there are fewer coins in the first pile than in the second pile and fewer coins in the second pile than in the third pile.

Answers

There are 331 ways when 66 identical coins can be separated into three nonempty piles

Let the piles have a, b and c coins, with 0<a <b <c. Then, let b=a+k₁, and

c=b+k₂, such that each ki≥1.

The sum is then a+a+k₁+a+k₁+k₂= 66 ⇒ 3a+2k₁+k₂ = 66.

This is simply the number of positive solutions to the equation

3x+2y+z = 66.

If a = 1, then 2k₁ + k₂ = 63⇒ 1≤k₁ ≤31. Each value of k₁ corresponds to a unique value of k₂, so there are 31 solutions in this case.

Similarly, if a = 2, then 2k₁+k₂= 60⇒ 1≤k₁ ≤29, for a total of 29 solutions in this case.

If a = 3, then 2k₁+ k₁= 57 ⇒ 1 ≤ k₁ ≤28, for a total of 28 solutions.

In general, the number of solutions is just all the numbers that aren't a multiple of 3, that are less than or equal to 31.

We then add our cases to get

=1+2+4+....31=1+2+3+...31-3(1+2+3+...10)

=31*(32)/2-3(55)

=31*16-165

=496-165

=331

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Which of these classes do the matrices A and B belong to (more than one answer is possible for each matrix: invertible; orthogonal; projection; permutation; diagonalizable; Markov.A = [0 0 1]0 1 01 0 0B = 1/3[1 1 1]1 1 11 1 1

Answers

Matrix A belongs to the permutation and Markov classes. A permutation matrix is a square matrix with exactly one 1 in each row and each column, and 0s everywhere else.

This is the case for matrix A, as it has one 1 in each row and column and 0s everywhere else. Matrix A is also a Markov matrix, which means that all the entries are non-negative and the sum of each row is equal to 1. This can be seen by summing each row, which yields 1+0+0 = 1, 0+1+0 = 1, and 1+0+0 = 1.

Matrix B belongs to the orthogonal, projection, and diagonalizable classes. Matrix B is orthogonal, which means that it is a square matrix whose columns and rows are orthonormal unit vectors (i.e. the dot product of any two columns or rows is 0). This is the case for matrix B, as the dot product of any two columns or rows yields 0. Matrix B is also a projection matrix, which means that it is a square matrix whose columns are all of unit length (i.e. the dot product of any two columns or rows is 1). This can be seen by taking the dot product of any two columns or rows, which yields 1. Finally, matrix B is diagonalizable, which means that it can be transformed into a diagonal matrix using a similarity transformation. This can be seen by calculating the eigenvalues and eigenvectors of matrix B, which yields the same diagonal matrix.

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