height and weight are two measurements used to track a childs development an organization measures child development by comparing the weights of children who are the same height and the same gender in a certain year weights for all 80 cm girls in the reference population had a mean
μ = 10.4 kg
and standard deviation
σ = 0.2 kg.
Weights are normally distributed.
X ~ N(10.4, 0.2). Calculate the z-scores that correspond to the following weights and interpret them. (Round your numerical answers to two decimal places.)

Answers

Answer 1

The z-score for a weight of 10.7 kg is 1.50, which means that the weight is 1.50 standard deviations above the mean of 10.4 kg.

Height and weight are two measurements used to track a childs development an organization measures child development by comparing the weights of children who are the same height and the same gender in a certain year weights for all 80 cm girls in the reference population had a mean

μ = 10.4 kg

and standard deviation

σ = 0.2 kg.

Weights are normally distributed.

X ~ N(10.4, 0.2). Calculate the z-scores that correspond to the following weights and interpret them. (Round your numerical answers to two decimal places.)

Weight = 10.7 kg

Z-score = 1.50

This means that the weight of 10.7 kg is 1.50 standard deviations above the mean of 10.4 kg.

First, calculate the difference between the weight (10.7 kg) and the mean (10.4 kg):

x - μ = 10.7 - 10.4 = 0.3

Then, divide the difference by the standard deviation:

(x - μ)/σ = 0.3/0.2 = 1.50

The z-score is 1.50, which means that the weight of 10.7 kg is 1.50 standard deviations above the mean of 10.4 kg.

The z-score for a weight of 10.7 kg is 1.50, which means that the weight is 1.50 standard deviations above the mean of 10.4 kg.

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Related Questions

Crickets chirp to attract other crickets. The temperatures and rates of their chirping are graphed above. Which statement below is most likely true for the data represented in the graph?
answer choices
A. The cooler the temperature, the louder the crickets chirp.
B. The crickets cannot chirp at temperatures lower than 10 degrees Celcius
C. The warmer the temperature, the more often crickets chirp.
D. The temperature and the chirping of crickets are not related.

Answers

C. The warmer the temperature, the more often crickets chirp.

The graph shows a direct correlation between temperature and the rate of chirping. As the temperature increases, the rate of chirping increases as well. Using the formula y=mx+b, where m is the slope of the line and b is the y-intercept, the slope of the line in the graph is approximately 0.5, which means that for every 1 degree Celcius increase in temperature, the rate of chirping increases by 0.5 chirps per second. This proves that the warmer the temperature, the more often the crickets chirp.

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of the 80 seniors at central high 32 are enrolled in at least one ap class and 35 are in a club 18 not enralled random

Answers

Of the 18 number of seniors not enrolled in an AP class or a club, 8 are enrolled in an AP class but not a club, and 10 are not enrolled in an AP class or a club.

First, we need to calculate the total number of seniors enrolled in AP classes and clubs. We know that 32 number of  seniors are enrolled in at least one AP class and 35 are in a club. That means that there are 67 seniors total enrolled in either an AP class or a club.

Next, we need to determine the number of seniors enrolled in both an AP class and a club. We can subtract the total number of seniors enrolled in either an AP class or a club from the total number of seniors at the school (80). This will give us the number of seniors not enrolled in either an AP class or a club, which is 18.

Finally, we can calculate the number of seniors enrolled in an AP class but not a club, and the number of seniors not enrolled in an AP class or a club. We know that there are 18 seniors not enrolled in either an AP class or a club, so we can subtract the number of seniors enrolled in an AP class (32) from 18 to get the number of seniors enrolled in an AP class but not a club, which is 8. We can also subtract the number of seniors enrolled in both an AP class and a club (67) from 18 to get the number of seniors not enrolled

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How do you find the area of the shaded region? Many geometry students struggle to solve shaded areas. The best way to find a shaded region's area is to familiarize yourself with the area decomposition method. The area decomposition method separates the basic shapes found in a given complex figure for fast and organized analysis. Two cases are present in obtaining the areas of the shaded regions – figures with holes and composite figures.

Answers

The area of the shaded region can be found by Area Decomposition Method.

Outer Area Minus Inner Area: Area of the shaded region = Area of the outer shape - Area of the unshaded inner shape

Area of Composite Figures: Area of the shaded region = Area of Region 1 + Area of Region 2 + ...... + Area of nth Region

The Area Decomposition Method:

Understanding the area decomposition method is the key to determining the area of a darkened zone.

For quick and efficient analysis, the area decomposition approach divides the fundamental forms present in a given complex figure.

To obtain the areas of the shaded zones, there are two scenarios.

They are of:

(1) Figures with holes and

(2) Composite figures.

Outer Area Minus Inner Area:

In figures with holes, take into account the area of the figure as a whole without the hole or hollow. By deducting the punch hole area from the whole figure, the remaining area can be found.

The area of the shaded region is equal to the Area of the outer shape minus the Area of the unshaded inner shape

Area of Composite Figures:

A composite plane figure's overall area is the same as the sum of its component areas.

The area of the shaded region is equal to the sum of the Area of Region 1, Area of Region 2, ......, Area of nth Region.

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The math department at a small school has 5 teachers. The ages of these teachers are 23, 34, 37, 42, and 58. Suppose you selected a random sample of 3 teachers and calculated the sample median.
(a) List all 10 possible samples of size 3. Calculate the sample median for each sample.
(b) Display the sampling distribution of the sample median.

Answers

When we select a random sample of 3 teachers and calculated the sample median from ages of 5 teachers in maths department, we get three samples of sample median 34, four samples of sample median 37 and three samples of sample median 42.

a. To list all 10 possible samples of size 3, we can use the combination formula C(5,3) = 5! / (3! * 2!) = 10.

The possible samples are:

Sample 1: (23, 34, 37) - Sample Median: 34

Sample 2: (23, 34, 42) - Sample Median: 34

Sample 3: (23, 34, 58) - Sample Median: 34

Sample 4: (23, 37, 42) - Sample Median: 37

Sample 5: (23, 37, 58) - Sample Median: 37

Sample 6: (23, 42, 58) - Sample Median: 42

Sample 7: (34, 37, 42) - Sample Median: 37

Sample 8: (34, 37, 58) - Sample Median: 37

Sample 9: (34, 42, 58) - Sample Median: 42

Sample 10: (37, 42, 58) - Sample Median: 42

b. To display the sampling distribution of the sample median, we can create a frequency table that shows how many times each sample median appears in the list of possible samples.

Sample Median Frequency

34                         3

37                         4

42                         3

This table shows that the sample median of 34 appears in 3 out of the 10 possible samples, the sample median of 37 appears in 4 out of the 10 possible samples, and the sample median of 42 appears in 3 out of the 10 possible samples.

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Find the equation of the plane containing all the points equidistant from the points (3,-7,c) and (1,-3,0). Assume that c is a constant.

Answers

The equation of the plane is 2(x-2) + 4(y+5) - c(z-c/2) = 0

How to determine the equation of the plane

From the question, we have the following parameters that can be used in our computation:

points (3,-7,c) and (1,-3,0)

The equation is then calculated as follows:

Start by calculating the midpoint M

M = ( (3+1)/2 , (-7-3)/2 , (c+0)/2 ) = (2,-5,c/2)

Then we need to find the vector parallel to the line, which is given by

v = (1-3, -3-(-7), 0-c) = (-2,4,-c)

Substitute the coordinates of the midpoint and the normal vector into the equation of a plane "ax + by + cz = d"

Where (a,b,c) is the normal vector and d is a constant.

-2(x-2) + 4(y+5) - c(z-c/2) = 0

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Let R be the region bounded by the graph of y = e^(2x-x^2) and the horizontal line y = 2, and let S be the region bounded by the graph of y = e^(2x-x^2) and the horizontal lines y = 1 and y = 2, as shown above.
(a) Find the area of R.
(b) Find the area of S.
(c) Write, but do not evaluate, an integral expression that gives the volume of the solid generated when R is rotated about the horizontal line y = 1.

Answers

The area of R can be calculated using the definite integral of the function y = e^(2x-x^2) between x = 0 and x = 1.

The integral expression is ∫e^(2x-x^2)dx = ∫e^u du = e^u + C = e^(2x-x^2) + C. Evaluating the integral between x = 0 and x = 1 gives the area of R as e^2 - 1.

(b) The area of S can be calculated using the definite integral of the function y = e^(2x-x^2) between x = 0 and x = 1, minus the integral of the function y = 1 between x = 0 and x = 1. The integral expression for S is ∫e^(2x-x^2)dx - ∫1dx = ∫e^u du - x = e^u + C - x = e^(2x-x^2) + C - x. Evaluating the integral between x = 0 and x = 1 gives the area of S as e^2 - 1 - 1.

(c) The volume of the solid generated when R is rotated about the horizontal line y = 1 can be found using the integral expression ∫2πx(e^(2x-x^2) - 1)dx. This expression represents the area of the circular cross-sections of the solid multiplied by 2πx, which is the circumference of the circle. When evaluated between x = 0 and x = 1, this integral gives the volume of the solid generated when R is rotated about the horizontal line y = 1.

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Let X be a binomial random variable with n=75 and p=0.6.
a) What is ?
b) What is ?
c) What is the probability of (≥) , solve this part Without continuity correction and with continuity correction.

Answers

The mean is 45 and the variance is 18

The probability values are 0.951 and 0.937

a) What is μ?

From the question, we have the following parameters that can be used in our computation:

n = 75

p = 0.6

The notation μ is the mean and it is calculated as

μ = n*p

So, we have

= 0.6*0.75

Evaluate

= 45.

b) What is σ²?

The notation σ² is the variance and it is calculated as

σ² = n*p*(1-p)

So, we have

= 75*0.6*(1-0.6)

Evaluate

= 18.

c) What is the probability of P(x≥52)

Without continuity correction

The probability P(x>=52) without continuity correction is represented as

normalcdf(52, μ, σ)

So, we have

normalcdf(52, 45, √18)

Using a calculator, we get:

P(x>=52) = 0.951

With continuity correction.

The probability P(x>=52) with continuity correction is represented as

normalcdf(51.5, μ, σ)

So, we have

normalcdf(51.5, 45, √18)

Using a calculator, we get:

P(x>=52) = 0.937

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Complete question

Let X be a binomial random variable with n = 75 and p = 0.6

a) What is μ?

b) What is σ2?

c) What is the probability of P(x≥52), without continuity correction and with continuity correction.

create an applab turtle project that uses loops and random numbers to create a background and 2 unique shapes.

Answers

A combination of loops and random numbers, a unique background and two unique shapes can be created.

The Applab Turtle project uses a combination of loops and random numbers to create a background and two unique shapes. The program starts by setting the background color of the canvas to a random number from 0 to 255. A for loop is then used to create a series of random circles. The loop is set to run 10 times, and each iteration uses the random number function to set the size of the circle and its position, resulting in a unique pattern of circles on the canvas. Following this, two for loops are used to create two unique shapes. The for loops are set to run a set number of times, and each iteration uses the random number function to set the size and position of the shape. By using a combination of loops and random numbers, a unique background and two unique shapes can be created.

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Dr. Chandler wants to print copies of
his thesis in hardcover book format. He
could use Washington Printing, paying a
setup fee of $41 and $6 for every book
printed. Or, he could go through Fairfax
University, paying an up-front fee of
$32 and $9 per book. For how many
books will the costs be the same? How
much is that?

Answers

On solving the equations y1 = 41 + 6x and y2 = 32 + 9x, it is obtained that -

For 3 books the cost will be the same.

The cost that will be same is $59.

What is an equation?

A mathematical definition of an equation is a claim that two expressions are equal when they are joined by the equals sign ("=").

The cost at Washington Printing is = $41 and $6 per book

The cost at Fairfax University is = $32 and $9 per book

Let the number of books be x.

Let y1 represent the total cost at Washington Printing.

Let y2 represent the total cost at Fairfax University.

So, the equations are -

y1 = 41 + 6x

y2 = 32 + 9x

According to the question -

y1 = y2

41 + 6x = 32 + 9x

Collect all the like terms together -

6x - 9x = 32 - 41

- 3x = - 9

x = 9/3

x = 3

Therefore, the number of books is 3.

The total cost can then be determined by the substituting the value of x in the equations -

41 + 6x = 41 + 6(3) = 41 + 18 = 59

32 + 9x = 32 + 9(3) = 32 + 27 = 59

Therefore, the total cost is $59.

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my grade depends on this, help, ive been stuck on it since im not the brightest

Answers

The domain and the range of the relation shown to the right are given as follows:

Domain: x >= -3.Range: All real values.

The relation is not a function, as there are inputs that are mapped to multiple outputs.

How to obtain the domain and the range of the relation?

The domain of a function is the set that contains all the input values of the function, hence on the graph it is the values of x, thus the domain is of:

x >= -5.

The range of a function is the set that contains all the output values of the function, hence on the graph it is the values of y, thus the domain is of:

All real values.

Tracing a vertical line through the graph of the function, there are values of x for which the graph would be crossed two times, meaning that the relation is not a function.

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leave your answer in exact form (in terms of pi, without spaces). the radius of each circle is r. if two circles are shown, r is the radius of the smaller circle and r is the radius of the larger circle. r

Answers

The small radius =5 cm; and the Long radius =5+4=9 cm.

Area (a + b) = 106 * pi cm^2 (given)

radius of a = x : radius of b = (x + 4)

Area a =[tex]pi * r^2 = pi * x^2\\[/tex]

Area b = [tex]pi * r^2 = pi * (x + 4)^2[/tex]

Area (a + b) = [tex]pi * x^2 + pi * (x + 4)^2[/tex] = 106 * pi cm^2

Area (a + b) =[tex]pi * x^2 + pi * (x^2 + 8x + 16)[/tex] = 106 * pi cm^2

Area (a + b) = pi * ([tex]2x^2[/tex]+ 8x + 16) = 106 * pi cm^2

Area (a + b) = [tex]2x^2 + 8x - 90 = 0[/tex]

2x^2 + 8x - 90 = x^2 + 4x - 45 = 0

x^2 + 4x - 45 = (x + 9)(x -5) = 0

x = 5 or x = -9

Therefore: radius a = 5 cm and radius b = 9 cm

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The question is incomplete

The sum of the areas of the two circles is 106pi cm^2 and the radius of the larger circle is 4cm longer than the radius Of the smaller circle. How could I find the length of the radii?

The number of solutions of (x2 + 1)2 + 2(x2 + 1) - 3 = 0 is equal to
A. 1
B. 2
C. 3
D. 4

Answers

Answer:

I'm pretty sure it's 3. I say that because I get 3 different answers.

x = -1 / 8

x = -0.125

x = -2^3

Those are the answers I got to solve the equation. There also is an answer if I were to rewrite the equation which is... 8x = -1

I hope this helps in any way <3

Step-by-step explanation:

Andrew is creating a rectangular dog run in his back yard. The length of the dog run is 22 feet. The perimeter of the dog run must be at least 52 feet and no more than 88 feet. Use a compound inequality to find the range of values for the width of the dog run. Use
x
when writing your inequality.

Answers

A compound inequality to find the range of values for the width include the following:

x ≥ 8.

x ≤ 44.

How to calculate the perimeter of a rectangle?

Mathematically, the perimeter of a rectangle can be calculated by using this equation;

P = 2(L + x)

Where:

P represents the perimeter of a rectangle.L represents the length of a rectangle.x represents the width of a rectangle.

Note: The length of the dog run is 22 feet.

Since the perimeter of the dog run must be at least 52 feet, an inequality that models the situation is given by:

2(22) + x ≥ 52.

44 + x ≥ 52.

x ≥ 52 - 44

x ≥ 8.

Since the perimeter of the dog run must be no more than 88 feet, an inequality that models the situation is given by:

2(22) + x ≤ 88.

44 + x ≤ 88

x ≤ 88 - 44

x ≤ 44.

Therefore, a compound inequality to find the range of values for the width is 8 ≤ x ≤ 44.

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Erica wants to buy new headphones for sixth graders. She can buy 4 headphones for $48. She needs to buy 25 headphones. How much will that cost?
Help me pls

Answers

Answer:

$300

Step-by-step explanation:

We know

4 headphones = $48

1 headphones = $12

25 headphones = $12 x 25 = $300

Jenny is making jewelry for an arts and crafts show. She Would like to make at least $100 in sales. She estimates that she will sell at most 50 pieces of jewelry. The bracelets that she is selling cost $2 and the necklaces cost $3

Answers

The Inequalities that represent the above situation are => x + y ≤ 50 and 2x + 3y ≥ 100 and the possible combinations are (20, 30) and (30, 20).
[ Graphs are given below ].

Forming Inequalities:  

To form the required inequalities, represent the unknown quantities with variables like x, y,..etc.

In the given problem, we don't know the number of items that Jenny will sell so here we represent them with variables 'x' and 'y'.

And obtain expression according to the condition of the given problem. Since we need to represent them in inequalities use signs like less than, greater than, etc.  

Here we have

Jenny would like to make at least $100 in sales.

She estimates that she will sell at most 50 pieces of jewelry.

The bracelets that she is selling cost $2 and the necklaces cost $3  

Let Jenny sold 'x' bracelets and 'y' necklaces

Number of pieces that Jenny estimated = 50

=> x + y ≤ 50 ----- (1)

Jenny would like to make at least $100 in sales.

=> 2x + 3y ≥ 100 ---- (2)      

Let Jenny sell 20 bracelets and 30 necklaces  

=> 2(20) + 3(30) ≥ 100      

=> 40 + 90 ≥ 100  

=>  130 ≥ 100  [ which is true ]

Let Jenny sell 30 bracelets and 20 necklace

=> 2(30) + 3(20) ≥ 100  

=> 60 + 60 ≥ 100    

=> 120 ≥ 100    

∴ The possible combinations are (20, 30) and (30, 20)

Therefore,

The Inequalities that represent the above situation are => x + y ≤ 50 and 2x + 3y ≥ 100 and the possible combinations are (20, 30) and (30, 20).
[ Graphs are given below ].

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In order to set premiums at profitable levels, insurance companies must estimate how much they will have to pay in claims on cars of each make and model, based on the value of the car and how much damage it sustains in accidents. Let C be a random variable that represents the cost of a randomly selected car of one model to the insurance company. The probability distribution of C is given below. C $0 $1500 $5000 $15000 PC 0.60 0.05 0.13 0.22 The expected value for the above distribution is $4025. Which of the following is the best interpretation of expected value? (In the choices below. "Exp(C)" represents the expected value).
O If the company insures a large number of these cars, they can expect the variability in cost per car to average approximately Exp(C). O If the company Insures a large number of these cars, they can expect the cost per car to average approximately Exp(C). O The maximum cost to the company for insuring this car model is Exp(C) per car. O If the company insures 10 cars of this model, they know they will incur 10xExp(C) in costs. O The company must insure at least Exp(C) of these cars to make a profit

Answers

The expected value for a random variable is defined as the sum of the product of the values and probabilities of the variable.

In this case, the expected value for C is calculated by multiplying each possible value by its probability and adding the products. This is represented mathematically as:

Exp(C) = 0 x 0.60 + 1500 x 0.05 + 5000 x 0.13 + 15000 x 0.22 = 4025

The expected value of C can be interpreted as the average cost that the insurance company can expect to pay out for a randomly selected car of this model. This means that if the company insures a large number of these cars, they can expect the cost per car to average approximately $4025. The expected value does not represent the maximum cost for insuring this car model, or the cost for insuring a set number of cars. Instead, it provides an estimate of what the average cost per car will be.

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An international food festival charges for admission and for each sample of food. Admission and 7 samples cost $9.25. Admission and 9 samples cost $11.25. Write a linear
function rule to model the cost y for any number of samples x.
The linear function rule is y=

Answers

Calculate and subtract for the answer

In a presentation about voter turnout, you are illustrating various data with charts. Which type of information would you present in a pie chart?
A. the decline of voter turnout by county
B. trends in voter turnout over the part 10 years
C. what percentage of the whole population voted
D. how many people voted in various geographic regions on a map

Answers

The percentage of the whole population voted. A pie chart is best used to show the percentage of the whole that different categories represent, in this case the percentage of the whole population that voted.

A pie chart is one of the most commonly used types of data visualization because it provides an easy way to understand the proportional distribution of the data that is being presented. In a presentation about voter turnout, a pie chart would be an excellent way to illustrate what percentage of the whole population voted. Pie charts can be used to show how a whole is divided into different categories, and how much of the whole each category represents. This type of chart is especially useful for presenting data in a visually appealing way and for making comparisons between different categories. In the case of voter turnout, a pie chart would be ideal for showing the percentage of the population that voted, and for comparing the proportions of those who did and did not vote.

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perpendicular to line y=1/2x-8 passes through (7,-6) point slope form

Answers

An equation that is perpendicular to line y = 1/2x - 8 and passes through (7, -6) in point-slope form is y + 6 = -2(x - 7).

What is the point-slope form?

Mathematically, the point-slope form of a straight line can be calculated by using this mathematical expression:

y - y₁ = m(x - x₁)

Where:

m represents the slope.x and y are the points.

From the information provided, an equation of the first line is given by;

y = 1/2x - 8

Therefore, slope (m) = 1/2

In Mathematics, a condition that must be met for two lines to be perpendicular is given by:

m₁ × m₂ = -1

1/2 × m₂ = -1

m₂ = -2

Note: m represents the slope.

At point (7, -6), an equation of the line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - (-6) = -2(x - 7)

y + 6 = -2(x - 7)

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Complete Question:

Write an equation perpendicular to line y = 1/2x - 8 and passes through (7, -6) in point-slope form.

If a dozen eggs (12 eggs) are worth 3 cowry shells, how much would 6 dozen eggs be worth?


A.
36 cowry shells


B.
9 cowry shells


C.
18 cowry shells


D.
15 cowry shells

Answers

Answer:

18 cowry shells

Step-by-step explanation:

1 dozen which is 1(12) eggs = 3 shells

6 dozens will be 6(12) eggs = ?

Cross Multiply

(72 eggs × 3 shells) ÷ 12

= 216 ÷ 12

= 18

explain why 1/12+1/12+1/12+1/12 is the same as 1/3.

Answers

Answer:

Step-by-step explanation:

It is equivalent

4/12

1/3

1x4=4

         _

3x4=12

Please help with with this 9th grade math question

Answers

We can observe from the graph that plan B is less expensive for the interval [0, 4], however plan A is better if you watch 4 or more movies each month.

How do I obtain the cost equations?

We know that Plan A costs $14 per month + $2 each movie, thus the total cost if you see x movies is:

C₁(x) = $14 + $2*x

Plan B costs $10 a month + $3 per movie, therefore the total cost if you see x movies is:

C₂(x) = $10 + $3*x

The graph at the end may now be used to compare expenses. The blue line is C2(x), while the green line is C1(x).

The blue line in the graph may be seen between x = 0 and x = 4.

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In each part, assume the random variable X has a binomial distribution with the given parameters. Compute the probability of the event.
(a) n=3,p=0.7
Pr(X=0)=
(b) n=5,p=0.4
Pr(X=5)=
(c) n=4,p=0.6
Pr(X=1)=
(d) n=5,p=0.4
Pr(X=2)=

Answers

the probabilities are p(0)=0.027 p(5)=0.4 p(1)= 0.243 and p(2)= 0.9

and P(x) = nCx p^x (1 - p)^(n - x) = n! / (x!(n - x)!) * p^x * q^(n - x)

For n = 5, x = 1, p = 0.2:

P(1) = 5! / (1! (5 - 1)!) * 0.2^1 * (1 - 0.2)^(5 - 1) = 5 * 0.2 * 0.4096 = 0.4096

For n = 4, x = 2, q = 0.4:

P(2) = 4! / (2! (4 - 2)!) * (1 - 0.4)^2 * 0.4^(4 - 2) = 6 * 0.36 * 0.16 = 0.3456

For n = 3, x = 0, p = 0.7:

P(0) = 3! / (0! (3 - 0)!) * 0.7^0 * (1 - 0.7)^(3 - 0) = 1 * 1 * 0.027 = 0.027

For n = 5, x = 3, p = 0.1

P(3) = 5! / (3! (5 - 3)!) * 0.1^3 * (1 - 0.1)^(5 - 3) = 10 * 0.001 * 0.81 = 0.0081

For n = 4, x = 2, q = 0.6

P(2) = 4! / (2! (4 - 2)!) * (1 - 0.6)^2 * 0.6^(4 - 2) = 6 * 0.16 * 0.36 = 0.3456

For n = 3, x = 1, q = 0.9

P(1) = 3! / (1! (3 - 1)!) * (1 - 0.9)^1 * 0.9^(3 - 1) = 3 * 0.1 * 0.81 = 0.243

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The probability of an event in a binomial distribution is calculated using the formula Pr(X=x)=C(n,x)p^x(1-p)^(n-x)

(a) Pr(X=0)=C(3,0)p^0(1-p)^3=C(3,0)(0.7)^0(0.3)^3=0.027

(b) Pr(X=5)=C(5,5)p^5(1-p)^0=C(5,5)(0.4)^5(0.6)^0=0.01024

(c) Pr(X=1)=C(4,1)p^1(1-p)^3=C(4,1)(0.6)^1(0.4)^3=0.2304

(d) Pr(X=2)=C(5,2)p^2(1-p)^3=C(5,2)(0.4)^2(0.6)^3=0.3456

The probability of an event in a binomial distribution is calculated using the formula Pr(X=x)=C(n,x)p^x(1-p)^(n-x), where n is the number of trials, p is the probability of success, x is the number of successes, and C(n,x) is the number of combinations of n things taken x at a time. To calculate each of the probabilities given above, we first calculate the combinations C(n,x), followed by the probabilities for success and failure, and then multiply these values together to get the probability of the event. For example, in part (a), we calculate C(3,0)=1, p^0=1, and (1-p)^3=0.027, and the probability of the event Pr(X=0)=1*1*0.027=0.027.

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The point (0, 0) is a solution to which of these inequalities?​

Answers

The point (0,0) is a solution of (y-5<3x-4)

HELP ME OUT PLEASE!!!!!!!

What is the domain of the function shown in the graph below?​

Answers

Answer:

X ≥ -4

Step-by-step explanation:

Remember domain only focuses on the X values, so we can immediately rule out the answers containing Y. We can observe that the graph has a closed circle over x=-4. This tells us it will be included and so we must have "≥" in the answer choice. By simple process of elimination A, the first answer choice is the correct answer.

Also note that it would be read as "X is greater than or equal to negative 4," which is exactly what our graph depicts. The second choice, which looks like it could be correct at first would be read as "X is greater than negative 4," which excludes negative 4 in the answer. We need that negative 4 for it to be correct.

Estimate the product by rounding the numbers so that the resulting arithmetic can easily be performed by hand or in
your head. Then use a calculator to perform the computation. How reasonable is your estimate when compared to
the actual answer?
17% of 279,394
-The estimated product is. (Type an integer.) I need help for this math please

Answers

The value of 17% of 279,394 is 47496.98.

What is Percentage?

percentage, a relative value indicating hundredth parts of any quantity.

We have to find the value of 17% of 279,394

Convert 17% to decimal value by dividing with 100

17/100=0.17

Now multiply 0.17 with 279394

0.17×279394

47496.98

Hence, the value of 17% of 279,394 is 47496.98.

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f(x) is a direct variation function
f(3)= 12
f(x)= ?
f(2)= ?

Answers

The function f(x) will be : f(x) = 4x and f(2) = 8.

What are algebraic expressions?

In mathematics, an expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping to help determine the order of operations and other aspects of logical syntax.

Given that f(x) is a direct variation function.

Direct variation of {y} with {x} means that as {x} increases, {y} increases uniformly with it. Mathematically -

{K} = y/x = constant

Scale factor {K} is a dimensionless value that indicates the constant ratio value indicating direct variation.

It is given that -

f(3) = 12

We can write the slope of f(x) as -

m = (12 - 0)/(3 - 0)

m = 12/3

m = 4

So, f(x) will be -

f(x) = 4x

f(2) will be -

f(2) = 8

Therefore, the function f(x) will be : f(x) = 4x and f(2) = 8.

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D. Apply Your Knowledge (See Ex 5) 10. Suppose a football is kicked from the ground and its height, h, in feet above the ground is given by h = -3.9t² + 15.6t. The time, t, represents the number of seconds after the ball is kicke At what time does the football hit the ground? SHOW YOUR WORK and include units of measurement.​

Answers

Answer:

To solve for the time when the football hits the ground, we need to set h = 0 and solve for t. We can do this using the quadratic equation: 0 = -3.9t² + 15.6t. Solving for t results in t = 0 or t = 4. Therefore, the football hits the ground at t = 0 seconds or 4 seconds after it is kicked. The units of measurement for time are seconds.

Choose the term that describes the slope of the line of a graph representing the data in the table.
The slope of a line graphed to represent the volume of water in a pool over time would be described as

Answers

Answer:

Answer is Negative

Step-by-step explanation:

picture at the bottom provides proof.

12 Select the correct answer from each drop-down menu. Graph shows two triangles plotted on a coordinate plane. One triangle is at A (minus 4, 4), B (minus 8, 2), and C (minus 6, minus 6). Another triangle is at A prime (4, minus 2), B prime (2, 2), and C prime (6, 0). A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC onto ∆A′B′C′ is a followed by a .

Answers

None of the transformations followed between the two given triangles. None of the options are correct.

What are Similar triangles?

Similar triangles are those triangles that have similar properties,i.e. angles and proportionality of sides.

Here,
The graph shows two triangles plotted on a coordinate plane. One triangle is at A (-4, 4), B (-8, 2), and C (-6, -6). Another triangle is at A '(4, -2), B '(2, 2), and C '(6, 0).

As we can see in the graph, the triangles are completely different, so the transformation of either of the ΔABC to ΔA'B'C' or ΔA'B'C' to ΔABC is not possible.

Thus, None of the transformations followed between the two given triangles. None of the options are correct.

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