Name two pairs of congruent angles using the figure shown.

Option 1: ∠JKM ≅ ∠KJL and ∠JLM ≅ ∠KML
Option 2: ∠JLM ≅ ∠KJL and ∠JKM ≅ ∠KML
Option 3: ∠JKM ≅ ∠JLM and ∠KJL ≅ ∠KML
Option 4: ∠JLM ≅ ∠KJL and ∠JLM ≅ ∠JKM

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

[tex]\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}[/tex]

Then

[tex]Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\[/tex]

Note that since

[tex]F \cap R=\varnothing[/tex], [tex]Perm(F)\cap Perm(R)\ne \varnothing[/tex]

But since

[tex]B \cap R \ne \varnothing[/tex], [tex]Perm(B)\cap Perm(R)= \varnothing[/tex]

and

[tex]B \cap F \ne \varnothing[/tex] , [tex]Perm(B)\cap Perm(F)= \varnothing[/tex]

Since

[tex]|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\[/tex]

where [tex]|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}[/tex]

and

[tex]|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}[/tex]

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

[tex]|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}[/tex]

This link contains another solved problem on permutations:

https://brainly.com/question/7951365

i guess is by multiplying 3by the first equation and multiply 2by the second equation

Answer:

114 degrees

Step-by-step explanation:

6x+12=3x+63

-3x -12 -3x  -12

3x=51

x=17

6(17) +12 = 114

Answer:

End of round 1:

128 ÷ 2 = 64

End of round 2:

64 ÷ 2 = 32

End of round 3:

32 ÷ 2 = 16

Step-by-step explanation:

Answer: 16

Step-by-step explanation: i think :)

Answer:

sorry I cannot understand that

Answer:

x is amount of money

c + a = 646

2c + 7a = x

2(380) + 7(246) = 2486

x = $2486

Answer:

A

Step-by-step explanation:

Answer:

solve:

-3x+10<dividing22

-3x< 12

by a negativie flips sign

x>4

So A is correct because the because its an open circle  on number line

Answer:

l=44in

Step-by-step explanation:

Using the formula

P=2(l+w)

Solving forl

l=P

2﹣w=94

2﹣3=44in

Answer:

\sqrt(3)[cos((4\pi )/(45))+isin((4\pi )/(45))]

Step-by-step explanation:

The first one.

Answer:

AB and GF are skew

DH and BF are II

EF and HG are skew

ABCD and EFGH are II

Step-by-step explanation:

II is parralell or side by side.

Skew would be like intercepting with one another.

Have an awesome day! :D

Answer:

Since 10% like neither, then 90% must like tea(T), coffee(C) or both(B). So what % like both? That % would have to be deducted from both the tea and coffee likers to arrive at tea only (TO), coffee only (CO) and those liking both and the three would have to sum to 90%, since 10% like neither. So whatever % the 120 represents it must be deducted from both the tea and coffee likers. I don’t know how to add graphics but in equation form

50-x + 70-x + x + 10 = 100, 130-x = 100, -x = -30, X = 30%,

120/30% = 400, 50%(T)-30%(B)=20%(TO) or 80, 70%-30%=40% or 160, 30% or 120, and 10% or 40

80+160+120+40=400

Answer:

Step-by-step explanation:

  50%        70%                 10%

like tea    like coffee      don't like both

100%-10% =90%

                   like coffee,tea or both

   50%  +   70%         =120%  -   90%   =   30%

like tea + like coffee  =          -           =    like both

LIKE BOTH           30%=`120

means 1%=4

100%=400

Answer:

60% adult

40% children

Reasoning:

Add the adults and children first.

Then find the ratios of the children and parent percentages.

16:40 children

24:40 adult

16/40=2/5=0.4=40% children

24/40=3/5=0.6=60% adult

Answer:

40% is children and 60% in adults

Step-by-step explanation:

so if you add the two you have 40, 100% of 40 is 40 and 50% is 20, so we know that the children percent is less than 50, if you go through you will find that 40% of 40 is 16 therefor leaving the rest (aka 60%) to be adults

Using proportions, it is found that the height of the lighthouse is of 84 ft.

The rule of three is:

5.25 feet - 8 feet

x feet - 128 feet

Applying cross multiplication:

[tex]8x = 5.25(128)[/tex]

[tex]x = \frac{5.25(128)}{8}[/tex]

[tex]x = 84[/tex]

The height of the lighthouse is of 84 ft.

A similar problem, which also uses proportions, is given at https://brainly.com/question/24372153

Answer:

Step-by-step explanation:

For SSS congruence, all three pairs of sides must be marked as congruent. That is, there needs to be 3 hash marks on sides SU and RP. (Note the order of the vertices.)

  needed: SU ≅ RP

If we label the triangles in order by hash marks, the congruence statement becomes ...

  ΔPQR ≅ ΔUTS

Answer:

Part A: $60

Part B: $54

Step-by-step explanation:

Answer:

its 5 boxes

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

john quincy adams was the 6th president

Answer:

5 would be the answer.

Step-by-step explanation:

13 divided by 3(weeks) = 4.3

4.3 x 5 = 21.

= 5.

Each team will play with 11 other teams. Hence each team plays 11 games. Hence a total of 11*12 =132 games but since each game involves two teams divide 132/2 = 66 so B

Answer:

Step-by-step explanation:

(-4 - 4)/(3 - 1)= -8/2= -4

y - 4 = -4(x - 1)

y - 4 = -4x + 4

y = -4x + 8

answer is option 1

Answer:

 [tex]\Large \text{$ \frac{1}{w^2} $}[/tex]

Step-by-step explanation:

Given the exponential expression, [tex]\displaytext\mathsf{w^3\:\times\:w^{-5}}[/tex], where it involves the multiplication of the same base, w, with varying powers.  

Using the Product Rule of Exponents, where it states that, [tex]\displaystyle\mathsf{a^{m}\:\times\:a^{n}\:=\:a^{(m\:+\:n)}}[/tex].

Hence, we simply need to add the exponents:  

[tex]\displaytext\mathsf{w^3\:\times\:w^{-5}\:=\:w\:^{[3\:+\:(-5)]}\:=\:w^{-2}}[/tex]

Next, apply the Negative Exponent Rule, where it states that: [tex]\displaystyle\mathsf{a^{-n}\:=\:\frac{1}{a^n}}[/tex].

Transforming the negative exponent of  [tex]\displaytext\mathsf{w^{-2}}[/tex]  becomes a positive exponent by using the Negative Exponent Rule.

  [tex]\displaytext\mathsf{w^{-2}\:=\:\frac{1}{w^2}}[/tex]

The special right triangle is the right triangle that have acute angle values

that simplify the process of finding its dimensions.

The correct values are;

1. The angle the ladder makes with the ground, is approximately 66.93°

2. The length of YZ is approximately 19.18 ft.

3. CB = 7 ft. and AB = 7·√3 ft.

Reasons:

1. The length of the ladder = 15 ft.

Height of the ladder above the ground, h = 13.8 ft.

Required:

The angle the ladder makes with the ground.

Solution:

The angle the ladder makes with the ground is given by the equation;

[tex]sin(\theta) = \dfrac{Length \ of \ the \ ladder}{Height\ of \ the \ ladder \ above the \ ground} = \dfrac{13.8}{15} = 0.92[/tex]

[tex]\theta = arcsin\left(0.92 \right) \approx 66.93^{\circ}[/tex]

2. The given parameters are;

XY = 11

∠Z = 35°

YZ = Required

In a right triangle, the side facing the acute angle is a leg of the triangle.

Therefore;

XY is the opposite side to ∠Z

[tex]sin(\angle Z) = \dfrac{XY}{YZ}[/tex]

Which gives;

[tex]sin(35^{\circ}) = \dfrac{11}{YZ}[/tex]

[tex]YZ= \dfrac{11}{sin(35^{\circ}) } \approx 19.18[/tex]

YZ ≈ 19.18 ft.

3. AC = 14 ft.

∠A = 30

Required:

The length of the other two sides

Solution:

Where by AC is the hypotenuse side, we have;

CB = AC × sin(∠A)

Therefore;

CB = 14 × sin(30°) = 7

CB = 7 ft.

AB =  AC × cos(∠A) = 14 × cos(30°) = 7·√3

Learn more here:

https://brainly.com/question/12237712

1. The angle the ladder makes with the ground, is approximately 66.93°

2. The length of YZ is approximately 19.18 ft.

3. CB = 7 ft. and AB = 7·√3 ft.

Answer:

5/12 of a gallon

Step-by-step explanation:

5 divided by 12 is 5/12

Answer: 8:05

Step-by-step explanation:

Answer: 8:05

Step-by-step explanation:

Answer:

ion

Step-by-step explanation:srry

Answer:

21

Step-by-step explanation:

The average rate of change of function f(x) from x = a to x = b is

[tex] \dfrac{f(b) - f(a)}{b - a} [/tex]

Here we have

a = -1

b = 2

f(a) = f(-1) = 1

f(b) = f(2) = 64

[tex] \dfrac{f(b) - f(a)}{b - a} = [/tex]

[tex] = \dfrac{f(2) - f(-1)}{2 - (-1)} = [/tex]

[tex] = \dfrac{64 - 1}{2 + 1} [/tex]

[tex] = \dfrac{63}{3} [/tex]

[tex] = 21 [/tex]