The expression 12 *3/4 is 9.
Exactly how do you solve a fraction expression?By multiplying both sides of the equation by the least common denominator (LCD) of each term, a fractional equation can be solved by first eliminating the fractions. This is possible because an equation cannot become unbalanced when both sides are multiplied by the same number, in this case, the LCD.Using mathematical operations like subtraction, addition, multiplication, and division, terms are joined to form an expression. Mathematical expressions contain the following terms: Constant: An absolute number is a constant.Explanation:
12 * 3/4 = 91 = 9.
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The expression 12 *3/4 is 9.
Exactly how do you solve a fraction expression?By multiplying both sides of the equation by the least common denominator (LCD) of each term, a fractional equation can be solved by first eliminating the fractions. This is possible because an equation cannot become unbalanced when both sides are multiplied by the same number, in this case, the LCD.
Using mathematical operations like subtraction, addition, multiplication, and division, terms are joined to form an expression. Mathematical expressions contain the following terms: Constant: An absolute number is a constant.
12 * 3/4 = 91 = 9.
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Square ABCD is shown in the xy-coordinate plane. The square will bedilated with the center O by a scale factor of 2 to create square A'B'C'D'.Which statements are true?Select all that apply.BC ||B'C'AC=A'C'AD_CDPoint D' has the same coordinates as point C.Point C' lies on the line containing points 0 and C.
The following statements are true:
BC║B'C'
AC ⊥ line C'D'
D' and C have the same coordinates
C' lies on line OC
What is dilation?
In mathematics, dilation refers to the process of scaling a geometric figure by a certain factor. This factor is called the scale factor or dilation factor, and it can be either greater than or less than 1. A dilation that enlarges an object is called a magnifying dilation and a dilation that reduces an object is called a shrinking dilation.
Dilation does not change angles or directions. Every image point X' lies on the line containing the center of dilation and the pre-image point X. If the scale factor is other than 1, no image segment will be congruent to its pre-image segment.
Hence, the following statements are true:
BC║B'C'
AC ⊥ line C'D'
D' and C have the same coordinates
C' lies on line OC
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please help!! i don’t understand this question
The Polynomial 4 will be 3x^2 - 2. The solution is obtained using arithmetic operations.
What are arithmetic operations?
There are four basic operations which are listed as follows:
Addition(‘+’): This operation deals with finding the sum.Subtraction(‘-’): This operation deals with finding the difference. Multiplication(‘×’): This operation deals with finding the product.Division(‘÷’): This operation deals with finding the quotient.⇒Polynomial 1 = x^2 - x^2 + x + x + x + x - 1 + 1 - 1
⇒Polynomial 1 = 4x - 1
⇒Polynomial 2 = x + x + x - x - x^2 - x^2 - 1 + 1 - 1
⇒Polynomial 2 = 2x - 2x^2 - 1
⇒Polynomial 2 = -2x^2 + 2x - 1
⇒Polynomial 3 = 1 + 1 + 1 + 1 - x - x + x - x^2 + x^2 - x^2
⇒Polynomial 3 = 4 - x - x^2
⇒Polynomial 3 = -x^2 - x + 4
We are given sum of all four expressions = 5x
So,
4x - 1 + (-2x^2 + 2x - 1) + (-x^2 - x + 4) + Polynomial 4 = 5x
On simplifying the equation,
⇒4x - 1 - 2x^2 + 2x - 1 - x^2 - x + 4 + Polynomial 4 = 5x
⇒5x - 3x^2 + 2 + Polynomial 4 = 5x
⇒Polynomial 4 = 5x - (5x - 3x^2 + 2)
⇒Polynomial 4 = 5x - 5x + 3x^2 - 2
⇒Polynomial 4 = 3x^2 - 2
Hence, polynomial 4 is 3x^2 - 2 which will be 3 big black squares and 2 small white squares.
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which of these features lets you control how long user-level and event-level data is stored by analytics?
Data Retention Settings. This feature allows you to specify how long user-level and event-level data is stored by analytics before being automatically deleted. You can set up data retention periods for different types of data, such as individual user data, event data, and session data.
Data Retention Settings is a feature available in many analytics platforms that allows you to control how long user-level and event-level data is stored. This helps ensure that the data stored is only relevant to your project. You can set up different data retention periods for different types of data, such as individual user data, event data, and session data. This allows you to specify how long the data should be stored before being automatically deleted. Data retention settings are important as they help protect user privacy and ensure that only the data necessary for your project is stored. They also help you manage your storage costs by allowing you to set a maximum amount of data that can be stored for a certain period of time. Data Retention Settings is a valuable tool for managing the data collected by your analytics platform.
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The complete question is
which of these features lets you control how long user-level and event-level data is stored by analytics Data Retention Policies.
Find the value of f(7)
The numeric value of f(x) = x - 3 at x = 7 is given as follows:
f(7) = 4.
How to find the numeric value of a function or of an expression?To find the numeric value of a function or of an expression, we replace each instance of the variable in the function or in the expression by the value at which we want to find the numeric value.
The function for this problem is defined as follows:
f(x) = x - 3.
To obtain the numeric value of the function at x = 7, we replace the lone instance of x by 7, hence:
f(7) = 7 - 3 = 4.
Missing InformationThe function for this problem is defined as follows:
f(x) = x - 3.
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A shipping box is in the shape of a cube. what is the volume of the shipping box in terms of m and n? Write the variables in alphabetical order.
The volume of the cube with side of (4m⁸n⁴) unit is (64m²⁴n¹²) unit³
What is an equation?An equation is an expression showing two or more numbers and variables linked together by a mathematical operation. Types of equations are linear, quadratic, cubic and so on depending on the degree of the variable.
Volume is the amount of space that a three dimensional object occupies. For a cube, all the sides are equal, that is length = width = height
The volume of the cube is:
Volume = length³
Given that length = 4m⁸n⁴
Hence:
Volume = length³ = (4m⁸n⁴)³ = 64m²⁴n¹²
The volume of the cube is (64m²⁴n¹²) unit³
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answer now its timed
Answer:
24
Step-by-step explanation:
Because of similar triangles,
UV/UG = UW/UH
132/24 = 132/UH
UH = 24
Answer:
24
Step-by-step explanation:
GU.U.V=HU. UW
24×132=HU×132
3168=132HU
HU=24
The data were collected from a statistics class. The column heads give the variable, and each of the row
Eye Shoe Height
Color Size (inches)
Brown 10
65
Blue 8.5
67
Blue 8.5
69
Blue
7
73
Male Age
31
30
30
20
0
1
1
1
There are
variables.
(Type a whole number.)
Weight
(pounds)
150
150
200
145
Number College Units
of Siblings This Term
3
232
2
2
5
15
13
15
Handedness
Left
Left
Right
Right
The statistics class was where the data were gathered. The variable is indicated by the column headers, along with each row's Eye Shoe Height 9.
Is the variable handedness numerical or categorical?5 different variables are present. Category-specific characteristics include gender, handedness, and field side. Quantitative factors include height and the distance covered when walking. Numbers are used to express variables like the number of siblings and student height. It is discrete since it is a count of siblings. As a continuous numerical variable, height varies throughout time.
There are three primary types of variables: controllable, dependent, and independent. His realization that shoe size is an interval variable came later. Eureka! There is no zero point in an interval variable, but there is a defined range between values. If we take shoe sizes into consideration,
we can conclude that the difference between
a size 2 and a size 3 = size 8 - a size 7
Two major categories—categorical and numeric—can be used to group variables.
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Full question:
Given Y1 and Y2 are random variables with E(Y1) = 10, E(Y2) = 2, 9 and 4. 2 2
1 2
Y Y
a. Calculate E(4Y1 – 2Y2 + 6)
b. Calculate V(4Y1 – 2Y2 + 6)
The values of the variance and expected value expressions are
E(4Y1 – 2Y2 + 6) = 42V(4Y1 – 2Y2 + 6) = undefinedHow to determine the expected values and the varianceFrom the question, we have the following parameters that can be used in our computation:
E(Y1) = 10
E(Y2) = 2
The above parameters are calculated as follows:
a. Expected value
E(4Y1 – 2Y2 + 6) = 4E(Y1) – 2E(Y2) + 6
= 4(10) – 2(2) + 6
= 40 - 4 + 6
= 42
So E(4Y1 – 2Y2 + 6) = 42
b. Variance
V(4Y1 – 2Y2 + 6) = 4^2 * V(Y1) + (-2)^2 * V(Y2)
= 16 * V(Y1) + 4 * V(Y2)
The variances of Y1 and Y2 are not given
This means that the value of the expression cannot be calculated
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On a test, for every correct answer the student gets 2 points and for every
incorrect answer the student loses 1 point
Corinne got the first two questions correct and missed the next three.
She will receive a grade of zero if she answers
O
question(s)
correctly
incorrectly
# 1
correctly
incorrectly
Answer: she will receive a grade of zero if she gets one more question incorrect.
Step-by-step explanation: She gets 2 questions correct which equals 4 points and 3 questions wrong which is minus 3 points
4-3=1 so if she were to get one more incorrect she would receive a zero
the height and age of each child in a random sample of children was recorded. the value of the correlation coefficient between height and age for the children in the sample was 0.8. based on the least-squares regression line created from the data to predict the height of a child based on age, which of the following is a correct statement?
The percentage of the variation in height that is explained by a regression on age is 0.64, which is the right answer.
from the aforementioned case, The relationship between children's age and height is strongly correlated, as evidenced by the correlation coefficient R of 0.8. Given the correlation coefficient value, we can calculate the coefficient of determination (R2), which indicates the proportion of variation that the regression model can account for.
Therefore, R2 = 0.82 = 0.64, which is the coefficient of determination. Therefore, the proportion of the variation in children's height that can be attributed to age is 0.64 and the remaining 0.36 can be attributed to other factors.
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The number N of locations of a popular coffeehouse chain is given in the table. (The numbers of locations as of October 1 are given.)(a) Find the average rate of growth between each pair of years.(b) Estimate the instantaneous rate of growth in 2006 by taking the average of the last two rates of change in part (a). locations/year(c) Estimate the instantaneous rate of growth in 2006 by measuring the slope of the tangent line through(2005, 10236) and (2007, 15005).locations/year(d) Estimate the instantaneous rate of growth in 2007 by measuring the slope of the tangent line through(2006, 12441) and (2008, 16683). locations/yearCompare the growth rates you obtained in part (c) and (d). What can you conclude?The rate of growth is constant.There is not enough information. The rate of growth is increasing.The rate of growth is decreasing.
The average rate of growth between each pair of years was calculated in part (a). The instantaneous rate of growth for 2006 was estimated in part (b) and (c), and the instantaneous rate of growth for 2007 was estimated in part (d). Comparing the growth rates from parts (c) and (d), it can be concluded that the rate of growth is constant.
In part (a), the average rate of growth between each pair of years was calculated by dividing the difference between the number of locations in two consecutive years by the number of years between them. For example, to find the average rate of growth between 2005 and 2006, the difference in the number of locations (12441-10236) was divided by the number of years (1). The result was 22.05 locations/year. In part (b), the instantaneous rate of growth in 2006 was estimated by taking the average of the last two rates of change from part (a). This was done by adding the rates of growth from 2005 to 2006 (22.05 locations/year) and 2006 to 2007 (27.64 locations/year) and then dividing by two. The result was 24.85 locations/year. In part (c), the instantaneous rate of growth in 2006 was estimated by measuring the slope of the tangent line through (2005, 10236) and (2007, 15005). This was done by finding the difference in the number of locations (15005-10236) and dividing by the number of years (2). The result was 22.85 locations/year. In part (d), the instantaneous rate of growth in 2007 was estimated by measuring the slope of the tangent line through (2006, 12441) and (2008, 16683). This was done by finding the difference in the number of locations (16683-12441) and dividing by the number of years (2). The result was 22.21 locations/year. Comparing the growth rates from parts (c) and (d), it can be concluded that the rate of growth is constant.
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Use the number line to find the missing value. (-6)+_=-3
Answer:
3
Step-by-step explanation:
Let x represent the missing value.
(-3) = x + (-6)
Add 6 to both sides.6 + (-3) = x + 6 + (-6)
+6 will eliminate -6 on the left side of the equation.3 = x
There are 24 four-digit whole numbers that use each of the four digits 2, 4, 5 and 7 exactly once. Only one of these four-digit numbers is a multiple of another one. Which of the following is it?
O 5724 O 7245 O 7254 O 7425
O 7542
The average four-digit number 7254 is the only one that is a multiple of another one, as it is composed of the digits 2, 4, 5 and 7 used exactly once.
To find the four-digit number that is a multiple of another one using the digits 2, 4, 5 and 7, we can list all the possible combinations of these digits:
2457, 2475, 2547, 2574, 2745, 2754, 4257, 4275, 4527, 4572, 4725, 4752, 5247, 5274, 5427, 5472, 5724, 5742, 7245, 7254, 7425, 7452, 7524, 7542. as it is composed of the digits 2, 4, 5 and 7 used exactly once.
Next, we can check to see which of these numbers is a multiple of another one. 7254 is the only one that is a multiple of another one, as it can be divided by 2, 4, 5 and 7. Therefore, the answer is 7254.
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Kaylee works in an office building across town. To get to the office in the morning, Kaylee walks to the bus stop a few blocks away. Then she takes the bus, staying on through several stops before getting off and walking the rest of the way. Which graph could show Kaylee's distance from the office over time?
The graph that represents the situation is added as an attachment
How to determine the graph of the situationFrom the question, we have the following parameters that can be used in our computation:
Bus stop = Few stepsBus = several stopsWalks the restThis means that the graph would be represented using a distance/time graph
Such that the distance would be on the y-axis and the time would be on the x-axis
See attachment for the graph
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a waitress wondered if there was an association between the type of food and the type of drink customers ordered. the results are displayed below. based on the graph, is there an association between food ordered and drink ordered? there is an association because the distribution of drinks ordered differs among the food groups. there is an association because the distribution of drinks ordered is the same among the food groups. there is no association because the distribution of drinks ordered differs among the food groups. there is no association because the distribution of drinks ordered is the same among the food groups.
Yes, there is an association between food ordered and drink ordered because the distributive property of drinks ordered differs among the food groups.
Yes, there is an association between food ordered and drink ordered, as evidenced by the graph. The graph shows the distribution of drinks ordered among the various food groups, and it can be seen that the distribution differs among the food groups. For example, beer is the most popular drink ordered when burgers are the food ordered, while soda is the most popular drink when salads are the food ordered. This indicates that customers are more likely to order certain drinks depending on the type of food they are ordering, showing an association between food ordered and drink ordered.
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1)Write a word problem that can be solved by the mathematics or the lesson that we are learning about variation given a problem: 2) changeone of the value in the problem. Explain how it would change the situations and the solution. A. Problem B. Solution C. Explanation difference between the two problems.
Many times referred to as "story issues," word problems can range in the amount of technical terminology utilized and typically incorporate some form of narrative.
What is considered a word problem in math?Many times referred to as "story issues," word problems can range in the amount of technical terminology utilized and typically incorporate some form of narrative.Jack has 2 dogs and 8 cats, for instance.7 cats and 4 dogs are owned by Jill.What's the total number of dogs?How many more cats does Jane have than I do if she has 23 and I only have 2 cats? What happens if Jane then gives me 5 cats?Mathematical questions that are written as one or more sentences and ask students to use their mathematical understanding to solve problems from "real-life" situations are known as word problems.In order for kids to understand the word problem, they must be familiar with the terminology that goes along with the mathematical symbols that they are used to.To learn more about word problem refer
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question 4 (essay worth 15 points) (06.05, 06.06 hc) students were asked to prove the identity (sec x)(csc x)
trignometry of secx * cscx= 1/ cosx*sinx = sin^2 x+ cos ^ 2 x/ cos x * sin x = cotx + tan x
What is the formula of sin?
The sine of an angle of a right-angled triangle is the ratio of its perpendicular (that is opposite to the angle) to the hypotenuse. The sin formula is given as: sin θ = Perpendicular / Hypotenuse.
secx = 1/cosx
and cscx= 1/sin x
then secx * cscx= 1/ cosx*sinx
= sin^2 x+ cos ^ 2 x/ cos x * sin x
= cotx + tan x
Hence trignometry of secx * cscx= 1/ cosx*sinx = sin^2 x+ cos ^ 2 x/ cos x * sin x = cotx + tan x
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Find the height of the triangle.
Answer:
6 cm
Step-by-step explanation:
a = 1/2bh
42 = 1/2(14)h
42 = 7h Divide both sides by 7
6 = h
Can you simply x-10
——
10
The equation be (x - 10)(x + 10) then x² - 100.
What is meant by expression?In addition to the monomial, binomial, and polynomial types of expressions, there are two further categories into which an algebraic expression can be placed: Expression in numbers. adjustable expression.
Using the operations + , – , × or ÷ a group of numbers or variables can be combined to form an expression. Expressions in algebra that include variables, numbers, and mathematical operators differ from expressions in arithmetic that simply contain numbers and mathematical operators.
Let the equation be (x - 10)(x + 10)
(x - 10)(x + 10)
simplifying the above equation, we get
= x² - 100
The equation be (x - 10)(x + 10) then x² - 100.
The complete question is:
How do you simplify (x - 10)(x + 10) ?
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Solve the formula firnthebspecified variable
I= Prt
P=
Answer:
Solve the formula firnthebspecified variable
I= Prt
P=
below is a stem and leaf plot of the magnitude of earthquakes on sept. 4th, 2012 in the philippine islands region. this data was collected by the general social survey. find the third quartile.
The value of the third quartile was then found to be 4.0, which is the 12th entry in the ordered data.
below is a stem and leaf plot of the magnitude of earthquakes on sept. 4th, 2012 in the philippine islands region. this data was collected by the general social survey. find the third quartile.
Stem|Leaf
2 | 0 2 3 6 8 9
3 | 0 1 3 4 6 7 8
4 | 0 1 2 4 5
Third Quartile = 4.0
Step 1: Order the data from least to greatest:
2.0, 2.3, 2.6, 2.8, 2.9, 3.0, 3.1, 3.3, 3.4, 3.6, 3.7, 3.8, 4.0, 4.1, 4.2, 4.4, 4.5
Step 2: Count the data points:
There are 16 data points.
Step 3: Calculate the index of the third quartile:
Index of third quartile = (3/4) x (16) = 12
Step 4: Find the value of the third quartile:
The value of the third quartile is the 12th entry in the ordered data, which is 4.0.
The third quartile of the magnitude of earthquakes in the Philippine Islands region on September 4th, 2012 is 4.0. This data was collected by the General Social Survey. To calculate the third quartile, the data points were ordered from least to greatest and the index of the third quartile was calculated. The value of the third quartile was then found to be 4.0, which is the 12th entry in the ordered data.
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Carolyn has $2.55 in her purse in nickels and dimes. The number of nickels in nine less than three times the number of dimes. Find the number of each type of coin
This is a system of equations problem. Let x be the number of dimes and y be the number of nickels.
From the problem, we know the following:
x + y = n (where n is the total number of coins)
y = 3x - 9 (because the number of nickels is three times the number of dimes minus nine)
We also know that the total value of the coins is $2.55 and that a dime is worth $0.10 and a nickel is worth $0.05. So we can create an equation using the total value of the coins:
0.10x + 0.05y = 2.55
Now we have a system of three equations and three variables. To solve for x, y and n, we can use substitution or elimination method.
First equation and second equation:
x+3x-9 = n
4x-9=n
4x = n+9
x = (n+9)/4
By substituting the value of x in equation 3
0.10*(n+9)/4 + 0.05*(3*(n+9)/4-9) = 2.55
Solving this equation we get n = 63
Thus, x = (63+9)/4 = 18 dimes
y = 3x - 9 = 3*18 - 9 = 45 nickels
So, Carolyn has 18 dimes and 45 nickels.
Two runners start a race at the same time and finish in a tie. Prove that at some time during the race they have the same speed. [Hint: Consider f(t) = g(t) - h(t) , where and are the position functions of the two runners.
Let's use v1(t) and v2(t) to represent the speed of the first and second runners, respectively, at time t. The functions v1 and v2 must both be continuous in the time variable t, hence this assumption must be made.
So, their difference, a(t), is similarly a continuous function in the variable t, with the formula a(t) = v1(t)-v2(t).
Now, using the principle of contradiction, one may demonstrate that t1, t2, such that a(t1) is less than or equal to 0 and a(t2) is higher than or equal to 0, exist because the overall average speed of both runners is identical.
Now, we may utilize the continuous function a's Intermediate Value Property to locate a t0 between t1 and t2, where a(to)=0 and the runners are moving at the same speed at this point.
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find the quadratic polynomial, the sum of whose zeroes is 8 and their product is 12. hence, find the zeroes of the polynomial.
The required quadratic polynomial is [tex]x^{2} - 8x + 12 =0[/tex] and roots of this quadratic polynomial are 2 and 6.
Let the roots of the quadratic equation be [tex]\alpha[/tex] and [tex]\beta[/tex] .
Given,
Sum of zeroes, [tex]\alpha +\beta = 8[/tex]
Product of Zeroes, [tex]\alpha *\beta = 12[/tex]
we know that,
Quadratic Equation can be written as :
[tex]x^{2} - (\alpha + \beta )x + \alpha \beta =0[/tex]
Substituting the values in the above Equation,
[tex]x^{2} - (8)x + (12) =0[/tex]
[tex]x^{2} - 8x + 12 =0[/tex]
Hence, The required quadratic equation is [tex]x^{2} - 8x + 12 =0[/tex] .
Now, let's factorize the equation to find its root:
[tex]x^{2} - 8x + 12 =0[/tex]
[tex]x^{2} - 6x -2x+ 12 =0[/tex]
[tex]x(x-6) -2(x-6)=0[/tex]
[tex](x-6)(x-2)=0[/tex]
⇒ [tex]x= 2,6[/tex]
Therefore roots of the quadratic equation [tex]\alpha ,\beta[/tex] are [tex]2,6[/tex] .
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A group of tourists spent three days hiking from the beginning to the end of the trail. On the first day, they hiked 1/8 of the trail. On the second day, they hiked 4/7 of the remaining trail. On the third day, they hiked 1/3 of the remaining trail plus the last 8 km. How many km long is the trail.
I NEED THE ANSWER FAST
The length of the trail is given as follows:
32 km.
How to obtain the length of the trail?The length of the trail is obtained applying the proportions in the context of this problem.
The fractions hiked each day are given as follows:
First day: 1/8.Second day: 4/7 of the remaining 7/8.Third day: 1/3 of the remaining plus 8 km.The total fraction after the second day is given as follows:
1/8 + 4/7 x 7/8 = 5/8.
On the third day, one third of the remaining was hiked, hence:
5/8 + 1/3 x 3/8 = 6/8.
Meaning that the remaining distance of 8 km is 2/8 = 1/4 of the total distance, hence:
x/4 = 8
x = 32 km.
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Please god someone help me with this, I literally do not understand. if someone coudl just please explain what I am to do, you don't have to do. please help me!
Answer:
[tex]\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12}\sf Bank & \sf Basic\;Fee\times 12 & \sf Bill\;Paying\;Fee\times 12 & \sf Checks\;Written-Limit\\\cline{1-4}\vphantom{\dfrac12}\sf A&\$18&\$27&20\\\cline{1-4}\vphantom{\dfrac12}\sf B&\$30&\$27&10\\\cline{1-4}\vphantom{\dfrac12}\sf C&\$18&\$21&10\\\cline{1-4}\vphantom{\dfrac12}\sf D&\$30&\$21&20\\\cline{1-4}\end{array}[/tex]
[tex]\begin{array}{|c|c|c|}\cline{1-3}\vphantom{\dfrac12}\sf Bank & \sf Column\;4\times Cost\;per\;bill\times 12 & \sf Annual\;Total\\\cline{1-3}\vphantom{\dfrac12}\sf A&\$24&\$69\\\cline{1-3}\vphantom{\dfrac12}\sf B&\$18&\$75\\\cline{1-3}\vphantom{\dfrac12}\sf C&\$24&\$63\\\cline{1-3}\vphantom{\dfrac12}\sf D&\$48&\$99\\\cline{1-3}\end{array}[/tex]
Step-by-step explanation:
Jane wants to compare the cost of online banking across 4 different banks. We are told that she writes an average of 40 checks each month.
Given monthly charges for four different banks:
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5}\vphantom{\dfrac12}\sf Bank & \sf Basic\;Monthly\;Fee& \sf Bill\;Paying\;Monthly\;Fee & \sf Limit& \sf Cost\;per\;bill\;beyond\;limit\\\cline{1-5}\vphantom{\dfrac12}\sf A&\$1.50&\$2.25&20&\$0.10\\\cline{1-5}\vphantom{\dfrac12}\sf B&\$2.50&\$2.25&30&\$0.15\\\cline{1-5}\vphantom{\dfrac12}\sf C&\$1.50&\$1.75&30&\$0.20\\\cline{1-5}\vphantom{\dfrac12}\sf D&\$2.50&\$1.75&20&\$0.20\\\cline{1-5}\end{array}[/tex]
The "limit" is the number of checks Jane is not charged a fee to write per month. For each check Jane writes above this monthly limit, she will be charged a fee (fifth column).
To complete the first table:
The second column is the charge per year for the basic fee. So we have to multiply the given "basic monthly fee" by 12 to calculate the basic fee per year (since there are 12 months in a year).The third column is the charge per year for the bill paying fee. Again, multiply the given "bill paying monthly fee" by 12 to calculate the bill paying fee per year (since there are 12 months in a year).The fourth column is the number of checks Jane writes per month more than the given limit. So as Jane writes an average of 40 checks per month, we have to subtract the given limit from 40.[tex]\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12}\sf Bank&\sf Basic\;Fee\times12&\sf Bill\;Paying\;Fee\times12&\sf Checks\;Written-Limit\\\cline{1-4}\vphantom{\dfrac12}\sf A&\$1.50\times12=\$18&\$2.25\times12=\$27&40-20=20\\\cline{1-4}\vphantom{\dfrac12}\sf B&\$2.50\times12=\$30&\$2.25\times12=\$27&40-30=10\\\cline{1-4}\vphantom{\dfrac12}\sf C&\$1.50\times12=\$18&\$1.75\times12=\$21&40-30=10\\\cline{1-4}\vphantom{\dfrac12}\sf D&\$2.50\times12=\$30&\$1.75\times12=\$21&40-20=20\\\cline{1-4}\end{array}[/tex]
To complete the second table:
The second column is the charge per year for the number of checks Jane writes over each bank's "free" limit. So multiply the number from the fourth column of the first table (Checks Written - Limit) by the "Cost per bill beyond limit" from the given table of information and then multiply by 12.The third column is the annual total charged by each bank. Sum "Basic Fee x 12" and "Bill Paying Fee x 12" and "Column 4 x Cost Per Bill x 12" for each bank.[tex]\begin{array}{|c|c|c|}\cline{1-3}\vphantom{\dfrac12}\sf Bank & \sf Column\;4\times Cost\;per\;bill\times 12 & \sf Annual\;Total\\\cline{1-3}\vphantom{\dfrac12}\sf A&20\times\$0.10\times12=\$24&\$18+\$27+\$24=\$69\\\cline{1-3}\vphantom{\dfrac12}\sf B&10\times\$0.15\times12=\$18&\$30+\$27+\$18=\$75\\\cline{1-3}\vphantom{\dfrac12}\sf C&10\times\$0.20\times12=\$24&\$18+\$21+\$24=\$63\\\cline{1-3}\vphantom{\dfrac12}\sf D&20\times\$0.20\times12=\$48&\$30+\$21+\$48=\$99\\\cline{1-3}\end{array}[/tex]
What is the slope of the line? m=
The slope of the line is given by the equation m = -3
What is an Equation of a line?The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept
And y - y₁ = m ( x - x₁ )
y = y-coordinate of second point
y₁ = y-coordinate of point one
m = slope
x = x-coordinate of second point
x₁ = x-coordinate of point one
The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )
Given data ,
Let the equation of line be represented as A
Now , the value of A is
Let the first point be represented as P ( 2 , -1 )
Let the second point be represented as Q ( 1 , 2 )
Now , the slope of the line between the points is
Slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )
Substituting the values in the equation , we get
Slope m = ( 2 - ( -1 ) ) / 1 - 2
Slope m = 3 / -1
Slope m = -3
Hence , the slope of the line is decreasing as m = -3 and has a negative value
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10. A company sold a total of $1440 in gift bears for Valentine's Day. If the gift bears cost $15 apiece, how many gift bears did it sell? A. 15 B. 96 C. 144 D. 1440
Answer:A
Step-by-step explanation:
1440:15=96
Drawn In A Circle Whose Radius Is 12 Cm, Chord AB Is 16 Cm Long. Calculate The Angular Size Of Minor Arc AB.
The angular size of the minor arc AB can be calculated using the formula: Angular size = Arc length/Radius. Therefore, the angular size of the minor arc AB is 16 cm/12 cm = 1.333 radians.
The angular size of the minor arc AB can be calculated using the formula: Angular size = Arc length/Radius. To calculate the angular size of the minor arc AB, we need to know the length of the chord AB and the radius of the circle. In this case, the chord AB is 16 cm long and the radius of the circle is 12 cm. Therefore, we can calculate the angular size of the minor arc AB by dividing the length of the chord AB by the radius of the circle, which is 16 cm/12 cm = 1.333 radians. The angular size of the minor arc AB is 1.333 radians.
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questionyou download a digital soccer game for $\$2.50$ . you can add new players for $\$1.50$ each to upgrade your team. the total cost $c$ is a function of the number $n$ of new players that you add. which of the following statements about the domain and the graph of the function is correct?
The domain of the function is all real numbers[tex]$\{x|x\in \mathbb{R}\}$[/tex] greater or equal to 0, because the number of players $n$ can not be negative.
The graph of the function is a line with a slope of 1.5 and a y-intercept of 2.5. This can be seen by considering the equation c(n) = 1.5n + 2.5. As the number of new players n increases, the cost c increases by 1.5 for each new player added. For example, if you add 3 new players, the total cost c is 1.5(3) + 2.5 = 6.5. Similarly, if you add 5 new players, the total cost is 1.5(5) + 2.5 = 8.5.
For example, if you want to add 10 new players, the cost will be $c=1.50\times10+2.50=17.50$. Substituting $n=10$ into the function gives $c=17.50$. The graph of this function is a straight line that passes through the origin and has a positive slope of 1.50.
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