Answer:
A = 79°
Step-by-step explanation:
CosA = adjacent ÷ hypoteneous
A = Cos^-1(6÷32)
A. =. 79.19°
A= 79°
The sum of two numbers is 50. If the larger number is divided by the
smaller number we get 7/11. Find the numbers.
Answer:
y = 30.555 and x = 19.444
Step-by-step explanation:
We are given:
x + y = 50 and
x / y = 7/11
use substitution taking
x + y = 50
x = 50 - y
then
x / y = 7/11 and from above substitute for x
(50 - y)/ y = 7/11
(50 - y) = 7y/11
11(50 - y) = 7y
550 - 11y = 7y
550 = 18y
y = 550/18 = 30.555 so
x + y = 50
x = 50 - y
x = 50 - 30.555 = 19.444
Find the measure of one exterior angle for the following regular polygon that’s for both questions
Answer:
Step-by-step explanation:
Consider a wall clock. In degrees, how far does the minute hand move in 5 minutes?
- 5 degrees
- 30 degrees
- 6 degrees
- 1 degree
Which of the following equations of a line is NOT written in standard form?
A. 12x - 2y = 82
B. y = -2x - 1
C. x – 7y = 22
D. -x + 5y = 10
Answer: B
Step-by-step explanation:
Its written in slope intercept form not standard
Can someone please answer B (PICTURE)
Answer:
The question is asking for the perimeter. There are three ways to answer this depending on the assumptions though so I'll let you choose.
Assumptions are basically the different scenarios
1st scenario being the trim covers the carpet and the tile, they'd need 48m of trim (12+12+4+8+8+4)
2nd scenario in which the trim covers the carpet but not the tiled area, they'd need 44m of trim (12+12+4+8)
3rd scenario where the trim only covers the the tiled area, 4m of trim
(just 4 since the tile only touches 4m of the wall)
Hope this helps!
Step-by-step explanation:
trim is just the perimeter since it covers the base of the wall
WHO CAN HELP ME !!!!!!! PLEASE FINNA CRY RN
Answer:
In the other polygon which is smaller you just half the size of the larger one like 12 became 5 and 6 became 3 so 14 will also be halved and the answer will be
7
Suppose triangle ABC is similar to triangle
PQR with AB:PQ = 5:9
What is the ratio of the area of ABC to PQR?
Answer:
[tex]( \frac{5}{9} ) ^{2} = \frac{25}{81} [/tex]
Drag the cards to create a number that matches these rules.
The number ends in the hundredths place.
6 is the nearest one when rounding.
9, 4, (.)decimal point, 5
Answer:
0.459
Step-by-step explanation:
O.459 will round to 0.46 which meets the question's criteria.
Each group of students receives a bag that has 8 red cubes, 2 green cubes, and 10 blue cubes. If each group makes 100 pulls and replaces the cube after each pull, how many times would you expect them to draw a blue cube?
Answer:
50% of the time
Step-by-step explanation:
8+2+10=20
20-10=10
10 is half of 20
Answer:
50
Step-by-step explanation:
First find the probability of drawing a blue
The total number of cubes
8 red cubes, 2 green cubes, and 10 blue cubes = 20 cubes
P(blue) = blue / total = 10/20 = 1/2
Since they are replaced, the probability remains the same
100 draws * P(blue) = 100 * 1/2 = 50
This is confusing very much, I’m having a lot of problems at the moment and I’m in a lot of pain.
abio and Carlos play on a basketball team together. In the last game, Fabio had 777 points less than 222 times as many points as Carlos. Fabio scored 313131 points in the game.Write an equation to determine the number of points (c)(c)(, c, )Carlos scored in the last game.
Answer:
The equation 31=2c-7 to determine the number of points Carlos scored in the last game.
Step-by-step explanation:
We are given with,(I think every number is repeating for 3 times. So, I took each number as once)
Fabio had 7 less than 2 times as many points as Carlos. And Fabio score 31 points.
Let Carlos scored in the last game as "C".
So, we can set up equation for Fabio had 7 less than 2 times Carlos as
Fabio= 2C-7
Like so for Fabio score 31 as
Fabio =31
So, substitute Fabio as 31 into the first equation, we get
31= 2c-7
So, the equation 31=2c-7 to determine the number of points Carlos scored in the last game.
find thd length of the missing sides
Answer:
x = 4[tex]\sqrt{3}[/tex] , y = 8[tex]\sqrt{3}[/tex]
Step-by-step explanation:
The ratio of the sides of a 30- 60- 90 triangle are
x : x[tex]\sqrt{3}[/tex] : 2x
From the diagram
x[tex]\sqrt{3}[/tex] = 12 ( divide both sides by [tex]\sqrt{3}[/tex] )
x = [tex]\frac{12}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ( rationalising the denominator )
= [tex]\frac{12\sqrt{3} }{3}[/tex]
x = 4[tex]\sqrt{3}[/tex]
Then
y = 2x = 2 × 4[tex]\sqrt{3}[/tex] = 8[tex]\sqrt{3}[/tex]
The approximate values of x and y are 4√3 and 8√3, respectively.
Given is a right triangle with base = x and the hypotenuse = y and the perpendicular side is 12, the acute angle between the base and the perpendicular side is 60°.
We need to find the value of x and y,
So, to find the value of x and y, we will use the concept of trigonometric ratios,
So, we know,
Sin = perpendicular / hypotenuse
Cos = base / hypotenuse
Tan = perpendicular / base
Let's denote the acute angle between the base and the perpendicular side as θ.
Angle θ = 60°
Using the sine ratio, we can write:
Sin(60°) = 12 / y
√3/2 = 12 / y
Cross-multiplying, we get:
√3 × y = 2 × 12
√3 × y = 24
y = 24 / √3
y = 8√3
To find the value of x, we can use the cosine ratio.
Cos(60°) = x / y
1/2 = x / 8√3
Cross-multiplying, we get:
2x = 8√3
x = 4√3
Hence, the value of x and y are:
x = 4√3
y = 8√3
Learn more about trigonometric ratios, click;
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What is the solution to the system that is created by the equation y = - x + 6
Answer:
If you draw the graph of y = -x + 6 on the above graph the solution to system will be the coordinates of the point of intersection.
the equation of the line drawn above is y = 0.5x
so you can also find the solution by solving the system
y = 0.5x
y = -x + 6
0.5x = -x + 6
1.5x = 6
x = 6/1.5 = 4
and y = 0.5*4 = 2
The answer is (4, 2) - the third choice.
Step-by-step explanation:
Can someone please help me out with this its really urgent Ill mark brainliest
Answer:
smart dot company c=.50t+12
communication plus c=2.50t
Step-by-step explanation:
smart dot has the starting point of $12 per month already so that would be your y-intercept with the equation being y=mx+b , y being the cost m being the amount of money per hour, x being the time spent, and b being the starting cost.
So with that smart dot would be c=.50t+12
with communication plus not having that starting point it would just be c=2.50t
Each day Jose spends 2/3 of an hour playing the piano and 1/4 of an hour practicing music theory. What is the total fraction of an hour that Jose spends playing the paino and practicing music theory each day?
Answer:
11/12
Step-by-step explanation:
2/3 + 1/4
Get a common denominator of 12
2/3 *4/4 + 1/4 *3/3
8/12 + 3/12
11/12
The local time in Singapore is 7 hours ahead of the local time in London. A flight to London leaves Singapore at 0300 local time .
Flight takes 12hours and 45 minutes .What is the local time in London when it arrives?
Answer:
I think its 8.45am if they are asking when it arrived in londonRearrange each of the following in slope/y-intercept form, y = mx + b.
a. 3x - 6y + 8 = 0 b. -2x - 5y - 2 = 0
Answer:
a.
[tex]{ \tt{3x - 6y + 8 = 0}} \\ { \tt{ 6y = 3x - 8}} \\ { \boxed{ \bf{y = \frac{1}{2} x - \frac{4}{3} }}}[/tex]
b.
[tex]{ \tt{ - 2x - 5y - 2 = 0}} \\ { \tt{5y = - 2x + 2}} \\ { \boxed{ \bf{y = - \frac{ 2}{5} x + \frac{2}{5} }}}[/tex]
which expression is equivalent to \root(3)(x^(5)y)
Answer:
[tex]\sqrt[3]{x^{5}y} = x^{\frac{5}{3}}y^\frac{1}{3}[/tex]
Step-by-step explanation:
Given
[tex]\sqrt[3]{x^{5}y}[/tex]
Required
The equivalent expression
We have:
[tex]\sqrt[3]{x^{5}y}[/tex]
Rewrite as an exponent
[tex]\sqrt[3]{x^{5}y} = (x^{5}y)^\frac{1}{3}[/tex]
Open bracket
[tex]\sqrt[3]{x^{5}y} = x^{5*\frac{1}{3}}y^\frac{1}{3}[/tex]
[tex]\sqrt[3]{x^{5}y} = x^{\frac{5}{3}}y^\frac{1}{3}[/tex]
HELPPPPP ASAP!!!! Thx!! and NOOO FILESSSS!! it's on KHAN ACADEMY!!
Answer:
[tex]32[/tex]
Step-by-step explanation:
[tex]x=\dfrac{180-116}{2}=\dfrac{64}{2}=32[/tex]
Complete each statement. If the triangles cannot be shown to be congruent from the information given, leave the triangles name blank and write Cannot Be Determined (CNBD) in the spot for rule. ∆SAT ≅ ∆_____ By _____
Answer:
The answer is "[tex]\bold{\Delta LAW \cong \Delta WKL}[/tex]. By applying the ASA congruence postulate rule".
Step-by-step explanation:
[tex]\Delta LAW\ and\ \Delta WKL\\\\AW\perp WL\ and \ WL\perp KL\\\\\angle AWL = \angle WLK .......[each \ 90^{\circ}]\\\\WL=WL.......\ [Reflexive \ property]\\\\\angle ALW = \angle KWL........\text{give in picture}\\\\[/tex]
[tex]\therefore,[/tex] by ASA postulate of congruence
[tex]\Delta LAW \cong \Delta WKL\\\\[/tex]
The ASA postulate states that when two angles on the included side with one triangle were congruent to two angles on the included side of the second triangle, then the triangles are said to have been congruent.
Understanding Transversals
Use the diagram to complete the statements. (please helpp)
Answer:
Step-by-step explanation:
need help with this refer to picture
Answer:
Step-by-step explanation:
last one! 50 points!
Answer:
sin theta = -2 sqrt(14)/15
Step-by-step explanation:
cos theta = adj / hyp
We can find the opp side by using the Pythagorean theorem
adj ^2 + opp ^2 = hyp^2
(-13)^2 + opp ^2 = 15^2
169 + opp ^2 = 225
opp ^2 = 225 -169
opp ^2 =56
Taking the square root of each side
sqrt( opp^2) = sqrt(56)
opp = sqrt(4 * 14)
opp = 2 sqrt(14)
Since we are in the third quadrant opp is negative
opp = -2 sqrt(14)
We know
sin theta = opp / hyp
sin theta = -2 sqrt(14)/15
Given that :
[tex] \frak {\cos( \theta_{1} ) = - \frac{13}{15} }[/tex]
To find :
[tex] \frak{ sin( \theta_{1} )}[/tex]
We know that cos θ is base/hypotentuse
So, here the base is -13 and the hypotentuse is 15
As we got the base and hypotentuse, perpendicular needs to be found out
Now, applying Pythagoras Theorem
According to Pythagoras theorem we know that :
(Hypotentuse)² = (Base)² + (Perpendicular)²Let us assume perpendicular be x
Putting the values we get
(15)² = (-13)² + (x)² 225 = 169 + x²By transposing we get
x² = 225 - 169x = √56 x = 2√14sin θ formula : Perpendicular/Hypotentuse
[tex] \star \: \: \underline{ \overline{ \boxed{ \frak{ sin (\theta_{1})} = \frac{-2 \sqrt{14} }{15} }}}[/tex]
Hence, the answer is -2√14/15
Coordinates of C and D are (-14 , 6) and (x , 13) respectively.Given x is a positive integer and the distance CD is 25 units.Find the value of x.
Answer:
10
Step-by-step explanation:
1) The vector CD is equal to (X-(-14); 13-6)= (x+14; 7)
2) The module of the vector CD is equal to diatance CD=25. It is equal to
sqrt ((x+14)(x+14)+7*7) from the formula of module (with coordinates).
25= sqrt ((x+14)(x+14)+7*7)
625= (x+14)*(x+14)+49
625= x^2+28x+196+49
X^2+28X-380=0
a=1 b=28 c=-380
D= b*b-4ac= 28*28-4*1*(-380)= 784+1520= 2304
sqrt D= sqrt2304=48
x1= (-28-48)/2= -38
x2= (-28+48)/2= 10
But x1<0 it is negative and it is not suitable, x2>0 it is positive, so answer is 10.
Please help cause if you dont you will get a beatboxbattle lol.
Answer:
14
Step-by-step explanation:
2a -b
Let a = 9 and b = 4
2(9) - 4
Multiply first
18-4
14
Please find the value of A,B,C&D
Given
A + B = 8
A + C = 13
B + D = 8
C - D = 6
Now
A + B = B + D
A = B + D -B
A = D
C - D = C - A
A + C = 13
C - A = 6
Adding 7 on both sides
C - A +7 = 6+7
C - A + 7 = A + C
C-C -A + 7 = A
-A +7 = A
7 = A+A
7/2 = A
A = 3.5
B = 4.5
C =9.5
D = 3.5
Answered by Gauthmath must click thanks and mark brainliest
Question 7 (1 point)
Which coordinates have a slope of 3?
(4,5) (1,4)
(6, 9) (3,0)
(-3, 0) (-6, 0)
(3, 1) (0, 2)
Answer:
(6, 9) (3, 0)
Step-by-step explanation:
Solve for each option using the slope formula:
Slope formula:
m = y2 - y1 / x2 - x1
m = 4 - 5 / 1 - 4
m = -1/-3
m = 1/3
This is not 3.
m = 0 - 9 / 3 - 6
m = -9 / -3
m = 3
This has a slope of 3!
m = 0 - 0 / -6 - 3
m = 0/ -9
m = 0
This is not 3.
m = 2 - 1 / 0 - 3
m = 1/-3
m = -1/3
This is not 3.
please show work it’s for calc
Answer:
-93
Step-by-step explanation:
This is just.a matter of using a couple of integration rules and plugging in then using order of operations.
Difference rule and constant multiple rule will be used here.
3(-17)-7(6)
-51-42
-93
Answer:
[tex]\displaystyle \int\limits^6_4 {[3f(x) - 7g(x)]} \, dx = -93[/tex]
General Formulas and Concepts:
Calculus
Integration
IntegralsIntegration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]: [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int\limits^6_4 {f(x)} \, dx = -17[/tex]
[tex]\displaystyle \int\limits^6_4 {g(x)} \, dx = 6[/tex]
[tex]\displaystyle \int\limits^6_4 {[3f(x) - 7g(x)]} \, dx[/tex]
Step 2: Integrate
[Integral] Rewrite [Integration Property - Addition/Subtraction]: [tex]\displaystyle \int\limits^6_4 {[3f(x) - 7g(x)]} \, dx = \int\limits^6_4 {3f(x)} \, dx - \int\limits^6_4 {7g(x)} \, dx[/tex][Integrals] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^6_4 {[3f(x) - 7g(x)]} \, dx = 3 \int\limits^6_4 {f(x)} \, dx - 7 \int\limits^6_4 {g(x)} \, dx[/tex][Integrals] Substitute: [tex]\displaystyle \int\limits^6_4 {[3f(x) - 7g(x)]} \, dx = 3(-17) - 7(6)[/tex]Simplify: [tex]\displaystyle \int\limits^6_4 {[3f(x) - 7g(x)]} \, dx = -93[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
One hundred pyramid-shaped chocolate candies with a square base with 12 mm sides and height of 15 mm are melted in a cylindrical pot. If the pot has a radius of 75 mm, what is the height of the melted candies in the pot?
Step-by-step explanation:
Volume of 100chocolates:
((12^2 x 15)/3) x 100 =72000
volume of cylinder:
base area x height
base area= πr^2= 5625π
height=volume/base area
height=72000/5625π=4.07 (3sf)
ans: 4.07mm
What do you get if subtract the sum of -1451 and 1267 from the sum of 1146 and -2172?
Answer:
-3502 is your answerStep-by-step explanation:
hope it will help you
Answer:
-842
Step-by-step explanation:
We should find the sum of -1451 and 1267 and the sum of 1146 and -2172.
-1451 + 1267 = 1267 - 1451 = -184
1146 + (-2172) = 1146 - 2172 = -1026
Then we subtract -184 from -1026.
-1026 - (-184) = -1026 + 184 = -842