I need help on this 20 points

I Need Help On This 20 Points

Answers

Answer 1

Answer:

4^15

Step-by-step explanation:

We know a^b^c = a^(b*c)

4^3^5

4^(3*5)

4^15


Related Questions

Two sides of a triangle have lengths 13 m and 19 m. The angle between them is increasing at a rate of 2°/min. How fast is the length of the third side increasing when the angle between the sides of fixed length is 60°? (Round your answer to three decimal places.)

Answers

Answer:

The third side is increasing at an approximate rate of about 0.444 meters per minute.

Step-by-step explanation:

We are given a triangle with two sides having constant lengths of 13 m and 19 m. The angle between them is increasing at a rate of 2° per minute and we want to find the rate at which the third side of the triangle is increasing when the angle is 60°.

Let the angle between the two given sides be θ and let the third side be c.

Essentially, given dθ/dt = 2°/min and θ = 60°, we want to find dc/dt.

First, convert the degrees into radians:

[tex]\displaystyle 2^\circ \cdot \frac{\pi \text{ rad}}{180^\circ} = \frac{\pi}{90}\text{ rad}[/tex]

Hence, dθ/dt = π/90.

From the Law of Cosines:

[tex]\displaystyle c^2 = a^2 + b^2 - 2ab\cos \theta[/tex]

Since a = 13 and b = 19:

[tex]\displaystyle c^2 = (13)^2 + (19)^2 - 2(13)(19)\cos \theta[/tex]

Simplify:

[tex]\displaystyle c^2 = 530 - 494\cos \theta[/tex]

Take the derivative of both sides with respect to t:

[tex]\displaystyle \frac{d}{dt}\left[c^2\right] = \frac{d}{dt}\left[ 530 - 494\cos \theta\right][/tex]

Implicitly differentiate:

[tex]\displaystyle 2c\frac{dc}{dt} = 494\sin\theta \frac{d\theta}{dt}[/tex]

We want to find dc/dt given that dθ/dt = π/90 and when θ = 60° or π/3. First, find c:

[tex]\displaystyle \begin{aligned} c &= \sqrt{530 - 494\cos \theta}\\ \\ &=\sqrt{530 -494\cos \frac{\pi}{3} \\ \\ &= \sqrt{530 - 494\left(\frac{1}{2}\right)} \\ \\&= \sqrt{283\end{aligned}[/tex]

Substitute:

[tex]\displaystyle 2\left(\sqrt{283}\right) \frac{dc}{dt} = 494\sin\left(\frac{\pi}{3}\right)\left(\frac{\pi}{90}\right)[/tex]

Solve for dc/dt:

[tex]\displaystyle \frac{dc}{dt} = \frac{494\sin \dfrac{\pi}{3} \cdot \dfrac{\pi}{90}}{2\sqrt{283}}[/tex]

Evaluate. Hence:

[tex]\displaystyle \begin{aligned} \frac{dc}{dt} &= \frac{494\left(\dfrac{\sqrt{3}}{2} \right)\cdot \dfrac{\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{\dfrac{247\sqrt{3}\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{247\sqrt{3}\pi}{180\sqrt{283}} \\ \\ &\approx 0.444\text{ m/min}\end{aligned}[/tex]

The third side is increasing at an approximate rate of about 0.444 meters per minute.

9514 1404 393

Answer:

  0.444 m/min

Step-by-step explanation:

I find this kind of question to be answered easily by a graphing calculator.

The length of the third side can be found using the law of cosines. If the angle of interest is C, the two given sides 'a' and 'b', then the third side is ...

  c = √(a² +b² -2ab·cos(C))

Since C is a function of time, its value in degrees can be written ...

  C = 60° +2t° . . . . . where t is in minutes, and t=0 is the time of interest

Using a=13, and b=19, the length of the third side is ...

  c(t) = √(13² +19² -2·13·19·cos(60° +2t°))

Most graphing calculators are able to compute a numerical value of the derivative of a function. Here, we use the Desmos calculator for that. (Angles are set to degrees.) It tells us the rate of change of side 'c' is ...

  0.443855627418 m/min ≈ 0.444 m/min

_____

Additional comment

At that time, the length of the third side is about 16.823 m.

__

c(t) reduces to √(530 -494cos(π/90·t +π/3))

Then the derivative is ...

  [tex]c'(t)=\dfrac{494\sin{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}\right)}\cdot\dfrac{\pi}{90}}{2\sqrt{530-494\cos{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}}}\right)}}}\\\\c'(0)=\dfrac{247\pi\sqrt{3}}{180\sqrt{283}}\approx0.443855...\ \text{m/min}[/tex]

A composite figure is made up of one simple figure.
True or
False

Answers

Answer:

False

Step-by-step explanation:

A composite figure would be any irregular shapes and can be made up of multiple shapes

Please find the missing ? Explanation need it

Answers

Answer:

the answer is 3.162

Step-by-step explanation:

is the sequence 1/6, 1/2, 3/2,9/2 arithmetic, or geometric

Answers

Answer:

geometric

Step-by-step explanation:

SAT scores are normally distributed with a mean of 1,500 and a standard deviation of 300. An administrator at a college is interested in estimating the average SAT score of first-year students. If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample? Make sure to give a whole number answer.

Answers

Answer:

The administrator should sample 968 students.

Step-by-step explanation:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.88}{2} = 0.06[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.06 = 0.94[/tex], so Z = 1.555.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Standard deviation of 300.

This means that [tex]n = 300[/tex]

If the administrator would like to limit the margin of error of the 88% confidence interval to 15 points, how many students should the administrator sample?

This is n for which M = 15. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]15 = 1.555\frac{300}{\sqrt{n}}[/tex]

[tex]15\sqrt{n} = 300*1.555[/tex]

Dividing both sides by 15

[tex]\sqrt{n} = 20*1.555[/tex]

[tex](\sqrt{n})^2 = (20*1.555)^2[/tex]

[tex]n = 967.2[/tex]

Rounding up:

The administrator should sample 968 students.

1. Given the line of best fit y = 6.2x + 13, what is the residual for the point (10,80)? (1 pt)
A. 75
B. 5
C. 499
D. 55

Answers

Answer:

c

Step-by-step explanation:

The residual for the point line (10,80) is option A 75. at the given line which best fits y = 6.2x + 13.

What is a straight line graph?

The graph follows a straight line equation shows a straight line graph.

equation of a straight line is   y=mx+cy represents vertical line y-axis.x represents the horizontal line x-axis.     m is the slope of the line

            slope(m)=tan∅=y axis/x axis.

c represents y-intercepts (it is the point at which the line cuts on the y-axis)

Straight line graphs show a linear relationship between the x and y values.

solving the equation:-

y = 6.2x + 13

putting value of X = 10

Y = 6.2 * 10 + 13

Y = 62 + 13

Y = 75

Hence the line best fit = 75.

Learn more about equation of a line here:-https://brainly.com/question/18831322

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Suppose the variable x is represented by a standard normal distribution. What is the probability of x > 0.3 ? Please specify your answer in decimal terms and round your answer to the nearest hundredth (e.g., enter 12 percent as 0.12).

Answers

Answer: 0.38

Step-by-step explanation:

Since the variable x is represented by a standard normal distribution, the probability of x > 0.3 will be calculated thus:

P(x > 0.3)

Then, we will use a standard normal table

P(z > 0.3)

= 1 - p(z < 0.3)

= 1 - 0.62

= 0.38

Therefore, p(x > 0.3) = 0.38

The probability of x > 0.3 is 0.38.

Social media is popular around the world. Statista provides estimate of the number of social media users in various countries in as well as the projections for . Assume that the results for surveys in the United Kingdom, China, Russia, and the United States are as follows.

Use Social Media United Kingdom China Russia United States
Yes 480 215 343 640
No 320 285 357 360

Required:
a. Conduct a hypothesis test to determine whether the proportion of adults using social media is equal for all four countries. What is the p-value? Using a .05 level of significance, what is your conclusion?
b. What are the sample proportions for each of the four countries? Which country has the largest proportion of adults using social media?
c. Using a 0.05 level of significance, conduct multiple pairwise comparison tests among the four countries. What is your conclusion?

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

The data table :

Use of SM _UK _China _ Russia _US _ col total

Yes ______480 __215 ___343 __640 _ 1678

No _______320 _ 285 ___357__ 360 _ 1322

Row Total__ 800 _500 __ 700_ 1000_ 3000

H0 : p1 = p2 = p3 = p4

H1 : p1 ≠ p2 ≠ p3 ≠ p4

Test statistic :

χ² = Σ(observed - Expected)² / Expected

Expected value of each cell = (Row total * column total) / N

N = grand total

Expected Values:

447.467 _279.667 _ 391.533 _ 559.333

352.533 _ 220.333 _ 308.467 _ 440.667

χ²=(2.36536+14.9527+6.01605+11.6337+3.00232 18.9793+7.63611+14.7665) = 79.352

Degree of freedom, df = (row-1)*(column-1) = (2 - 1) * (4 - 1) = 1 * 3 = 3

Using the Pvalue from Chisquare calculator :

Pvalue(79.352, 3) = 0.00000000001

Decision region :

Reject H0 ; If Pvalue < α

α = 0.05

Since 0.000000001 < 0.05 ; Reject H0 and conclude that not all population proportion are equal.

Sample proportion :

Phat = number of yes, x / total

For UK, Phat = 480/800 = 0.6

For China , Phat = 215/500 = 0.43

For Russia , Phat = 343/700 = 0.49

For US, Phat = 640/1000 = 0.64

Determine whether or not the given procedure results in a binomial distribution. If not, identify which condition is not met. Spinning an American roulette wheel 8282 times and recording the number the ball lands on.

Answers

Answer:

No, binomial distribution cannot be applied.

Step-by-step explanation:

We known that a Binomial Distribution depends on provided experiment , a binomial distribution have only 2 outcomes. For example, when we flip a coin in the air, then the possible outcomes are Head and Tail.

But in the context, an American roulette wheel has [tex]37[/tex] outcomes. It means when we spin the American Roulette wheel, ball may lend on any of the numbers between 0 to 36. So there are more than [tex]2[/tex] outcomes.

Therefore, binomial distribution can not be applied here.

Ivan caught a total of 7 2/5 pounds of fish one day. Of the fish caught, 4 5/8 pounds were sea bass and the rest were mackerel. He gave away 1 7/8 pounds of mackerel. How many pounds of mackerel did he have left.

Answers

Given:

Total fish (Sea bass and mackerel) = [tex]7\dfrac{2}{5}[/tex] pounds

Sea bass = [tex]4\dfrac{5}{8}[/tex] pounds

He gave away [tex]1\dfrac{7}{8}[/tex] pounds of mackerel.

To find:

The remaining mackerel.

Solution:

We know that,

Mackerel = Total fish - Sea bass

[tex]\text{Mackerel}=7\dfrac{2}{5}-4\dfrac{5}{8}[/tex]

[tex]\text{Mackerel}=\dfrac{37}{5}-\dfrac{37}{8}[/tex]

[tex]\text{Mackerel}=\dfrac{296-185}{40}[/tex]

[tex]\text{Mackerel}=\dfrac{111}{40}[/tex]

He gave away [tex]1\dfrac{7}{8}[/tex] pounds of mackerel. So, the remaining mackerel is:

[tex]\text{Remaining Mackerel}=\dfrac{111}{40}-1\dfrac{7}{8}[/tex]

[tex]\text{Remaining Mackerel}=\dfrac{111}{40}-\dfrac{15}{8}[/tex]

[tex]\text{Remaining Mackerel}=\dfrac{111-75}{40}[/tex]

[tex]\text{Remaining Mackerel}=\dfrac{36}{40}[/tex]

[tex]\text{Remaining Mackerel}=\dfrac{9}{10}[/tex]

Therefore, the remaining Mackerel is [tex]\dfrac{9}{10}[/tex] pounds or 0.9 pounds.

Answer:

The amount of Mackerel left is 9/10.

Step-by-step explanation:

total fish = 7 2/5 pounds

sea bass = 4 5/8

The amount of mackerel =

[tex]7\frac{2}{5}-4\frac{5}{8}\\\\=\frac{37}{5}-\frac{37}{8}\\\\=\frac{296-185}{40}\\\\=2 \frac{31}{40}[/tex]

Mackerel left =

[tex]2 \frac{31}{40}-1\frac{7}{8}\\\\= \frac{111}{40}-\frac{15}{8}\\\\=\frac{111-75}{40}\\\\=\frac{36}{40}\\\\=\frac{9}{10}[/tex]

Joe nas to take two quizzes tomorrow. He nas only enough time to study one of them. • The science quiz has 7 true-or-false questions. • The English quiz has 3 multiple-choice questions. Joe calculates the probability that he will get each question correct by guessing. ?​

Answers

Answer:

C.

Step-by-step explanation:

Science questions are T/F. That's .5 or [tex]\frac{1}{2}[/tex] chance to get it right.

7 questions. Each with a [tex]\frac{1}{2}[/tex].

That's [tex](\frac{1}{2})^{7}[/tex]  

[tex](\frac{1}{2})^{7}[/tex] = [tex]\frac{1}{128}[/tex] = .0078 = .008 rounded

English questions are multiple choice. 4 choices. That's .25 or [tex]\frac{1}{4}[/tex]

3 questions. Each [tex]\frac{1}{4}[/tex]

That's [tex](\frac{1}{4})^{3}[/tex]

[tex](\frac{1}{4})^{3}[/tex] = [tex]\frac{1}{64}[/tex] = .0156 = .016 rounded

The probability of getting all questions correct is 0.004 which is lower than for science (0.016).

Science questions are said to have a 6 out of 6 correct answer range and a 0.5 chance of being answered properly.

So, P(6) = 0.5⁶

P(6) = 0.016

We are informed that there are 4 out of 4 correct answers for English, with a 0.25 chance of getting it right.

Thus; P(4) = 0.25⁴ = 0.004

Thus, we conclude that they will have to study English.

Learn more about Probability here:

brainly.com/question/251701

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What is the distance between (8, -3) and (4, - 7)?
Choose 1 answer:

Will GIVE YOU BRAINLIEST

Answers

Step-by-step explanation:

We'll find the distance using the all-famous "Distance Formula." You'll probably come across it quite a bit, so it's best to have it written down somewhere.

The Distance Formula: [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

Our points are (8, -3) and (4, -7), so we'll plug in those numbers accordingly.

For reference:

x2 = 4

x1 = 8

y2 = -7

y1 = -3

The calculation:

(substitute)

[tex]\sqrt{(4-8)^2+((-7)-(-3))^2 }[/tex]

(simplify)

[tex]\sqrt{(-4)^2+(-4)^2 }[/tex]

(square things)

[tex]\sqrt{16+16 }[/tex]

(add)

[tex]\sqrt{32}[/tex]

Answer:

[tex]\sqrt{32}[/tex]

Answer:

[tex]\boxed {\boxed {\sf C. \sqrt{32}}}[/tex]

Step-by-step explanation:

The distance between 2 points can be determined with the following formula.

[tex]d= \sqrt{(x_2-x_1)^2+ (y_2-y_1)^2[/tex]

In this formula, (x₁, y₁) and (x₂, y₂) are the 2 points. We want to find the distance between the points (8, -3) and (4, -7). If we match the value with its corresponding variable, then we see:

x₁= 8 y₁= -3 x₂= 4 y₂ = -7

Substitute the values into the formula.

[tex]d= \sqrt{(4-8)^2+(-7--3)^2[/tex]

Solve inside the parentheses.

(4-8) = -4 (-7 - -3) = (-7+3)= -4

[tex]d= \sqrt {(-4)^2+(-4)^2[/tex]

Solve the exponents.

(-4)² = -4 * -4 = 16

[tex]d= \sqrt {16+16[/tex]

Add.

[tex]d= \sqrt {32}[/tex]

This radical can be simplified, but since it is an answer choice, we can leave it as is.

The distance between the points (8, -3) and (4, -7) is √32 and choice C is correct.

Round to the nearest whole number.
6.4

Answers

Answer:

6

Step-by-step explanation:

Therefore, the number 6.4 rounded to the nearest whole number is 6. * If the number you are rounding off is followed by 0,1,2,3,4, round the number down. To find 6.4 rounded to the nearest whole number.

Please Mark me brainliest

6.4 rounded to the nearest whole number is 6.

35 POINTS HELP in the figure above the circle has center O and radius 6 what is the length of arc acb

Answers

Answer:

9.425 or 3π

Step-by-step explanation:

arc length = 2πr(θ/360)

The angle is 90˚ as indicated by the square symbol.

ABC = 2π6(90/360) = 9.425 or 3π

Find the missing length indicated

Answers

Answer:

x = 960

Step-by-step explanation:

x=√{576×(576+1024)}

or, x = √(576×1600)

or, x = √576×√1600

or, x = 24×40

or, x = 960

Answered by GAUTHMATH

Answer:

Step-by-step explanation:

In an assembly-line production of industrial robots, gearbox assemblies can be installed in one minute each if holes have been properly drilled in the boxes and in ten minutes if the holes must be redrilled. Twenty-four gearboxes are in stock, 6 with improperly drilled holes. Five gearboxes must be selected from the 24 that are available for installation in the next five robots. (Round your answers to four decimal places.) (a) Find the probability that all 5 gearboxes will fit properly. (b) Find the mean, variance, and standard deviation of the time it takes to install these 5 gearboxes.

Answers

Answer:

The right answer is:

(a) 0.1456

(b) 18.125, 69.1202, 8.3139

Step-by-step explanation:

Given:

N = 24

n = 5

r = 7

The improperly drilled gearboxes "X".

then,

⇒ [tex]P(X) = \frac{\binom{7}{x} \binom {17}{5-x}}{\binom{24}{5}}[/tex]

(a)

P (all gearboxes fit properly) = [tex]P(x=0)[/tex]

                                               = [tex]\frac{\binom{7}{0} \binom{17}{5}}{\binom{24}{5}}[/tex]

                                               = [tex]0.1456[/tex]

(b)

According to the question,

[tex]X = 91+5[/tex]

Mean will be:

⇒ [tex]\mu = E(x)[/tex]

       [tex]=E(91+5)[/tex]

       [tex]=9E(1)+5[/tex]

       [tex]=9.\frac{nr}{N}+5[/tex]

       [tex]=9.\frac{5.7}{24} +5[/tex]

       [tex]=18.125[/tex]

Variance will be:

⇒ [tex]\sigma^2=Var(X)[/tex]

         [tex]=V(9Y+5)[/tex]

         [tex]=81.V(Y)[/tex]

         [tex]=81.n.\frac{r}{N}.\frac{N-r}{N}.\frac{N-n}{N-1}[/tex]

         [tex]=81.5.\frac{7}{24}.\frac{24-7}{24}.\frac{24-5}{24-1}[/tex]

         [tex]=69.1202[/tex]

Standard deviation will be:

⇒ [tex]\sigma = \sqrt{69.1202}[/tex]

       [tex]=8.3139[/tex]      

A physicist examines 10 water samples for iron concentration. The mean iron concentration for the sample data is 0.711 cc/cubic meter with a standard deviation of 0.0816. Determine the 90% confidence interval for the population mean iron concentration. Assume the population is approximately normal.
Step 1 of 2: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Step 2 of 2: Construct the 90% confidence interval. Round your answer to three decimal places. Lower endpoint? Upper endpoint?

Answers

Answer:

Poggers

Step-by-step explanation:

Marnie just finished setting herself up at a cozy spot at the airport. Her laptop is ready, phone within reach, and her papers are organized, but now, she's hungry. What should she do? a) Take her phone and laptop with her to get something to eat b) Leave her stuff, but get a snack really quickly O c) Put her coat over her laptop to hide it and go get a snack O d) Ask the person next to her to watch her stuff

Answers

Answer:

a) someone will steal her stuff in any other situation even if a stranger watches it

exchange rate for rand is 7 for $1 how any dollars would u receive is u exchange 21 rand

Answers

Answer:

$3

Step-by-step explanation:

7 rands for $1

7×3=21

21 rands for $3

Answer:

$3

Step-by-step explanation:

7 rand = 1 dollar

Divide both sides by 7 rand.

1 = (1 dollar)/(7 rand)

Notice that the fraction (1 dollar)/(7 rand) equals 1, so multiplying by it will not change the amount, just the units.

21 rand * (1 dollar)/(7 rand) =

= 21/7 dollar

= 3 dollar = $3

A perfect correlation is denoted by:

A. +1.0 and -1.0

B. +1.00

C. -1.00

D. .50

Answers

A perfect correlation is denoted by:

A. +1.0 and -1.0

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly targeted and destroyed, what is the probability that no more than 11 vessel transporting nuclear weapons was destroyed

Answers

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

Fleet of 18 means that [tex]N = 18[/tex]

9 are carrying nuclear weapons, which means that [tex]k = 9[/tex]

9 are destroyed, which means that [tex]n = 9[/tex]

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

In which

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021[/tex]

[tex]P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687[/tex]

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

PLEASE HELP LOOK AT PICTURE

Answers

the answer is option 2. try subbing in the values of each of the X values and you’ll discover that option 2 is correct since the answers match with the Y values

6( n - 2) in word form please c:

Answers

Answer:

six in parenthesis n minus two

Step-by-step explanation:

2 ways could be:

A. N minus two then multiply by six

B. Six times parentheses n minus two end parentheses

The average score of all golfers for a particular course has a mean of 65 and a standard deviation of 4.5 . Suppose 81 golfers played the course today. Find the probability that the average score of the golfers exceeded 66 . Round to four decimal places.

Answers

Answer:

Answer:

The probability that the average score of the 49 golfers exceeded 62 is 0.3897

Step-by-step explanation:

Which of the following statements best describes the effect of replacing the graph of y = f(x) with the graph of y = f(x) − 11? The graph of y = f(x) will shift up 11 units. The graph of y = f(x) will shift right 11 units. The graph of y = f(x) will shift left 11 units. The graph of y = f(x) will shift down 11 units.

Answers

Answer:

The graph of y = f(x) will shift down 11 units

Step-by-step explanation:

the figure below is made up of a square, a quadrant and a semicircle. the length of the square is 12cm. find the area of the shaded parts.

Answers

Answer:

P=2pi×r

P=2×12pi=24pi

24pi÷4=6pi

6pi÷2=3pi

p=2×6×pi

p=12pi

12pi÷2=6pi

permiter=3pi+6pi+12=40.27

that is for part a

Present value takes ____________.
A. Compounding rate.
B. Discounting rate.
C. Inflation rate.
D. Deflation rate​

Answers

C. Inflation rate would be correct

2x+3=60 thì x băng bao nhieu

Answers

Answer:

x=57/2

Step-by-step explanation:

2x+3=60

<=> 2x=57

=> x=57/2

I need help with C,D,E,F,G thank you

Answers

Answer:

D = 120 Degrees ,  E : x = 14 , F: <JHK = 21, G: Summplementary Angle is 96 Degrees

Step-by-step explanation:

4X+2X = 180

6X=180

X=30

<ABD = 4X = 4(30) = 120

D= 120 degrees
If I am correct

The five number summary of a dataset is given as
0, 4, 12, 14, 20
An observation is considered an outlier if it is below _______
An observation is considered an outlier if it is above _______


The five number summary of a dataset is given as
2, 8, 14, 18, 20
An observation is considered an outlier if it is below _______
An observation is considered an outlier if it is above _______

.
.

Answers

Given:

The five number summary of two data sets are given as:

a) 0, 4, 12, 14, 20

b) 2, 8, 14, 18, 20

To find:

The range for the outliers.

Solution:

We know that,

An observation is considered an outlier if it is below [tex]Q_1-1.5(IQR)[/tex]

An observation is considered an outlier if it is above [tex]Q_3+1.5(IQR)[/tex]

Where, IQR is the interquartile range and [tex]IQR=Q_3-Q_1[/tex].

The five number summary of two data sets are given as:

0, 4, 12, 14, 20

Here, [tex]Q_1=4[/tex] and [tex]Q_3=14[/tex].

Now,

[tex]IQR=14-4[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-1.5(10),14+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-15,14+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-11,29][/tex]

An observation is considered an outlier if it is below -11.

An observation is considered an outlier if it is above 29.

The five number summary of two data sets are given as:

2, 8, 14, 18, 20

Here, [tex]Q_1=8[/tex] and [tex]Q_3=18[/tex].

Now,

[tex]IQR=18-8[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-1.5(10),18+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-15,18+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-7,33][/tex]

An observation is considered an outlier if it is below -7.

An observation is considered an outlier if it is above 33.

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