In which quadrant does the point (13 , 20) lie? A. Quadrant III B. Quadrant I C. Quadrant IV D. Quadrant II

Answer:

1. Eleven plus t

2. 7 times r times s time t

3. t minus seven

4. ten times n

5. fifteen times y

6. four times x

7. a plus b

8. fourteen times x plus 3 times y

Step-by-step explanation:

Hope this helps!

Answer:

1, eleven plus t

2, seven rst

3,t-17

........................

Answer:

3 / (3t+4) is the answer

Answer:

Make it an improper fraction and multiply by 100

Answer:

Well a percent means out of a hundred

And a mixed number is

x e/y (example)

Now we know the whole number is already 1 and above so we know that’s already a 100%

Now we just need to add the other fraction to the 100%.

Thats it!

OR you can do convert the mixed number into an improper fraction.

From there make a proportion of the improper fraction equaling x/100

Now solve the proportion by cross multiplying.

Solve for x

Answer:

y = (x - 1)(x - 3)

y = (x + 2)^2

Step-by-step explanation:

3)

Has roots at x = {1, 3}

y = (x - 1)(x - 3)

4)

Has double root at x = -2

y = (x + 2)^2

Answer:

[tex]t_4 = 20[/tex]

Step-by-step explanation:

The base case in the recursive function are:

[tex]t_1 = 1[/tex]

[tex]t_2 = 2[/tex]

The recursive case is equal to:

[tex]t_n = 2t_{n-1} + 3t_{n-2}[/tex]

So replace [tex]t_n[/tex] for [tex]t_4[/tex]:

[tex]t_4 = 2t_{3} + 3t_{2}[/tex]

In the new expression [tex]t_2[/tex] is a base case so you don't have to worry for that part, but [tex]t_3[/tex] is still the recursive case so evaluate again in [tex]t_n[/tex]

[tex]t_3 = 2t_{2} + 3t_{1}[/tex]

[tex]t_2[/tex] and [tex]t_1\\[/tex] are define as base cases so you replace for it's numbers:

[tex]t_3 = 2(2) + 3(1) = 7[/tex]

Now return to [tex]t_4[/tex] and replace for the new values:

[tex]t_4 = 2(7) + 3(2) = 14 + 6 = 20[/tex]

So the final answer is 20

The kite is a quadrilateral that has two pairs of equal adjacent sides and

one of equal opposite angles.

5. The two column proof is presented as follows;

Statement [tex]{}[/tex]                            Reason

[tex]\overline{AB}[/tex] = [tex]\overline{BC}[/tex]     [tex]{}[/tex]                           Given

[tex]\overline{AB}[/tex] ≅ [tex]\overline{BC}[/tex]     [tex]{}[/tex]                          Definition of congruency

[tex]\overline{AD}[/tex] = [tex]\overline{CD}[/tex]     [tex]{}[/tex]                           Given

[tex]\overline{AD}[/tex] ≅ [tex]\overline{CD}[/tex]     [tex]{}[/tex]                          Definition of congruency

[tex]\overline{BD}[/tex] ≅ [tex]\overline{BD}[/tex]     [tex]{}[/tex]                          By reflexive property

ΔABD ≅ ΔBDC    [tex]{}[/tex]                   By Side-Side-Side, SSS congruency postulate

∠ABC = ∠ABD + ∠CBD      [tex]{}[/tex]    Angle addition postulate

∠ABD ≅ ∠CBD     [tex]{}[/tex]                  CPCTC

∠ABD = ∠CBD     [tex]{}[/tex]                   Definition of congruency

[tex]\overline{BD}[/tex] is a bisector of  ∠ABC    [tex]{}[/tex] Definition of angle bisector

∠ADC = ∠ABD + ∠CBD      [tex]{}[/tex]     Angle addition postulate

∠ABD ≅ ∠CBD     [tex]{}[/tex]                  CPCTC

∠ABD = ∠CBD     [tex]{}[/tex]                   Definition of congruency

Therefore;

[tex]\overline{BD}[/tex] is a bisector of ∠ADC     [tex]{}[/tex] Definition of angle bisector

CPCTC is the acronym for Congruent Parts of Congruent Triangles are Congruent

6. The two column proof is presented as follows;

Statement [tex]{}[/tex]                          Reason

∠ABD ≅ ∠CBD  [tex]{}[/tex]           CPCTC (question 5)

[tex]\overline{AB}[/tex] = [tex]\overline{BC}[/tex]     [tex]{}[/tex]                  Given

[tex]\overline{BM}[/tex] ≅ [tex]\overline{BM}[/tex]      [tex]{}[/tex]              Reflexive property

ΔABM ≅ ΔCBM      [tex]{}[/tex]      According to Side-Angle-Side, SAS congruency rule

[tex]\overline{AM}[/tex] ≅ [tex]\overline{CM}[/tex]      [tex]{}[/tex]               CPCTC

[tex]\overline{AM}[/tex] = [tex]\overline{CM}[/tex]    [tex]{}[/tex]                  Definition of congruency

[tex]\overline{AC}[/tex] = [tex]\overline{AM}[/tex] + [tex]\overline{CM}[/tex]    [tex]{}[/tex]        Segment addition postulate

[tex]\overline{AC}[/tex] = [tex]\overline{AM}[/tex] + [tex]\overline{AM}[/tex] =  2·[tex]\overline{AM}[/tex] [tex]{}[/tex] Substitution property of equality

[tex]\overline{AM}[/tex] = 0.5·[tex]\overline{AC}[/tex]    [tex]{}[/tex]        Division property of equality

M divides [tex]\overline{AC}[/tex] to two   [tex]{}[/tex]  Definition

M is midpoint of [tex]\overline{AC}[/tex]   [tex]{}[/tex]   Definition of midpoint

Learn more here:

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Answer:

Step-by-step explanation:

300(0.70) + 200(0.95) = (300 + 200)x

                             400 = 500x

                                  x = 0.80

                                          80%

Answer: 1/3

Step-by-step explanation:

Answer:David bought an identical mailbox for $ 19.95 at a different store.

Step-by-step explanation:

David bought an identical mailbox for $ 19.95 at a different store. you can buy a same mailbox but for different prices you have 22 dollars you have a 110 percent off you dont have enough

Answer:

Area = πr²

Circumference = 2πr

You can use pie as both 22/7 Or 3.14

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

No

But it us Near though

Step-by-step explanation:

9/15 or 3/5 =60%

Answer= -50

a= 5

b= 30

z= 25

c= -50

Answer:

$499

Step-by-step explanation:

Since the price was reduced from an amount which is $2,498. You have to take that amount and the other amount which is $1999 and subtract them both.

2489-1999=499

(When you get your answer,make sure to add the dollar sign.)

The price was reduced by $499.

Answer:

Step-by-step explanation:

Let x be the lowest number of the four

x  + (x + 7) + (x + 14) + (x + 21) = 6

4x + 42 = 6

4x = -36

x = -9

-9 + 7 = - 2

-9 + 14 = 5

-9 + 21 = 12

-9. -2, 5, 12

Answer:

4th option

Step-by-step explanation:

2x-5 means yo have to take minus 5 twice. So you start from 0 and jump back 5 steps twice. So 4

Answer:

? = 32

Step-by-step explanation:

Because 8 times 4=32 plus 2 = 34 and therefore t=4 8 times 4 again plus 2 = 34 so 32 plus 2 =34

Plz give brainliest

Answer:

$12,845.80

Step-by-step explanation:

take the first number and go +7%. repeat four times

hope this helps :-)

Answer:

2−4−12

Step-by-step explanation:

Answer:

Area: (2x - 7) * (3*2 + 4x)

         (2x - 7) * (6 + 4x)

                 8x-42

Perimeter: 2(2x - 7) + 2(3*2 + 4x)

Step-by-step explanation:

hope this helps!

Answer:

Cubic

Step-by-step explanation:

He has widht, heigh and length.

The cubic function is used to represent the length, width or height of a box. The correct option is C.

The cubic function is defined as a function having a degree of three. It is the same as that of cubic polynomials.

A cubic function is defined in mathematics as a function of form f(x)=ax³+bx²+cx+d, where the coefficients a, b, c, and d are complex numbers and the variable x takes real values.

The box has three dimensions that are length, width, and height. The volume of the box will be calculated by the product of the three sides of the box.

There are three dimensions involved in the calculation of the volume of the box. It means that the volume will be a cubic function.

To know more about cubic functions follow

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Simplify the coefficient of z on the left side. We do this by rationalizing the denominators and multiplying them by their complex conjugates:

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3-2i}{1+i}\cdot\dfrac{1-i}{1-i} - \dfrac{5+3i}{1+2i}\cdot\dfrac{1-2i}{1-2i}[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{(3-2i)(1-i)}{1-i^2} - \dfrac{(5+3i)(1-2i)}{1-(2i)^2}[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 2i - 3i + 2i^2}{1-(-1)} - \dfrac{5 + 3i - 10i - 6i^2}{1-4(-1)}[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 5i + 2(-1)}2 - \dfrac{5 - 7i - 6(-1)}5[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2 - \dfrac{11 - 7i}5[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2\cdot\dfrac55 - \dfrac{11 - 7i}5\cdot\dfrac22[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{5 - 25i - 22 + 14i}{10}[/tex]

[tex]\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = -\dfrac{17 + 11i}{10}[/tex]

So, the equation is simplified to

[tex]-\dfrac{17+11i}{10} z = \dfrac12 - \dfrac{2i}5[/tex]

Let's combine the fractions on the right side:

[tex]\dfrac12 - \dfrac{2i}5 = \dfrac12\cdot\dfrac55 - \dfrac{2i}5\cdot\dfrac22[/tex]

[tex]\dfrac12 - \dfrac{2i}5 = \dfrac{5-4i}{10}[/tex]

Then

[tex]-\dfrac{17+11i}{10} z = \dfrac{5-4i}{10}[/tex]

reduces to

[tex]-(17+11i) z = 5-4i[/tex]

Multiply both sides by -1/(17 + 11i) :

[tex]\dfrac{-(17+11i)}{-(17+11i)} z = \dfrac{5-4i}{-(17+11i)}[/tex]

[tex]z = -\dfrac{5-4i}{17+11i}[/tex]

Finally, simplify the right side:

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{5-4i}{17+11i} \cdot \dfrac{17-11i}{17-11i}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{(5-4i)(17-11i)}{17^2-(11i)^2}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44i^2}{289-121(-1)}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44(-1)}{410}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 123i}{410}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 41\cdot3i}{410}[/tex]

[tex]-\dfrac{5-4i}{17+11i} = -\dfrac{1 - 3i}{10}[/tex]

So, the solution to the equation is

[tex]z = -\dfrac{1-3i}{10} = \boxed{-\dfrac1{10} + \dfrac3{10}i}[/tex]

Yes, 3 divides 27,333. We have

27,333 = 27,000 + 333

… = 27•1,000 + 333

… = 3•9•1,000 + 3•111

… = 3•(9•1,000 + 111)

… = 3•(9,000 + 111)

… = 3•9,111

Answer:

31/18

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

25% of 72

25/100 * 72

= 1/4 * 72

= 18

The graphs of f(x) and g(x) are related by transforming one of the two graphs.

The equation of the blue graph is [tex]\mathbf{g(x) =(x - 4)^2}[/tex]

From the graphs, we have:

[tex]\mathbf{f(x) =x^2}[/tex]

f(x) is transformed to the right by 4 units.

The rule of this transformation is:

[tex]\mathbf{g(x) \to f(x - 4)}[/tex]

So, we start by calculating f(x - 4)

Given that:

[tex]\mathbf{f(x) =x^2}[/tex]

Substitute x - 4 for x in f(x)

[tex]\mathbf{f(x - 4) =(x - 4)^2}[/tex]

Also, recall that:

[tex]\mathbf{g(x) \to f(x - 4)}[/tex]

So, we have:

[tex]\mathbf{g(x) =(x - 4)^2}[/tex]

Hence, the equation of g(x) is [tex]\mathbf{g(x) =(x - 4)^2}[/tex]

Read more about transformation at:

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Answer: (x+2)^2 -11

Step-by-step explanation:

X^2 +4x -7

Half the middle term, add it to x and put them into a bracket and square it

(X+2) ^2 -7

Square the second term to get 4 and then take that away from 7. (We do this because if we had the extra 4, our answer when’s we multiplied out of the brackets wouldn’t be x^2 +4x -7.)

(X+2)^2 -7 -4

Now simplify the whole numbers outside the bracket

(X+2) ^2 -11

Answer: 33.5

Step-by-step explanation:

the answer is: 58.95

i took the test

Answer:

m∠E = 124°

Step-by-step explanation:

Since the triangles are congruent, B and E are automatically congruent, since they are corresponding angles.

First, we must find the value of y.

Set both measures equal to each other.

98 + y = 6y - 32.

Subtract y from both sides.

98 = 5y - 32

Add 32 on both sides.

130 = 5y

Divide 5 on both sides.

y = 26

Substitute y for angle E.

E = 6(26) - 32

E = 156 - 32

E = 124°