Answer:
228573
Step-by-step explanation:
a = 219 (first term)
an = 2018 (last term)
Sn->Sum of n terms
Sn=n/2(a + an) [Where n is no. of terms] -> eq 1
To find number of terms,
an = a + (n-1)d [d->Common Difference] -> eq 2
d= 226-219 = 7
=> d=7
Substituting in eq 2,
2018 = 219 + (n-1)(7)
1799 = (n-1)(7)
1799 = 7n-7
1799 = 7(n-1)
1799/7 = n-1
257 = n-1
n=258
Substituting values in eq 1,
Sn = 258/2(219+2018)
= 129(2237)
= 228573
Determine the y-intercept of the quadratic equation Y = x^2 - 4x + 8
9514 1404 393
Answer:
(0, 8)
Step-by-step explanation:
The y-value of the y-intercept is the function value when x=0. That is the constant in the equation, since x=0 will make all of the x-terms be zero.
y-intercept = 8
When (8x − 4) = 2x is solved, the result is:
Answer:
x = 1
General Formulas and Concepts:
Pre-Algebra
Distributive Property
Equality Properties
Multiplication Property of EqualityDivision Property of EqualityAddition Property of EqualitySubtraction Property of EqualityAlgebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
1/2(8x - 4) = 2x
Step 2: Solve for x
[Distributive Property] Distribute 1/2: 4x - 2 = 2x[Subtraction Property of Equality] Subtract 2x on both sides: 2x - 2 = 0[Addition Property of Equality] Add 2 on both sides: 2x = 2[Division Property of Equality] Divide 2 on both sides: x = 1Answer:
x = 2/3
Step-by-step explanation:
(8x − 4) = 2x
8x - 4 = 2x
6x = 4
x = 2/3
From a group of three boys and six girls a boy and a girl will be selected to attend a conference and how many ways can the selection you made
Answer:
18
Girl = g
Boy = b
1g 1b 1g 2b 1g 3b
2g 1b 2g 2b 2g 3b
3g 1b 3g 2b 3g 3b
4g 1b 4g 2b 4g 3b
5g 1b 5g 2b 5g 3b
6g 1b 6g 2b 6g 3b
---------------------------------------
Another way you can do this,
6 × 3 = 18
In the end there will be 18 selections.
Grandfather Giovanni's hens lay 180 eggs per day, which are placed in containers of 6 each. How many containers will you need per day?
Answer:
6
Step-by-step explanation:
State the quadrant in which the terminal side of the given angle lies.
0
=
Зл
5
Rotate the vector 3,-2 90 degrees clockwise about the origin.
Answer:
-2,-3
Step-by-step explanation:
Answer:
-2 -3
It worked for me on acellus
Step-by-step explanation:
40 POINTS- please help me
Answer:
a, c, d,
Step-by-step explanation:
I'm not sure if this is right but i think.
First you cant have exponents in a linear equation, so its not e or f. Then i just graphed the rest.
Given that the days are the independent variable, which dependent variable has a constant rate of change?
What is the difference quotient for the function f(x) = 8/ 4x + 1
Answer:
Last option (counting from the top)
Step-by-step explanation:
For a given function f(x), the difference quotient is:
[tex]\frac{f(x + h) - f(x)}{h} = \frac{1}{h}*(f(x + h) - f(x))[/tex]
In this case, we have:
[tex]f(x) = \frac{8}{4x + 1}[/tex]
Then the difference quotient will be:
[tex]\frac{1}{h}*( \frac{8}{4*(x + h) + 1} - \frac{8}{4x + 1})[/tex]
Now we should get a common denominator.
We can do that by multiplying and dividing each fraction by the denominator of the other fraction, so we will get:
[tex]\frac{1}{h}*( \frac{8}{4*(x + h) + 1} - \frac{8}{4x + 1}) = \frac{1}{h}*(\frac{8*(4x + 1)}{(4(x + h) +1 )*(4x + 1)} - \frac{8*(4(x + h) + 1)}{(4(x + h) +1 )*(4x + 1)})[/tex]
Now we can simplify that to get:
[tex]\frac{1}{h}*\frac{8*(4x + 1) - 8*(4(x + h) + 1)}{(4(x + h) +1 )*(4x + 1)}} = \frac{1}{h}*\frac{-32h}{(4(x + h) +1 )*(4x + 1)}} = \frac{-32}{(4(x + h) +1 )*(4x + 1)}}[/tex]
Then the correct option is the last one (counting from the top)
SEE QUESTION IN IMAGE
Answer:
B. 48°Step-by-step explanation:
∠OST = 90° as ST ⊥ OS (tangent is perpendicular to radius at same point)
m∠OSP = 1/2(180° - m∠SOP) = 90° - 96°/2 = 42° (sum of interior angles of the triangle SOP)
m∠PST = 90° - m∠OSP = 90° - 42° = 48° (angle addition postulate)
Correct choice is B
Solve the system of equations using the substitution method. -x − 2y = 0 y = -8x (x, y) = ( , )
Answer:
[tex] = { \tt{(0, \: 0)}}[/tex]
Step-by-step explanation:
Let:
[tex]{ \bf{ - x - 2y = 0 - - - (a)}} \\ { \bf{y = - 8x - - - (b)}}[/tex]
Substitute for y in equation (b) to equation (a):
[tex]{ \tt{ - x - 2( - 8x) = 0}} \\ { \tt{ - x + 16x = 0 }} \\ { \tt{x = 0}}[/tex]
Also, y = 0
Which algebraic expression represents the phrase "six less than a number"?
Answer:
[tex]x-6[/tex]
Step-by-step explanation:
We can let the 'number' in the expression be equal to [tex]x[/tex]. Something 6 less than x would x minus 6, or [tex]x-6[/tex].
Answer:
x-6
Step-by-step explanation:
Let the number be x
Less than means subtract from
x-6
Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah, a total of 8 people took the trip. She was able to purchase coach tickets for $300 and first-class tickets for $1060. She used her total budget for airfare for the trip, which was $6960. How many first-class tickets did she buy?
How many coach tickets did she buy?
number of first-class tickets bought nothing number of coach tickets bought nothing
Answer:
She bought 6 first class tickets and 1 coach ticket
Step-by-step explanation:
1060(6)= 6360 and 6960-6360=300 and 300 is the price for a coach ticket.
Form a third-degree polynomial function with real coefficients, with leading coefficient 1, such that 6+i and 5 are zeros.
Answer:
A third-degree polynomial can be written as:
f(x) = a*x^3 + b*x^2 + c*x + d
Where the leading coefficient is a, and all the coefficients are real.
If we know that the leading coefficient is 1, then the equation becomes:
f(x) = x^3 + b*x^2 + c*x + d
Now, we also know that:
(6 + i) and 5 are zeros.
This means that:
(6 + i)^3 + b*(6 + i)^2 + c*(6 + i) + d = 0
remember that:
i^2 = - 1
This is equal to:
(6 + i)*(36 + 2*6*i + i^2) + b*(36 + 2*6*i + i^2) + c*(6 + i) + d = 0
(6 + i)*(35 + 12i) + b*(35 + 12i) + c*(6 + i) + d =0
(210 + 35i + 72i - 12) + b*(35 + 12i) + c*(6 + i) + d = 0
198 + 107i + b*(35 + 12i) + c*(6 + i) + d = 0
sparating in real and imaginary part, we get:
(198 + b*35 + c*6 + d) + (107 + b*12 + c)*i = 0
Then each parentheses needs to be zero, this means that:
198 + b*35 + c*6 + d = 0
107 + b*12 + c = 0
Knowing that 5 is another zero, we have:
5^3 + b*5^2 + c*5 + d = 0
125 + b*25 + c*5 + d = 0
Then we have a system of 3 equations and 3 variables:
198 + b*35 + c*6 + d = 0
107 + b*12 + c = 0
125 + b*25 + c*5 + d = 0
To solve this, we first need to isolate one of the variables in one of the equations.
Let's isolate d in the last one, so we get:
d = -125 - b*25 - c*5
now we can replace this in the first equation to get:
198 + b*35 + c*6 + d = 0
198 + b*35 + c*6 + ( -125 - b*25 - c*5) = 0
70 + b*10 + c = 0
So now we have two equations:
70 + b*10 + c = 0
107 + b*12 + c = 0
Again, now we can isolate the one variable in one of the equations, this time let's isolate c in the first one.
c = -70 - b*10
now we can replace this in the other equation:
107 + b*12 + c = 0
107 + b*12 + (-70 - b*10) = 0
38 + b*2 = 0
now we can solve this for b
b*2 = -38
b = -38/2 = -19
Now, with the equation c = -70 - b*10 we can find the value of c.
c = -70 - b*10 = c = -70 - (-19)*10 = 120
And with the equation d = -125 - b*25 - c*5
we can find the value of d:
d = -125 - b*25 - c*5 = -125 - (-19)*25 - (120)*5 = -250
Then we have:
a = 1
b = -19
c = 120
d = -250
The eqation is:
f(x) = 1*x^3 - 19*x^2 + 120*x - 250
Does this graph represent a function? Why or why not?
A. Yes, because it passes the vertical line test.
B. No, because it is not a straight line.
C. No, because it fails the vertical line test.
D. Yes, because it has two straight lines.
Answer:
with my own opinion the answer is b
What is the quotient?
(-3)
(-3)²
O-9
1
o
1
9
100
O 9
Answer:
(-3)
Step-by-step explanation:
follow me if you want
Find the measures of
Answer:
Step-by-step explanation:
Measure of an inscribed angle intercepted by an arc is half of the measure of the arc.
From the picture attached,
m(∠A) = [tex]\frac{1}{2}m(\text{arc BD})[/tex]
= [tex]\frac{1}{2}[m(\text{BC})+m(\text{CD}][/tex]
= [tex]\frac{1}{2}[55^{\circ}+145^{\circ}][/tex]
= 100°
m(∠C) = [tex]\frac{1}{2}[(360^{\circ})-m(\text{arc BCD})][/tex]
= [tex]\frac{1}{2}(360^{\circ}-200^{\circ})[/tex]
= 80°
m(∠B) + m(∠D) = 180° [ABCD is cyclic quadrilateral]
115° + m(∠D) = 180°
m(∠D) = 65°
m(arc AC) = 2[m(∠D)]
m(arc AB) + m(arc BC) = 2(65°) [Since, m(arc AC) = m(arc AB) + m(arc BC)]
m(arc AB) + 55° = 130°
m(arc AB) = 75°
m(arc ADC) = 2(m∠B)
m(arc AD) + m(arc DC) = 2(115°)
m(arc AD) + 145° = 230°
m(arc AD) = 85°
Hai giá sách có 450 cuốn sách .Nếu chuyển 50 quyển từ giá thứ nhất sang giá thứ hai thì số sách ở giá số hai sẽ bằng 4/5 số sách ở giá thứ nhất ?Tính số sách ở mỗi giá.
Step-by-step explanation:
hơi khó hiểu thông cảm UwU
Givenl || m | n, find the value of x.
. m
44°
77
By
Answer: 0
Submit Answer
attempt 1 out of 2
Can someone pls help
Answer:
x = 136
Step-by-step explanation:
x and 44 are same- side interior angles and sum to 180° , that is
x + 44 = 180 ( subtract 44 from both sides )
x = 136
Here are the ages (in years) of 12 professors at a college.
51, 34, 56, 48, 37, 39, 59, 53, 52, 45, 3367
What is the percentage of these professors who are younger than 50?
=__%
Answer:
50%
Step-by-step explanation:
6 professors younger than 50 years = 6/12 = 50
Answer:
%50
Step-by-step explanation:
If you count the number of proffessors that are under 50, there are six. If there are 12 proffessors then it would be 1/2. One half in percentage is %50.
Pls give Brainliest!
if my mine craft house was burning leaves irl and i was watering my boat on a Wednesday on a weekend in December when its summer how many fish will become orphans late nights in the middle of june?
Will give brainliest need a quick answer
Can someone please help me to evaluate
Answer:
1
Step-by-step explanation:
a*log(b) = log(b^a), so (1/2)*log(196)=log(14)
So 1+log(15)-log(14)=1
If 2^x-4 = 4^x-6 , then value of x is?
Answer: [tex]x=1[/tex]
Step-by-step explanation:
[tex]2^x-4=4^x-6[/tex] is the equation that you've given us.
Now if we plot these two equations on the graph we notice there's an intersection at (1,-2). Therefore meaning that [tex]x=1[/tex].
We can prove that by doing the following calculations to prove that both sides are equal to each other.
The left side of the equal sign:
Step 1: Write the equation down:
[tex]2^x-4[/tex]
Step 2: Substitute x for the numerical value we found.
[tex]2^1-4[/tex]
Step 3: Find the square of [tex]2^1[/tex], which is itself, 2.
[tex]2-4[/tex]
Step 4: Subtract 2 from 4. Which is a negative number, thus being -2.
[tex]-2[/tex]
The right side of the equal sign:
Step 1: Write the equation down:
[tex]4^x-6[/tex]
Step 2: Substitute x for the numerical value we found.
[tex]4^1-6[/tex]
Step 3: Find the square of [tex]4^1[/tex], which is itself, 4.
[tex]4-6[/tex]
Step 4: Subtract 4 from 6. Which is a negative number, thus being -2.
[tex]-2[/tex]
We know that [tex]x=1[/tex] because when substituting x with 1, we get -2 on both sides. Therefore making this statement true and valid.
[tex]-2=-2[/tex]
Customers arrive at a movie theater at the advertised movie time only to find that they have to sit through several previews and prepreview ads before the movie starts. Many complain that the time devoted to previews is too long. A preliminary sample conducted by The Wall Street Journal showed that the standard deviation of the amount of time devoted to previews was 4 minutes. Use that as a planning value for the standard deviation in answering the following questions. Round your answer to next whole number. a. If we want to estimate the population mean time for previews at movie theaters with a margin of error of seconds, what sample size should be used
Answer:
[tex]n=35[/tex]
Step-by-step explanation:
From the question we are told that:
Standard Deviation [tex]\sigma=4min[/tex]
Let
[tex]CI=95\%[/tex]
Since
Significance level [tex]\alpha[/tex]
[tex]\alpha =1-CI[/tex]
[tex]\alpha =1-0.95[/tex]
Therefore
[tex]Z_{\alpha/2}=Z_{0.025[/tex]
[tex]Z_{\alpha/2}}=1.96[/tex]
Generally the equation for Sample size is mathematically given by
[tex]n = (Z_{\alpha/2}* \frac{\sigma}{E})^2[/tex]
[tex]n= \frac{1.96 * 3}{1}^2[/tex]
[tex]n=35[/tex]
Line segment QR is dilated to create line segment Q'R' using the dilation rule DT,1.5. Point T is the center of dilation. Line segment Q R is dilated to create line segment Q prime R prime. The length of R T is 6 and the length of R prime R is y. What is y, the distance between points R and R'?
Answer:
[tex]y= 3[/tex]
Step-by-step explanation:
Given
[tex]RT = 6[/tex]
[tex]k = 1.5[/tex] --- dilation ratio
See attachment
Required
Determine length, y
First, we calculate length R'T.
Since point T is the center of dilation, then:
[tex]R'T = k * RT[/tex]
Substitute known values
[tex]R'T = 1.5 * 6[/tex]
[tex]R'T = 9[/tex]
y is between R'T and RT;
So:
[tex]y = R'T - RT\\[/tex]
[tex]y = 9 -6[/tex]
[tex]y= 3[/tex]
Answer:
either 4 or 9
Step-by-step explanation:
How would two billion, nine hundred seventy-six million, twelve thousand, eight be written
Find the slope of the line
Answer:
The slope is 0.84
Step-by-step explanation:
View solution from above uploaded photos
determine the equation of a line that is vertical and goes through (-5,6)
Answer:
x = -5
Step-by-step explanation:
A vertical line is a line that goes up and down. It is of the form x = constant
To go through (-5,6) is has to have the value of the x coordinate
x = -5
Which statements are true about David's work? Check all that apply. The GCF of the coefficients is correct. The GCF of the variable b should be b4 instead of b2. The variable c is not common to all terms, so a power of c should not have been factored out. The expression in step 5 is equivalent to the given polynomial. In step 6, David applied the distributive property.
Answer:
The GCF of the coefficients is correct.
The variable c is not common to all terms, so a power of c should not have been factored out.
In step 6, David applied the distributive property.
Step-by-step explanation:
Given the polynomial :
80b⁴ – 32b²c³ + 48b⁴c
The Greatest Common Factor (GCF) of the coefficients:
80, 32, 48
Factors of :
80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80
32 : 1, 2, 4, 8, 16, and 32
48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.
GCF = 16
b⁴, b², b⁴
b⁴ = b * b * b * b
b² = b * b
b⁴ = b * b * b * b
GCF = b*b = b²
GCF of c³ and c
c³ = c * c * c
c = c
GCF = c
We can see that David's GCF of the coefficients are all correct
From the polynomial ; 80b⁴ does not contain c ; so factoring out c is incorrect
In step 6 ; the distributive property was used to obtain ; 16b²c(5b² – 2c² + 3b²)
