Determine the mmol of both starting materials (factoring in that formic acid is not pure, but rather 88% weight/volume, or 88g/100 ml), showing your work. Determine the limiting reagent in this synthesis. Lastly, calculate the theoretical yield of benzimidazole that you could expect to form.

Answers

Answer 1

Solution :

Molecular      Molar Mass       Volume      Density       Mass      Moles      nmoles

formula            (g/mol)               (mL)          (g/mL)           (g)

[tex]$C_6H_8N_2$[/tex]            108.14                                                    0.108      0.001          1

HCOOH           46.02                0.064          1.22     0.07808     0.0017       1.7

mmoles of o-phenylenediamine = 1 mmoles

mmoles of formic acid = 1.7 [tex]\approx[/tex] 2 mmoles

From the reaction of o-phenylenediamine and formic acid, we see,

1 mmole of o-phenylenediamine reacts with 1 mmole of formic acid.

But here, 2 mmoles of the formic acid , this means that the formic acid is an excess reagent and the o-phenylenediamine is the limiting reagent here.

The amount of product depends on the limiting reagent that is o-phenylenediamine. So, 1mmole of o-phenylenediamine will give 1mmole of product.

molar mass of Benzimidazole = [tex]118.14[/tex] g/mol

mmoles of Benzimidazole formed = [tex]1[/tex] mmol

Mass of benzimidazole formed = molar mass x [tex]\frac{nmoles}{1000}[/tex]

                                                    [tex]$=\frac{118.14 \times 1}{1000}$[/tex]

                                                     = 0.11814 g

So the theoretical yield of Benzimidazole is = 0.118 g = 118mg


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List the known and unknown quantities and plan the problem. Change each percent abundance into decimal form by dividing by 100. Multiply this value by the atomic mass of that isotope. Add together for each isotope to get the average atomic mass

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Answer:

Space-based telescopes like Hubble get a much clearer view of the universe than most of their ground-based counterparts. ... Ground-based telescopes can't do the same, because the Earth's atmosphere absorbs a lot of the infrared and ultraviolet light that passes through it.

A Carnot engine takes 2000 j of heat from a reservoir at 500 k, does some work and discards some heat to a reservoir at 350k . how much work does it do, how much heat is discarded, and what is it's efficiency?​

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Answer:

Explanation:

The Carnot engine is a theoretical or conceptual heat engine that has a higher efficiency than any practical or theoretical heat engine working between the same temperature range. The theoretical efficiency of a Carnot engine is considered as the highest efficiency and no practical heat engines can operate at that efficiency. A Carnot engine draws heat energy, performs useful work and the leftover energy is released from the working substance. According to the second law of thermodynamics, there must be a temperature gradient between the heat energy drawing point and release point of the heat engine.

The decomposition of ethanol (C2H5OH) on an alumina (Al2O3) surface C2H5OH1 g2 h C2H4 1 g2 1 H2O1 g2 was studied at 600 K. Concentration versus time data were col- lected for this reaction, and a plot of [A] versus time resulted in a straight line with a slope of 24.00 3 1025 mol/L  s. a. Determine the rate law, the integrated rate law, and the value of the rate constant for this reaction. b. If the initial concentration of C2H5OH was 1.25 3 1022 M, calculate the half-life for this reaction. c. How much time is required for all the 1.25 3 1022 M C2H5OH to decompose?

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The rate constant for the decomposition of ethanol on an alumina surface is 24.00 × 10²⁵ M.

The rate law is: rate = 24.00 × 10²⁵ M/s

The integrated rate law is: [C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, the half-life is 2.60 × 10⁻⁵ s.

The time required for all the 1.25 × 10²² M C₂H₅OH to decompose is 5.21 × 10⁻⁵ s.

Let's consider the decomposition of ethanol on an alumina surface.

C₂H₅OH(g) ⇒ C₂H₄(g) + H₂O(g)

The plot of [A] vs time (t) resulted in a straight line, which indicates that the reaction follows zero-order kinetics.

The slope, 24.00 × 10²⁵ M/s, represents the rate constant, k.

What is zero-order kinetics?

It is a chemical reaction in which the rate of reaction is constant and independent of the concentration of the reacting substances

The rate law for zero-order kinetics is:

rate = 24.00 × 10²⁵ M/s

The integrated rate law for zero-order kinetics is:

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

What is the half-life?

Is the time for the amount of substance to decrease by half.

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, we can calculate the half-life [t(1/2)] using the following formula.

t(1/2) = [C₂H₅OH]₀ / 2 × k

t(1/2) = (1.25 × 10²² M) / 2 × (24.00 × 10²⁵ M/s) = 2.60 × 10⁻⁵ s

We can calculate the time required for all the 1.25 × 10²² M C₂H₅OH to decompose using the integrated rate law.

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

0 M = 1.25 × 10²² M - 24.00 × 10²⁵ M/s × t

t = 5.21 × 10⁻⁵ s

The rate constant for the decomposition of ethanol on an alumina surface is 24.00 × 10²⁵ M.

The rate law is: rate = 24.00 × 10²⁵ M/s

The integrated rate law is: [C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, the half-life is 2.60 × 10⁻⁵ s.

The time required for all the 1.25 × 10²² M C₂H₅OH to decompose is 5.21 × 10⁻⁵ s.

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Define Endothermic reaction in terms of Deta H

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I didn't learn about that topic in school,but I found this :

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which planet is closests to the moon

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Answer:

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Explanation:

Answer:

Earth

Explanation:

Hope this helps! Pls give brainliest! Also, please sub to Kgirl633 on yt.

Many fundamental concepts are at the heart of chemistry. Match the description to the name.

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Answer:

you dony have a picture for me to match them

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Apply Concepts
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Answer:

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Explanation:

about distillation methods​

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Answer:

Distillation, or classical distillation, is the process of separating the components or substances from a liquid mixture by using selective boiling and condensation. Dry distillation is the heating of solid materials to produce gaseous products

Answer:

Explanation:

Distillation, or classical distillation, is the process of separating the components or substances from a liquid mixture by using selective boiling and condensation. Dry distillation is the heating of solid materials to produce gaseous products.

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Answer:

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Even in pitchblende, polonium is exceedingly rare: 1,000 tons of ore must be treated to yield 40 milligrams of polonium. It has a one-part-in-ten-thousandth-thousandth-thousandth-thousandth-thousandth-thousandth It is found in nature as a byproduct of the radioactive decay of uranium, thorium, and actinium.

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please help me...
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Answer:

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Lithium has an atomic mass of 6.941 amu. Lithium has two isotopes. One isotopes has a mass of 6.015 amu with a relative abundance of 7.49%. What is the mass of the other isotopes?

Answers

Explanation:

List the known and unknown quantities and plan the problem. Change each percent abundance into decimal form by dividing by 100. Multiply this value by the atomic mass of that isotope. Add together for each isotope to get the average atomic mass.

Answer:

The atomic mass of second isotope is 7.016

Explanation:

Given data:

Average Atomic mass of lithium = 6.941 amu

Atomic mass of first isotope = 6.015 amu

Relative abundance of first isotope = 7.49%

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Solution:

Total abundance = 100%

100 - 7.49 = 92.51%

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Now we will calculate the mass if second isotope.

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6.941 = (6.015×7.49)+(x×92.51) /100

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Answer:

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+
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Question:

Sodium chloride reacts with copper sulfate to produce sodium sulfate and copper chloride.

2NaCl(aq) + CuSO4(aq) → Na2SO4(aq) + CuCl2(s)

+

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ありがとう!

Sodium chloride reacts with copper sulfate to produce sodium sulfate and copper chloride. This equation represents a double replacement reaction. Therefore, the correct option is option D.

What is double replacement reaction?

In a double replacement process, the ions in two input ionic compounds are exchanged for the same ions in two new product compounds. When two reactants swap cations or anions to produce two new products, the process is known as a double replacement reaction.

Double displacement reactions and metathesis reactions are other names for double replacement processes. Double replacement reactions include neutralisation, precipitation, and gas production. Sodium chloride reacts with copper sulfate to produce sodium sulfate and copper chloride. This equation represents a double replacement reaction.

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help please I'll mark you as a brainliest promise.​

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Answer:

Law of the Sea Treaty

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D. Above and before the symbol.

Answers

Answer:A

Explanation

:

The balanced chemical equation for the conversion of nitrogen to ammonia is:2N₂(g) + 3H2(g)2NH3(g): Which of the following statements concerning this chemical equation is/are correct?

1. In a 22.4 L container at standard temperature, 2 atm of nitrogen gas will react with 3 atm of hydrogen gas to produce 2 atm of ammonia gas.

2. At standard pressure and temperature, 22.4 L of nitrogen gas will react with 22.4 L of hydrogen gas to produce 22.4 L of ammonia gas.

3. At standard pressure and temperature, 44.8 L of nitrogen gas will react with 67.2 L of hydrogen gas produce

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Answers

Answer:

At standard temperature and pressure, 44.8

Explanation:

A 0.500-g sample containing Na2CO3 plus inert matter is analyzed by adding 50.0 mL of 0.100 M HCl, a slight excess, boiling to remove CO2, and then back-titrating the excess acid with 0.100 M NaOH. If 5.6 mL NaOH is required for the back-titration, what is the percent Na2CO3 in the sample?

Answers

The percentage by mass of Na2CO3 in the sample is 48%.

The equation of the reaction of Na2CO3 with HCl;

Na2CO3(aq) + 2HCl(aq) ------> 2NaCl(aq) + H2O(l) + CO2(g)

Since the HCl is in excess, the excess is back titrated with NaOH as follows;

NaOH (aq) + HCl(aq) ---->NaCl(aq) + H2O(l)

Number of moles of HCl added =  0.100 M × 50/1000 L = 0.005 moles

Number of moles of NaOH added = 5.6/1000 ×  0.100 M = 0.00056 moles

Since the reaction of NaOH and NaOH is 1:1, 0.00056 moles of HCl reacted with excess HCl.

Amount of HCl that reacted with Na2CO3 =  0.005 moles -  0.00056 moles = 0.0044 moles

Now;

1 mole of Na2CO3 reacts with 2 moles of HCl

x moles of Na2CO3 reacts with 0.0044 moles of HCl

x = 1 mole × 0.0044 moles / 2 moles

x = 0.0022 moles

Mass of Na2CO3 reacted = 0.0022 moles × 106 g/mol = 0.24 g

Percentage of Na2CO3  in the sample = 0.24 g/ 0.500-g × 100/1 = 48%

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Which of the following transports information from the eye to the brain?

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B) visual cortex

C) optic nerve

D) cornea

Answers

Answer:

c

Explanation:

c is the correct answer

Answer:

c

Explanation:

Which of the following best represents a ​chemical change?

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B. Silver tarnishing (changing color)
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B. silver tarnishing

Explain why the first ionisation energy of beryllium is higher than the first ionisation
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Answer:

since the distance between the electron and the nucleus is smaller in B than in Li, the electrostatic nuclear force of attraction experienced by B is higher than the one experienced by Li...this translates to the higher first ionization energy in B than in Li.

Explanation:

i hope it's helping!

Which is warmer -30C or -30 F?​

Answers

-30°F is warmer than -30°C.

The -ve sign is used when the temperature drops down. Celsius is the greater unit. By converting, -30°F = -1.11°C (approx.) We know that, -1.11 > -30. So, -30°F (-1.11°C) is warmer than -30°C.

Formula :-

(x°C × 9/5) + 32 = y°F

_____

Hope it helps ⚜

Answer:

-30 c is warmer

Explanation:

-30 c =-22 f

-30 f=-34.444 c

Differentiate between acids and bases on the basis of their pH values Give an example of each type. Please help worth 100 points!!!!!!!

Answers

Answer: Well 0-7 is acid, and 0-3 is a strong acid. 4-7 is a weak acid. 8-11 is strong base. 12-14 is weak base!

Explanation:

Below the time line, list the layers from oldest to youngest

Answers

Answer:

F,E,D,C, B, A, G, H, I

Explanation:

I think. It goes bottom to top. the fault probably cause g to happen and maybe h but mattering on what caused what I am not positive

Which of the following is a challenge of prosthetic engineering that has been met through tissue engineering?

- Predicting failure
- Biocompatibility
- Strength
- Power

Answers

Answer:

Biocompatibility

Explanation:

I’m a genius and it’s the answer :D

Biocompatibility is a challenge of prosthetic engineering that has been met through tissue engineering. Hence, option B is correct.

What is Biocompatibility?

Biocompatible materials are used in medical devices, such as menstrual cups, stents, or ventilators.

A biocompatibility problem might happen when some of the materials are trapped in the patient's gingival sulcus.

Tissue engineering is an important field of regenerative medicine for tissue repair (after damaged caused by a disease or an accident, for example).

To offer this possibility, stem cells are important tools owing to their capacity to differentiate into a large number of cells according to the stimuli provided.

Hence, option B is correct.

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Would you expect a Boron (B) atom with atomic mass = 9.999 to be stable?

Answers

The balance of forces allows to find the result for the question if the isotope of boron 9.99 una  is stable:

The boron isotope of mass 9.99 uma is unstable because the repulsive force increases.

The stability of atomic nuclei depends on the balance the force is electrostatic repulsion between the protons and the strong interaction of attraction.

One way to achieve this balance is to increase the separation of the protons with uncharged particles between them, the neutral ones, the strong interaction is of the same magnitude for protons and neutrons, therefore the repulsion is decreased and the strong attraction interaction is maintained. .

In the case of Boron, which has 5 protons, the stable structures have more atomistic 10 and 11 una, which is why it has 5 and 6 neutrons each. Therefore each proton has  a neutrons next to it and in the other case a proton at the end has two neutrons, this causes the distance between the protons to increase, decreasing the electrostatic repulsion.

It indicates that we have a Boron nucleus of mass 9.999. The number of protons must remain fixed, therefore there are only 4 neutrons.

Consequently, some of the protons does not have a neutron next to it and can approach the other proton, therefore the electrostatic repulsion increases and the stability of the atom decreases.

In conclusion, using the balance of Forces we can find the result for the question if the isotope of boron 9.99 una is stable:

The boron isotope of mass 9.99 amu is unstable because the repulsive force increases.

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