(1) D
[tex]L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt[/tex]
Integrate by parts, taking
[tex]u = t \implies \mathrm du=\mathrm dt[/tex]
[tex]\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}[/tex]
Then
[tex]L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}[/tex]
[tex]L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}[/tex]
(2) A
[tex]L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt[/tex]
[tex]L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}[/tex]
[tex]L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}[/tex]
What is the distance from point Yto wx in the figure below?
W 16 Z
30
X
1612
34
O A. 4
O B. 162
O C. 16
O D. Cannot be determined
E. 16/3
F. 8
The length of YZ in the similar triangle given is calculated using Pythagoras theorem which gave us 16√3
What are Similar TriangleSimilar triangles are two or more triangles that have the same shape but may be different sizes. They have the same angles and corresponding sides that are proportional.
In this problem, we need to use the concept of ratio and proportions to find the length of YZ
However, we can simply use Pythagoras theorem to determine the length.
According to Pythagoras' Theorem, the square of the hypotenuse, or side opposite the right angle, in a right-angled triangle, is equal to the sum of the squares of the other two sides.
It is expressed as the equation a² + b² = c².
This is because the triangles forms a right angled triangle and we can easily apply that here.
YZ² = 16² + (16√2)²
YZ² = 768
YZ = √768
YZ = 16√3
The length or distance from point Y to WX which is the same as the length of YZ is calculated as 16√3.
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Answer:
C. 16
Step-by-step explanation:
I hope this helps :)
50T Q12 A man wants to buy bags of gravel to cover his driveway. He decides to work out the area of his driveway. 1 bag of gravel covers 14m2 3m Sketch of driveway Not to scale 3m 8m 6m What is the area of his driveway? How many bags of gravel must he buy?
Answer:
hi amki nai patajjdkfkejd
3 lawns in 9 hours.what was the rate of mowing in hours per lawn
Answer:
3
Step-by-step explanation:
3 = 9 \:th \\ 1 = 3 \\ 3 \times 3 = 9 \\ 9 \div 3 = 3 \\ so \: that \: answer \: is \: 3
What is the image of (3, -12) after a dilation by a scale factor of į centered
at the origin?
Answer:
9 is. ................m.m..mk
the art club held a show for 2 days a total 269 people attended the show. On the second day, 15 more people attended than had come to the show the first day how many people attended on the first day?
Answer:
127 peopleStep-by-step explanation:
Number of attendees the first day = x.
Solve the following equation for x:
x + (x + 15) = 2692x = 269 - 152x = 254x = 254/2x = 127Are 3(3x - y) and 12 ( x - 4y ) equivalent expression?
Answer:
No, they are not.
Step-by-step explanation:
If you distributed 12(x - 4y), you would get 12x - 48y. If you distributed 3(3x-y), you would get 9x- 3y. 12x - 48y and 9x - 3y are not equivalent. Hope this helped!
If only the height of a pyramid is doubled its volume is Also doubled true or false
Answer: true
Step-by-step explanation:
Which equation has the same solution as 10(x) - x + 5 = 41
Step-by-step explanation:
if that is truly the full problem description, then we have
10x - x + 5 = 41
=>
9x = 36
our simply
x = 4
so, I am not sure, what your teacher wants to see as result.
there is an infinite number of equations I could find, all with the solution x = 4.
Question for the kids orrr?
Answer:
B. 18 sq in.
Step-by-step explanation:
Surface area of the triangular pyramid excluding the base = area of the three triangular faces = 3(½ × base × height)
Where,
base = 3 inches
height = ED = 4 inches
Plug in the known values into the equation
Surface area of the triangular pyramid excluding the base = 3(½ × 3 × 4)
= 3(3 × 2)
= 3(6)
= 18 sq in.
If 10 wholes are divided into pieces that are one half of a whole each how many pieces are there?
9514 1404 393
Answer:
20
Step-by-step explanation:
A whole can be divided into two pieces that are each 1/2 of the whole.
(10 wholes) × (2 pieces per whole) = 20 pieces
Solve the equation by graphing. If integral roots cannot be found, estimate the roots by stating the consecutive integers between which the roots lie. -2p2=12p+15
9514 1404 393
Answer:
roots are between -5 and -4, and between -1 and -2.
Step-by-step explanation:
The graph shows the roots are approximately ...
-4.2 — between -5 and -4
-1.8 — between -2 and -1
What is |1-8i|?
A.
B.
C
D
9514 1404 393
Answer:
(b) √65
Step-by-step explanation:
The modulus of a complex number is the root of the sum of the squares of the real and imaginary parts.
|1 -8i| = √(1² +(-8)²) = √(1+64) = √65
Use AABC to find the value of sin B.
Answer:
35/37
Step-by-step explanation:
sin(B)=(AC)/(AB) = 35/37
Help please. I need the answer
Answer:
y=-2/3x+6
Step-by-step explanation:
Graph it
Answer:
y= -2/3 x + 6
Step-by-step explanation:
1. In the graph, you can see the points (0,6) and (6,2)
2. Since you have all the available options, you can input both points into all equations.
3. In this case, the correct answer is y= -2/3 x + 6
Simplify Square root (150n^2)
Answer:
12
Step-by-step explanation:
What is the domain of the following function?
Answer:
the domain is all real numbers except x=3
Step-by-step explanation:
The domain is the values that x can take
X can be all real number except when the denominators equal zero
x-3 ≠ 0
x≠3
the domain is all real numbers except 3
Tìm diện tích của mặt. Phần mặt x2+y2+z2=9 nằm bên trên mặt phẳng z=1.
If you're familiar with surface integrals, start by parameterizing the surface by the vector-valued function,
r(u, v) = 3 cos(u) sin(v) i + 3 sin(u) sin(v) j + 3 cos(v) k
with 0 ≤ u ≤ 2π and 0 ≤ v ≤ arccos(1/√8).
Then the area of the surface (I denote it by S) is
[tex]\displaystyle\iint_S\mathrm dA = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}\left\|\dfrac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm dv\,\mathrm du \\\\ = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}9\sin(v)\,\mathrm dv\,\mathrm du \\\\ =18\pi \int_0^{\arccos\left(1/\sqrt8\right)}\sin(v)\,\mathrm dv = \boxed{\frac{9(4-\sqrt2)\pi}2}[/tex]
A company produces 2 types of computers; desktops and laptops
Answer:
?
Step-by-step explanation:
Help me please --------------------
9514 1404 393
Answer:
139.39 in
Step-by-step explanation:
The length of a semicircle of diameter D is ...
C = (1/2)πD
For the given diameter of 27 inches, the length of the curved edge of the figure is ...
C = 1/2(3.14)(27 in) = 42.39 in
__
The perimeter of the figure is the sum of the side lengths. Clockwise from left, that sum is ...
P = 27 + 35 + 42.39 + 35 = 139.39 . . . inches
The perimeter of the figure is 139.39 inches.
A store spends $10 for each pair of Brand X jeans and adds a 120% markup to the cost. What is the selling price of the jeans? (circle one)
Answer:
12
Step-by-step explanation:
120 divided by 100 =1.2 x 10
The BBQ club meets every Thursday. The meetings last 2 1/2 hours. There were 5 Thursdays in
September. How many hours did the BBQ club meet in September?
A.2 1/2 hours
B.5 hours
C.12 1/2 hours
D.10 hours
Answer:
12 1/2
Step-by-step explanation:
2 x 5 = 10
1/2 x 5 = 2 1/2
10 + 2 1/2 = 12 1/2
a woman has two boards one is two times as long as the other together the two boards equal 9 ft what is the length of the shortest board
Answer:
3 feet
Step-by-step explanation:
Let x represent the length of the shortest board.
Since the other is two times as long, its length can be represented by 2x.
Create an equation to represent the situation, and solve for x:
x + 2x = 9
3x = 9
x = 3
So, the shortest board is 3 feet long
find each measurement indicated round your answers to the nearest tenth. Part 1d. NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!!
Answer:
see explanation
Step-by-step explanation:
Using the Sine rule in all 3 questions
(1)
[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values , firstly calculating ∠ B
[ ∠ B = 180° - (78 + 49)° = 180° - 127° = 53° ]
[tex]\frac{a}{sin78}[/tex] = [tex]\frac{18}{sin53}[/tex] ( cross- multiply )
a sin53° = 18 sin78° ( divide both sides by sin53° )
a = [tex]\frac{18sin78}{sin53}[/tex] ≈ 22.0 ( to the nearest tenth )
(3)
[tex]\frac{c}{sinC}[/tex] = [tex]\frac{a}{sinA}[/tex] , substitute values
[tex]\frac{35}{sinC}[/tex] = [tex]\frac{45}{sin134}[/tex] ( cross- multiply )
45 sinC = 35 sin134° ( divide both sides by 35 )
sinC = [tex]\frac{35sin134}{45}[/tex] , then
∠ C = [tex]sin^{-1}[/tex] ( [tex]\frac{35sin134}{45}[/tex] ) ≈ 34.0° ( to the nearest tenth )
(5)
Calculate the measure of ∠ B
∠ B = 180° - (38 + 92)° = 180° - 130° = 50°
[tex]\frac{a}{sinA}[/tex] = [tex]\frac{b}{sinB}[/tex] , substitute values
[tex]\frac{BC}{sin38}[/tex] = [tex]\frac{10}{sin50}[/tex] ( cross- multiply )
BC sin50° = 10 sin38° ( divide both sides by sin50° )
BC = [tex]\frac{10sin38}{sin50}[/tex] ≈ 8.0 ( to the nearest tenth )
A lottery ticket has a grand prize of $30.1 million. The probity of winning the grand prize is .000000038
Deteman the expected value of the lottery ticket
Answer:
$30.1 million * .000000038
$1.14
did the question say how much the ticket cost?
if it was $1 then you would have to subtract $1 so the expected value would be 14 cents
Step-by-step explanation:
p(X)=x²+50 then p(2)=
a) 6
b)7
c)8
d)9
Answer:
54
Step-by-step explanation:
p(x)=x^2+50, p(2)=2^2+50=54
P(x) = x² + 50
P(2) = 2² + 50
= 54
P(6) = 6²+50
= 86
P(7) = 7²+ 50
= 99
P(8) = 8²+50
= 114
P(9) = 9²+50
= 131
Answered by Gauthmath must click thanks and mark brainliest
72a^7/-9 as a monomial
Answer:
− 8 a ^7
Step-by-step explanation:
See picture for steps :)
Change to cylindrical coordinates. 3∫−3 9-x^2∫0 9−x^2-y^2∫x^2+y^2 dz dy dx
I think the given integral reads
[tex]\displaystyle \int_{-3}^3 \int_0^{9-x^2} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]
In cylindrical coordinates, we take
x ² + y ² = r ²
x = r cos(θ)
y = r sin(θ)
and leave z alone. The volume element becomes
dV = dx dy dz = r dr dθ dz
Then the integral in cylindrical coordinates is
[tex]\displaystyle \boxed{\int_0^\pi \int_0^{(\sqrt{35\cos^2(\theta)+1}-\sin(\theta))/(2\cos^2(\theta))} \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta}[/tex]
To arrive at this integral, first look at the "shadow" of the integration region in the x-y plane. It's the set
{(x, y) : -3 ≤ x ≤ 3 and 0 ≤ y ≤ 9 - x ²}
which is the area between a paraboloid and the x-axis in the upper half of the plane. So right away, you know θ will fall in the first two quadrants, so that 0 ≤ θ ≤ π.
Next, r describes the distance from the origin to the parabola y = 9 - x ². In cylindrical coordinates, this equation changes to
r sin(θ) = 9 - (r cos(θ))²
You can solve this explicitly for r as a function of θ :
r sin(θ) = 9 - r ² cos²(θ)
r ² cos²(θ) + r sin(θ) = 9
r ² + r sin(θ)/cos²(θ) = 9/cos²(θ)
(r + sin(θ)/(2 cos²(θ)))² = 9/cos²(θ) + sin²(θ)/(4 cos⁴(θ))
(r + sin(θ)/(2 cos²(θ)))² = (36 cos²(θ) + sin²(θ))/(4 cos⁴(θ))
(r + sin(θ)/(2 cos²(θ)))² = (35 cos²(θ) + 1)/(4 cos⁴(θ))
r + sin(θ)/(2 cos²(θ)) = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))]
r = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))] - sin(θ)/(2 cos²(θ))
Then r ranges from 0 to this upper limit.
Lastly, the limits for z can be converted immediately since there's no underlying dependence on r or θ.
The expression above is a bit complicated, so I wonder if you are missing some square roots in the given integral... Perhaps you meant
[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]
or
[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{\sqrt{9-x^2-y^2}} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]
For either of these, the "shadow" in the x-y plane is a semicircle of radius 3, so the only difference is that the upper limit on r in either integral would be r = 3. The limits for z would essentially stay the same. So you'd have either
[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]
or
[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{\sqrt{9-r^2}} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]
can someone help me pls
Answer:
D NO IS THE WRITE ANSWER .
Answer:
D)
Step-by-step explanation:
Find the length of the arc.
A. 21/π4 in
B. 18π in
C. 45/π8 in
D. 1890π in
Answer:
we know that all Lenght of circle is 2πr so 2*π*7=14π
Step-by-step explanation:
14π equal to 360°
but we need just 135° so we should write it kind of radian(π)
if 14π=360°
x=135°
14π*135=360°*x 14π*27=72*x ........= 14π*3=8*x
7π*3=4*x ....... X=21π/4
The length of the arc is 21/π4 in
An answer is an option A. 21/π4 in
What is the arc of the circle?The arc period of a circle can be calculated with the radius and relevant perspective using the arc period method.
⇒angle= arc/radius
⇒ 135°=arc/7
⇒ arc =135°*7
⇒arc=135°*π/180° *7in
⇒arc = 21/π4 in
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Which inequality is true?
O A. 1 2 > 2
OB. 8 - T > 5
O C. 1071 > 30
O D. 1+4<7
Answer:
true
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
A
[tex]\frac{12}{2\pi }[/tex] ≈ 1.91 < 2
B
8 - π 8 - 3.14 = 4.86 < 5
C
10π ≈ 31.42 > 30 ← True
D
π + 4 = 3.14 + 4 = 7.14 > 7
Option C is a true inequality