run a regression analysis on the following data set, where y is the final grade in a math class and x is the average number of hours the student spent working on math each week. hours/week x grade y 5 52 5 44 11 67.4 13 89.2 13 75.2 14 92.6 15 87 16 84.4 17 86.8 17 88.8 State the regression equation y=m⋅x+by=m⋅x+b, with constants accurate to two decimal places.
What is the predicted value for the final grade when a student spends an average of 8 hours each week on math?
Grade = Round to 1 decimal place.
Expert Answer

Camille can buy maximum of 3 shirts with the amount with him and left with $24 after buying 3 shirts .

Price of each shirt is $32 and the maximum she can buy is 5 shirts

suppose he buys x shirts from the money he initially have

so 32*x<=120

=> x<=3.75

solving the inequality we get:

so x=3 so maximum he can buy is 3 shirts.

Cost of each shirts is $32 so  the cost of 3 shirts is given by:

=>3*32

=> $96

so the amount of money left with him = 120 -96

=> 24

so total $24 she can save after buying 3 shirts.

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Complete question:

camille have $120 with him he can buy upto 5 shirts and cost of each shirt is $32 .how much money could she have and how manu shirts he buys? enter the correct answers in the boxes in dollars and cents.

The three-dimensional object formed when the shape is rotated about the axis is a hollow cylinder.

This object is generated by taking a vertical rectangle and rotating it around the vertical axis. Mathematically, this can be described as a revolution of the rectangle about the y-axis in which the points of the rectangle are shifted a certain distance away from the axis. The three-dimensional object formed when the shape is rotated about the axis is a hollow cylinder.The formula used to calculate the volume of a hollow cylinder is V = π(r^2)h, where r is the radius of the cylinder, and h is the height. For example, if we have a cylinder with radius 4 and height 8, the volume would be V = π(4^2)8 = 128π cubic units.

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The median salary in 2048 will be  2.853 million

A general linear equation is given by:

y=a × x + b

Where the slope is a and the y-intercept is b.

We shall discover that the linear equation for this scenario is

y = 0.033 ×  x + 1.269

And we may anticipate that in 2048, the median salary will be 2.853 million.

The slope can be expressed as if the line passes through the points (x1, y1) and (x2, y2).:

[tex]$a=\frac{y_2-y_1}{x_2-x_1}[/tex]

Here, we know that whereas the median player pay in 2007 (x = 7) was y = 1.5 million, it was y = 1.7 million in 2013 (x = 13).

The following two points can be written as follows:

(7,1.5)

(13,1.7)

Note that the y-value is in millions.

Then the slope of the linear equation will be:

[tex]$a=\frac{1.7-1.5}{13-7}=0.033[/tex]

So the linear equation is something like:

y=0.033 × x + b

Remember the point (7,1.5), which indicates that for x=7, we also get y=1.5, so we can substitute these in the equation above:

1.5=0.033 ×  7+b

1.5-0.033 ×  7 = b = 1.269

Then the linear equation is:

y=0.033 ×  x+1.269

b) Now we want to predict the median salary in 2048 . For 2048 the

x-value is x=48

So we just need to evaluate this in the linear equation:

y = 0.033 × 48 + 1.269 = 2.853

Then the median salary in 2048 will be  2.853 million

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sint= [tex]y=\frac{\sqrt{5} }{5}[/tex], cost= [tex]x=\frac{2\sqrt{5} }{5}[/tex], tant=2.

If the terminal point P(X, Y) is determined as a real number, t lies on the unit circle then:

sint=y cost=x tant=y/x

we are given a terminal point of P [tex](\frac{\sqrt{5} }{5} ,\frac{2\sqrt{5} }{5} )[/tex] but not given that t lies on the unit circle. we must then first verify that P lies on the unit circle:

The equation of the unit circle is:

x²+y²=1

After substituting the given points in the above equation:

[tex](\frac{\sqrt{5} }{5} )^{2} +(\frac{2\sqrt{5} }{5} )^2=1[/tex]

Now evaluate the powers we get:

[tex]\frac{5}{25} +\frac{20}{25} =1[/tex]

Adding the equation we get:

1=1

Since P [tex](\frac{\sqrt{5} }{5} ,\frac{2\sqrt{5} }{5} )[/tex] lies on the unit circle, then:

[tex]sint=y=\frac{\sqrt{5} }{5}\\\\cost=x=\frac{2\sqrt{5} }{5} \\\\tant=\frac{y}{x}=\frac{\frac{2\sqrt{5} }{5} }{\frac{\sqrt{5} }{5} }[/tex]

By solving the tant we get:

tant=2.

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Answer: mean would be d or 998.67 wouldn't it

Step-by-step explanation:

because mean 998.67 median 1100 and mode 1500

i think that is right but i am not 100% sure

Answer:

Q1 - 7910

Q2 - 9710

Q3 - 1097

Q4 - 7190

I don't know what these mean, but here you go..?

Answer:52.8

Step-by-step explanation:

52.752

so it = 52.8

The shape of the sampling distribution of the sample mean is approximately normal because the sample size is greater than 3.

Given data :

a ) Approximately normal because the sample size is greater than 3.

b ) b )  ux  = 1.1 and Jx =  [tex]\frac{1.4}{\sqrt{40} }[/tex]= 0.198

c  ) c ) P ( ux ∠ 1 ) = normal cdf ( lower : 1000, upper : 1, u : 1.1 , J : 0.198 ) = 0.3068

d ) The principal could pick 50 students may times and find the median and repeat several times until he has every possible sampling distribution.

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Step-by-step explanation:

The vertical extent of the graph is all range values 3 and -2, so the range is (−2,3]

Question

Answered step-by-step

"Match the key aspect of a function's graph with its meaning. f(x) > 0 intervals of the domain where the graph is above the x-axis f(x) < 0 location on graph where input is zero x-intercept location on graph where output is zero y-intercept intervals of the domain where the graph is below the x-axis Common Core Algebra 'httpsinIscorekam edgenuftycomPlayer Common Core Algebra /- MAJIO9 / AcR 7haijliy Giapiij Instruction Active of a Graph the Meaning of Key Features Matching of a function $ graph with its meaning Match the key aspect intervals of Ihe domain where the graph. IS above the x-axis flx) > E Iocation on graph where input IS zero fix) < 0 Iocation on graph where output IS x-Intercepi zero Intervals Of the domain where the y-intercept graph Is below the x-axis Untto Done PrevousAaml Type here i0 search"

Answer:

2.25.50

Step-by-step explanation:

it is simplified since 25 is not divisible by 2

The equation of the line containing point  (7, -5) and having slope 4/5 is found as y = 4/5x - 3/5.

The given data:

Comparing eq with standard form:

5y = 4x - 2

y = 4/5 x - 2/5

slope m = 4/5

As both lines are parallel, the slope of both lines will be equal.

Thus, using slope intercept form

y - y1 = m(x - x1)

y + 5 = 4/5 (x - 7)

y + 5 = 4/5x - 28/5

y = 4/5x - 3/5

Thus, the equation of the line containing point  (7, -5) and having slope 4/5 is found as y = 4/5x - 3/5.

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4/3 is the value of k that makes the system of linear equations has no solutions .To determine the value(s) of k such that the system of linear equations has no solutions, we need to use the concept of consistency and consistency of a system of linear equations, which is the property that a system of equations has exactly one solution or no solution.

A system of linear equations is consistent if it has exactly one solution and inconsistent if it has no solution. We can use the concept of determinant of a matrix to check the consistency of the system of linear equations. The determinant of a matrix is a scalar value that can be calculated from the elements of a matrix and it tells us whether a matrix is invertible or not. An invertible matrix corresponds to a consistent system of linear equations and a non-invertible matrix corresponds to an inconsistent system of linear equations. To check the consistency of the system of linear equations, we can use Cramer's Rule, which states that the determinant of the coefficient matrix must be non-zero for the system to have a unique solution.

The coefficient matrix of the given system of equations is:

| 1 2 k |

| 3 6 8 |

The determinant of the coefficient matrix is:

|1 2 k|

|3 6 8| = (18) - (26) + (k*3) = 8 - 12 + 3k

If the determinant of the coefficient matrix is non-zero, the system of equations will have a unique solution, if the determinant of the coefficient matrix is zero, the system of equations will have no solution.

So for the system of linear equations to have no solution, the determinant of the coefficient matrix must be zero.

8 - 12 + 3k = 0

3k = 4

k = 4/3

So the value of k that makes the system of linear equations has no solutions is 4/3.

It is worth noting that if there are infinite solutions, the determinant of the matrix is zero but the rank of the matrix (the number of linearly independent rows or columns) is smaller than the number of variables

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We have used spherical coordinates to show that the triple integral from negative infinity to infinity of the [tex]\int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \sqrt{x^2+y^2+z^2} e^{-\left(x^2+y^2+z^2\right)} d x d y d z=2 \pi$$[/tex]

Triple integrals, as their name suggests, are three sequential integrations that can be used to determine a volume or to integrate in a fourth dimension over three other independent dimensions.

The total amount of heat in the three-dimensional room can be calculated using this triple integral.

We understand that triple integrals have several uses if "dimension" can refer to something other than a spatial dimension. We could determine a 3-D object's overall inertia or the gravitational attraction on a basketball.

The sum of an infinite number of rectangular prisms across a bounded region in three-space is a double integral, which represents the volume beneath the surface above the xy-plane.

[tex]$$To show that $\int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \sqrt{x^2+y^2+z^2} e^{-\left(x^2+y^2+z^2\right)} d x d y d z=2 \pi$, begin by converting the integral into spherical coordinates. Recall that $\rho^2=x^2+y^2+z^2$ and $d V=\rho^2 \sin \phi d \rho d \phi d \theta$. To convert the bounds, notice that as $x, y$, and $z$ expand infinitely in both directions, this can be modeled to a sphere of an infinite radius.\\$$[/tex]

[tex]$$This means that the new bounds become $0 \leq \rho \leq \infty, 0 \leq \phi \leq \pi$, and $0 \leq \theta \leq 2 \pi$. Because the integral is infinite, let the upper limit of $\rho$ be $R$ and take the limit as $R$ goes to infinity. To evaluate with respect to $\rho$, first use $u$ substitution by letting $u=\rho^2$ and then integrating by parts$$[/tex]

[tex]$\int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \sqrt{x^2+y^2+z^2} e^{-\left(x^2+y^2+z^2\right)} d x d y d z$[/tex]

[tex]& =\lim _{R \rightarrow \infty} \int_0^{2 \pi} \int_0 \int_0^R \sqrt{\rho^2} e^{-\left(\rho^2\right)} \rho^2 \sin \phi d \rho d \phi d \theta \\& =\lim _{R \rightarrow \infty} \int_0^{2 \pi} \int_0^\pi \int_0^R e^{-\rho^2} \rho^3 \sin \phi d \rho d \phi d \theta \\[/tex]

[tex]& =\lim _{R \rightarrow \infty} \int_0^{2 \pi} \int_0^2 \sin \phi\left[\frac{1}{2}\left(-e^{-\rho^2}\left(1+\rho^2\right)\right)\right]_{\rho=0}^{\rho-R} d \phi d \theta \\& =\frac{1}{2} \lim _{R \rightarrow \infty} \int_0^{2 \pi \pi} \int_0^\pi \sin \phi\left[-e^{-R^2}\left(1+R^2\right)+e^{-0^2}\left(1+0^2\right)\right] d \phi d \theta\end{aligned}$$[/tex]

[tex]$$\\\text{Use L' Hospital's Rule to simplify the limit}$$\begin{aligned}& \int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \sqrt{x^2+y^2+z^2} e^{-\left(x^2+y^2+z^2\right)} d x d y d z \\& =2 \pi(1)-2 \pi \lim _{R \rightarrow \infty}\left(\frac{2 R}{2 R e^{R^2}}\right) \\& =2 \pi-\lim _{R \rightarrow \infty} \frac{1}{e^{R^2}} \\& =2 \pi-0 \quad \text { As } \lim _{x \rightarrow \infty} \frac{1}{e^x}=0 . \\& =2 \pi\end{aligned}$$[/tex]

[tex]$$Therefore,$$\int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \int_{-\infty}^{\infty} \sqrt{x^2+y^2+z^2} e^{-\left(x^2+y^2+z^2\right)} d x d y d z=2 \pi$$[/tex]

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The scale factor of the dilated pentagon is the ratio of the side length of the original pentagon to the side length of the dilated pentagon.

In this case, the side length of the original pentagon is 5 and the side length of the dilated pentagon is 1. Therefore, the scale factor is 5:1 or 5/1. To calculate the scale factor, divide the side length of the original pentagon by the side length of the dilated pentagon. In this case, the calculation would be 5 / 1 = 5. The scale factor of the dilated pentagon is 5.

We can also use the formula for finding the scale factor of two figures: Scale Factor = Length of figure 1 / Length of figure 2. In this case, the length of figure 1 is 5 and the length of figure 2 is 1. So, the scale factor is 5.

Therefore, the scale factor of the first pentagon to the second pentagon is 5.

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The randomly number of the students who got selected  are 4,5,6,7,.......

Professor randomly select the fourth and every  student after that

Now  by using the next  term formula which is

=>a + d(n-1)

The next student is the 2nd student.

=>4 + 1*(2-1)

=>4 + (1)

=>4 + 1

=> 5

The 3rd student will be

=>4 + 1(3-1)

=>4 + 1(2)

=>4 + 2

=> 6

The 4th student will be

=>4 + 1(4-1)

=>4 + 1(3)

=> 4+ 3

=> 7

students numbers are 4,5,6,7......

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The value of the voltage (E) is given as 33 + 48i

An equation is an expression showing the relationship between numbers and variables.

Given the equation:

E = IZ

Where E is the voltage, I is the current and Z is the impedance.

But I = 5 + 2i, Z = 9 + 6i, substituting the values gives:

E = IZ

E = (5 + 2i)(9 + 6i)

E = 45 + 30i + 18i - 12

E = 33 + 48i

The value of E is 33 + 48i

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The function:

f(x) = 1/x

Does not has 0 on its domain, then the domain is not R, that is why the function is not from R to R.

A function from R to R is a function where the domain is the set of all real numbers and the range is also the set of all real numbers.

Here the given function is rational, and it is:

f(x) = 1/x

Remember that we can't divide by zero, so the input x = 0 can't be on the domain of function f(x).

Thus, the domain is not the set of all real numbers.

That is why the function f is not from R to R, because the domain is not R.

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The line touches -x axis at 3 and touches y axis at 3

P(x,y) = (-3,3)

α+ β = -3

α β = 3

Answer:

I believe the answer may be 31.5cm.

Step-by-step explanation:

I first found the area of the total region which was 70cm. From there I found the area of the triangle to the left of the region by doing 6x7 which is 42, and multiplied by 1/2 because it is a triangle. I did the same to the triangle on the right, doing 5x7 which is 35, and multiplied by 1/2 since this is also a triangle. Finally, I subtracted both totals of 21, and 17.5 from the 70, getting a grand total of 31.5cm.

Answer:

31.5 cm²

Step-by-step explanation:

To find the area of the crossed region, subtract the areas of the two triangles from the area of the rectangle.

Formulae:

Area of the rectangle

⇒ A = (4 + 6) × 7

⇒ A = 10 × 7

⇒ A = 70 cm²

Area of triangle 1

⇒ A = ¹/₂ × 6 × 7

⇒ A = 3 × 7

⇒ A = 21 cm²

Area of triangle 2

⇒ A = ¹/₂ × 5 × 7

⇒ A = 2.5 × 7

⇒ A = 17.5 cm²

Area of the crossed region

⇒ A = 70 - 21 - 17.5

⇒ A = 49 - 17.5

⇒ A = 31.5 cm²

The firm's accounting profit earnings as required to be determined in the task content is; $0.

As evident in the task content, the firm produces 275,000 units a year and sells them all for $8 each.

Therefore, the total revenue generated from sales is; 275,000 × $8 = $2,200,000.

Hence, since the total cost is the sum of $1,800,000 and $400,000 which is; $400,000 + $1,800,000 = $2,200,000.

Ultimately, the total accounting profit earned is; Revenue generated - Expenses = $2,200,000 - $2,200,000 = $0.

Therefore, the total accounting profit earned is; $0.

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The span of the two vectors is the set of all linear combinations of the two vectors. This means that any point on the line through u and the origin, as well as any point on the line through v and the origin, can be written as a linear combination of u and v.

1. Start by taking two non-zero vectors u and v.

2. The span of the two vectors is the set of all linear combinations of the two vectors, which means that any point on the line through u and the origin, as well as any point on the line through v and the origin, can be written as a linear combination of u and v.

3. Therefore, span{u, v} contains the line through u and the origin, as well as the line through v and the origin.

The span of two non-zero vectors u and v contains the line through u and the origin, as well as the line through v and the origin. Any point on these two lines can be written as a linear combination of u and v.

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The equation 4x+8=4(x+4)−8 can be simplified by distributing the 4 on the right side of the equation:

4x+8=4x+16-8

Subtracting 4x from both sides:

8=16-8+8

Which simplifies to:

8=8

This is a true statement, so x could be any real number. The solution to the equation is x is any real number or x∈R.

Answer:

The answer is 1.04

Step-by-step explanation

For 1.04, 4 is in the hundredths place, and 0 is in the tenths place.

Extreme values are present in a set of data in business. which of the following descriptive summary measures are most appropriate interquartile range and median.

Range is the maximum easy and normally comprehensible measures of dispersion. Range is described because the distinction among the highest (or largest) and lowest (or smallest) determined fee in a series. Therefore, it's miles the maximum affected measures of dispersion via way of means of the acute values of the series.

The median offers the best weight to factors withinside the center of the ordered records. When there are intense numbers withinside the records set (very low or very excessive numbers), the median is a great data preference for a degree of principal tendency.

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Tony walked 7/10 km which in decimal will be 0.7 km

Volet spent 0.5 hrs reading a pocket which in Fraction will be 5/10 = 1/2

Any number of equal parts is represented by a fraction, which also represents a portion of a whole. A fraction, such as one-half, eight-fifths, or three-quarters, indicates how many components of a particular size there are when stated in ordinary English.

An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a correct fraction is smaller than the denominator.

The three main sorts of fractions are as follows. Proper fractions, improper fractions, and mixed fractions are these three types. The expressions with a numerator and a denominator are called fractions. We categorize its kinds based on these two parameters.

Tony walked 7/10 km which in decimal will be 0.7 km

Volet spent 0.5 hrs reading a pocket which in Fraction will be 5/10 = 1/2

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If s and t are integers greater than 1 and each is a factor of the integer n, then the product nst must be divisible by both s and t. This is because s and t are factors of n, which means that n is divisible by s and t.

The product of two integers is divisible by the factors of each of those integers. Therefore, since n is divisible by s and t, and nst is the product of n, s, and t, nst must also be divisible by s and t. This can be proven by the definition of divisibility: if a number, in this case n, is divisible by an integer, in this case s or t, then the product of that number and another integer, in this case t or s, is also divisible by the initial integer.

For example, if n = 24, s = 4, and t = 3, we can see that 4 and 3 are factors of 24, since 24 is divisible by 4 and 3. The product of 24, 4 and 3 is 2443 = 288. 288 is also divisible by 4 and 3.

In summary, if s and t are integers greater than 1 and each is a factor of the integer n, then s and t must be factors of nst.

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The value of Q (1/4) as required to be determined in the task content is; 10 ½.

It follows from the task content that the value of the function instance Q (1/4) is to be determined based on the given function definition; Q(x)=8x^2+10.

Hence, since the given function is; Q (x) = 8x² + 10.

The function instance Q (1/4) can be evaluated as follows;

Q (1/4) = 8 ( 1/4 )² + 10

= 8 • 1/16 + 10

= 1/2 + 10

= 10 ½.

Ultimately, the value of the function instance Q (1/4) is; 10 ½.

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