what is john locke's ideas that affected government?

Answers

Answer 1

John Locke's ideas related to government focus on the separation of powers and respect for the individual rights of citizens.

Who was John Locke?

John Locke (1632-1704) was a British philosopher who stands out as one of the most important thinkers in history in the field of political philosophy, English empiricism, and classical liberalism.

What were his outstanding ideas?

Some of the most popular and important postulates of John Locke were:

The State's main mission is to protect the three natural rights: life, liberty and private property.Individuals have a fourth right, the right to defend these rights, as well as any other individual freedom of citizens.The citizen cedes some rights to the State through a written consensus or constitution.The government must be made up of a king and a parliament. Parliament is where popular sovereignty is expressed and where laws are made that must be followed by both the king and the people.He described the separation of legislative and executive power.The authority of the State is sustained by the principles of popular sovereignty and legality.Power is not absolute but must respect human rights.

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Related Questions

B. Study the figure on the right.
1. Name the points on it
2 Name any three segments from the figure,
3. Which segments have B as one endpoint?
4. Which points are endpoints of only two segments?
5. Which points are endpoints of three segments?
6. Which point is the endpoint of six segments?
7. Name the lines with A as one of the points on them.
8. Name any three rays from the figure, 9. How many segments are there in the figure?
10. How many rays can be named from the figure?​

Answers

Answer:

can you clear more I don't understand

1. Find the equation of a line passing through the points (1,-2) and (-3,10).​

Answers

Answer:

Step-by-step explanation:

(1 , -2)   x₁ =1 & y₁ = -2

(-3,10)  x₂= -3 & y₂ = 10

First we need to find the slope.

[tex]\boxed{Slope = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$}[/tex][tex]\boxed{Slope=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}[/tex]

          [tex]=\dfrac{10-[-2]}{-3-1}\\\\\\=\dfrac{10+2}{-4}\\\\\\=\dfrac{12}{-4}\\\\\\= - 3[/tex]

m = -3

Equation of the line: y = mx + b

y = -3x + b

To find the value of b, take one of the point and substitue in the above equaiton.

(1 , -2)

-2 = -3*1 + b

-2 = -3 + b

-2 + 3 = b

b = 1

Equation of the line:

y = -3x + 1

PLEASE HELP I ILL MARK BRAINLIEST

Answers

Answer: 90 dergrees

Step-by-step explanation: 90 dergrees

What is the area of this figure?

Answers

Answer:

through lengthy mafs, your answer should be 307 mi (wrong somehow)

Step-by-step explanation:

if you want an explanation, please, dont be afraid to comment ;)

(to other people who look this up the answer is actually 318 i dont know, but i got it wrong

-3y (y⁴ + 2y³ - 5y²- y + 4)​

Answers

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's expand the given expression ~

[tex]\qquad \sf  \dashrightarrow \: - 3y( {y}^{4} + 2 {y}^{3} - 5 {y}^{2} - y + 4)[/tex]

[tex]\qquad \sf  \dashrightarrow \: ( - 3y \cdot {y}^{4} ) + ( - 3y \cdot2 {y}^{3} ) + ( - 3y \cdot - 5 {y}^{2} ) + ( - 3y \cdot - y) + ( - 3y \cdot4)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 3{y}^{5} - 6{y}^{4} + 1 5 {y}^{3} + 3{y}^{2} - 12y[/tex]

Drew has a coin: one side shows heads and the other side shows tails. he also has a six-sided number cube with a number, 1 through 6, on each side. he flips the coin, rolls the number cube, and records his results. what is the probability, written as a fraction, that the coin shows tails and he rolls a 5?

Answers

Using it's concept, it is found that the probability that the coin shows tails and he rolls a 5 is of [tex]\frac{1}{12}[/tex].

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, the coin has two outcomes, one of which is tails, while the number cube has six outcomes, one of which is five. Since the coin and the number cube are independent, we just multiply the probabilities, hence:

[tex]p = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}[/tex]

The probability that the coin shows tails and he rolls a 5 is of [tex]\frac{1}{12}[/tex].

More can be learned about probabilities at https://brainly.com/question/14398287

help!
this is urgent
i need it rn
ty in advance

Answers

Answer:

The graph shows a steady declining plot as the aveage traffic volume increases. Since y axis is speed the correct answer is that as traffic volume increases the average vehicle speed decreases.

Step-by-step explanation:

I need help please, Its for today

Answers

Answer:

a) 1,2; 3.4

b) <1=<6, <6+<6+72=180, 2<6=108, <6=54.

<1=54

You can tell this by "these are parallel lines"

Carly and Carter are comparing bedrooms. They are each getting new carpet and are trying to figure out which room will be the most expensive to cover with carpet. (The rooms are both rectangular) Carly's bedroom is 15.3 ft. long and 8.7 ft. wide. Carter's bedroom is 14.4 ft. long and 9.6 ft. wide. Which bedroom will be the most expensive to cover with carpet? Explain your steps for figuring out the area of the floor for each bedroom and determining your answer. Make sure to Show your math steps as well. ~ 100 POINTS AND ILL GIVE YOU BRAINLIEST IF YOU ANSWER CORRECTLY AND 5 SENTENCES NEEDED

Answers

If Carly's bedroom is 15.3ft long and 8.7 ft long then it is necessary to multiply them because you need to find the area of the room so 15.3*8.7= 133.11. We have to do the same for Carter's room so we multiply 14.4 and 9.6 to find the area of the room which is 138.24.

Now that we have both the areas we can compare which room is bigger. Carly's room is 133.11 ft in total and Carter's room is 138.24 ft in total. So it is clear that Carter's room is going to be more expensive to cover with carpet since Carter's room is bigger than Carly's.

Carly:-

L=15.3B=8.7

Area:-

LB15.3(8.7)133.11ft^2

#Carter

L=14.4B=9.6

Area:-

14.4(9.6)138.24ft^2

Carter's room is expensive


x/-6-8> -12

PLEASE HELP AND SOLVE

Answers

Answer:

24

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

x=24

Help me











Question
Find mHK⌢.

Answers

Answer:

62

Step-by-step explanation:

(x+8)=(2x-15)
8=x-15
+15   +15
23=x

so


23 +8 = 31
23x2-15 = 46-15 =31
Both are the same always since one side is equal to the other
Therefore
62 is the answer!

Find the area of the composite figure.

A: 96.75 units2
B: 112.5 units2
C: 139.5 units2
D: 192

Answers

The area of the composite figure from the image attached is 112.5 units²

What is the area of a composite figure?

The area of a composite figure refers to the sum total of all the areas of the shapes in that composite figure. This can be done by first identifying the shapes in that composite figure, then finding each area, followed by the addition of all the areas to determine the area of the composite figure.

From the given figure; we can break it down into:

A parallelogramA rectangleA triangle

The area of a parallelogram = b × h

where;

b & h refers to the length of the two opposite diagonal lines.

The area of a parallelogram =  9 × 6

The area of a parallelogram = 54 units²

The area of a rectangle = Length × breadth

The area of a rectangle = (9 × 3) units²

The area of a rectangle = 27 units²

The area of the triangle [tex]\mathbf{=\dfrac{1}{2}\times b \times h}[/tex]

where;

Base = b Height = h

The area of the triangle [tex]\mathbf{=\dfrac{1}{2}\times b \times h}[/tex]

The area of the triangle [tex]\mathbf{=\dfrac{1}{2}\times 9 \times 7}[/tex]

The area of the triangle [tex]\mathbf{= 31.5 units^2}[/tex]

Therefore, the area of the composite figure is:

= 54 + 27 + 31.5

= 112.5 units²

Learn more about composite figures here:

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Hello ! Here's a calculus question!

Find that value of

[tex]\\ \rm\Rrightarrow {\displaystyle{\int\limits_{\pi}^{2\pi}}}\dfrac{sin^6x+cos^6x}{sin^3xcos^3x}[/tex]


Note:-

Answer must include all steps properly .

Kindly don't waste time here if you don't know the answer .

All the best !​

Answers

Answer:

Undefined.

Formula's used:

[tex]\longrightarrow \bold{sec(x) = \dfrac{1}{cos(x)} }[/tex]

[tex]\longrightarrow \bold{cosec(x) = \dfrac{1}{sin(x)} }[/tex]

[tex]\longrightarrow \bold{cot(x) = \dfrac{1}{tan(x)} }[/tex]

[tex]\longrightarrow \bold{tan(x) = \dfrac{sinx}{cos(x)} }[/tex]

[tex]\longrightarrow \bold{sin^2x + cos^2 x = 1 }[/tex]

[tex]\longrightarrow \sf \bold{Sum \ Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx}[/tex]

[tex]\longrightarrow \bold{ \int \:{sec^2(ax+b) = \dfrac{1}{a}tan(ax+b)+c }}[/tex]

[tex]\longrightarrow \bold{\int \:\dfrac{1}{ax+b} =\dfrac{1}{a} ln|ax+b|+c}[/tex]

Explanation:

[tex]\sf \Longrightarrow \int _{\pi }^{2\pi }\:\dfrac{sin^6(x)+cos^6(x)}{sin^3(x) \ * \ cos^3\left(x)}[/tex]

[tex]\sf \Longrightarrow \sf \int _{\pi }^{2\pi }\:\dfrac{sin^6\left(x\right)}{sin^3\left(x\right)\cdot \:cos^3\left(x\right)} +\dfrac{cos^6\left(x\right)}{sin^3\left(x\right)\cdot \:cos^3\left(x\right)}[/tex]

[tex]\Longrightarrow \sf \int _{\pi }^{2\pi }\:\dfrac{sin^3\left(x\right)}{\:cos^3\left(x\right)} +\dfrac{cos^3\left(x\right)}{sin^3\left(x\right)}[/tex]

                                                               

[tex]\Longrightarrow \sf \int _{\pi }^{2\pi }\ tan^3(x)+ cot^3(x)[/tex]

[tex]\sf \Longrightarrow \sf \int _{\pi }^{2\pi } \tan ^3(x)dx+\int _{\pi }^{2\pi } \cot ^3 (x)dx[/tex]

[tex]\Longrightarrow \sf \bold{ [ }-\ln |\sec \left(x\right) |+\dfrac{\sec ^2(x)}{2}-\dfrac{\cot ^2 (x)}{2}-\ln |\sin(x)| \bold{ ] }^{2\pi }_\pi[/tex]

apply limits

[tex]\sf \Longrightarrow \sf -\ln \left|\sec \left(2\pi \right)\right|+\dfrac{\sec ^2\left(2\pi\right)}{2}-\dfrac{\cot ^2\left(2\pi\right)}{2}-\ln \left|\sin \left(2\pi\right)\right|-(-\ln \left|\sec \left(\pi \right)\right|+\dfrac{\sec ^2\left(\pi\right)}{2}-\dfrac{\cot ^2\left(\pi\right)}{2}-\ln \left|\sin \left(\pi\right)\right|)[/tex]

simplify using trigonometric basic functions

[tex]\Longrightarrow \sf -\ln \left|\dfrac{1}{\cos \left(2\pi \right)}\right|+\dfrac{\left(\dfrac{1}{\cos \left(2\pi \right)}\right)^2}{2}-\dfrac{\cot ^2\left(2\pi \right)}{2}-\ln \left|\sin \left(2\pi \right)\right|- ( -\ln \left|\dfrac{1}{\cos \left(\pi \right)}\right|+\dfrac{\left(\frac{1}{\cos \left(\pi \right)}\right)^2}{2}-\dfrac{\cot ^2\left(\pi \right)}{2}-\ln \left|\sin \left(\pi \right)\right|)[/tex]

The value of cot(2π) is not defined. [ cot(2π) = ∞ ]

⇒  Undefined

Answer:

[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \boxed{\text{un} \text{de} \text{f}}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

DerivativesDerivative Notation

Integration

Integrals

Integration Rule [Reverse Power Rule]:
[tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:
[tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:
[tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Methods: U-Substitution + U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx[/tex]

Step 2: Integrate Pt. 1

[Integrand] Rewrite:
[tex]\displaystyle \frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x} = \frac{\sin^6 x}{\sin^3 x \cos^3 x} + \frac{\cos^6 x}{\sin^3 x \cos^3 x}[/tex][Integrand] Simplify:
[tex]\displaystyle \frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x} = \tan^3 x + \cot^3 x[/tex][Integrand] Rewrite:
[tex]\displaystyle \frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x} = \tan x (\sec^2 x - 1) + \cot x (\csc^2 x - 1)[/tex]


Step 3: Integrate Pt. 2

[Integral] Rewrite:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{2 \pi}_{\pi} {\tan x (\sec^2 x - 1) + \cot x (\csc^2 x - 1)} \, dx[/tex][Integral] Rewrite [Integration Property - Addition/Subtraction]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{2 \pi}_{\pi} {\tan x (\sec^2 x - 1)} \, dx + \int\limits^{2 \pi}_{\pi} {\cot x (\csc^2 x - 1)} \, dx[/tex]

Step 4: Integrate Pt. 3

Identify variables for u-solve.

1st Integral

Set u:
[tex]\displaystyle u = \sec x[/tex][u] Apply Trigonometric Differentiation:
[tex]\displaystyle du = \sec x \tan x \, dx[/tex][du] Rewrite:
[tex]\displaystyle dx = \frac{1}{\sec x \tan x} \, du[/tex]

2nd Integral

Set v:
[tex]\displaystyle v = \csc x[/tex][v] Apply Trigonometric Differentiation:
[tex]\displaystyle dv = - \cot x \csc x \, dx[/tex][dv] Rewrite:
[tex]\displaystyle dx = \frac{-1}{\cot x \csc x} \, dv[/tex]

Step 5: Integrate Pt. 4

[Integrals] Apply Integration Method [U-Solve]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{x = 2 \pi}_{x = \pi} {\frac{\tan x (\sec^2 x - 1)}{\sec x \tan x}} \, du + \int\limits^{x = 2 \pi}_{x = \pi} {\frac{- \cot x (\csc^2 x - 1)}{\cot x \csc x}} \, dv[/tex][Integrals] Simplify:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \int\limits^{x = 2 \pi}_{x = \pi} {\frac{u^2 - 1}{u}} \, du - \int\limits^{x = 2 \pi}_{x = \pi} {\frac{v^2 - 1}{v}} \, dv[/tex][Integrals] Apply Integration Rule [Reverse Power Rule]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \frac{u^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \int\limits^{x = 2 \pi}_{x = \pi} {\frac{1}{u}} \, du - \Bigg( \frac{v^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \int\limits^{x = 2 \pi}_{x = \pi} {\frac{1}{v}} \, dv \Bigg)[/tex][Integrals] Apply Logarithmic Integration:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \frac{u^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \ln | u | \bigg| \limits^{x = 2 \pi}_{x = \pi} - \Bigg( \frac{v^2}{2} \bigg| \limits^{x = 2 \pi}_{x = \pi} - \ln | v | \bigg| \limits^{x = 2 \pi}_{x = \pi} \Bigg)[/tex]Back-Substitute variables u and v:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \frac{\sec^2 x}{2} \bigg| \limits^{2 \pi}_{\pi} - \ln | \sec x | \bigg| \limits^{2 \pi}_{\pi} - \Bigg( \frac{\csc^2 x}{2} \bigg| \limits^{2 \pi}_{\pi} - \ln | \csc x | \bigg| \limits^{2 \pi}_{\pi} \Bigg)[/tex]Simplify:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \bigg( \ln | \csc x | - \ln | \sec x | + \frac{\sec^2 x - \csc^2 x}{2} \bigg) \bigg| \limits^{2 \pi}_{\pi}[/tex]Apply Integration Rule [Fundamental Theorem of Calculus 1]:
[tex]\displaystyle \int\limits^{2 \pi}_{\pi} {\frac{\sin^6 x + \cos^6 x}{\sin^3 x \cos^3 x}} \, dx = \boxed{\text{un} \text{de} \text{f}}[/tex]

∴ we have found the value of the given integral.

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

omg please help its due by 12 am! the sum of 2 numbers is 69. the larger number is 3 less than twice the smaller number .find the numbers. show your work!

Answers

Answer:

The smaller number is 24

The larger number is 45

Step-by-step explanation:

smaller number  = x

Larger: 2x - 3

Smaller + larger = 69

x + 2x - 3 = 69                        Combine left

3x - 3 = 69                              add 3 to both sides

3x - 3+3 = 69+ 3                     Combine

3x = 72                                    Divide by 3

3x/3 = 72/3                        

x = 24

Larger number = 2*24 - 3

Larger number = 45

What is the answer to this?

Answers

Answer:

0.216 cubic feet

Step-by-step explanation:

v = lwh (volume = length times width times height)

v = 0.6 x 0.6 x 0.6  OR 0.6^3

v = 0.216

Use the picture I provided to help me answer the math problem.

Answers

Part A

25%/100%1/4

Part B

1 → 20 pieces 4 → (20*4) pieces 4 → 80 pieces of yellow paper

Answer:

See below ↓↓

Step-by-step explanation:

Part A

We have to write 25% as a rate per 100⇒ We know percentages are given to be the fraction of a number out of 100⇒ Therefore, 25% as rate per 100 = 25/1001/4 [simplified]

Part B

Let's take the total number of pieces of colored paper to be TThen 25% of T is 20Therefore our equation will be :⇒ T x 25/100 = 20Bring 100 to the other side⇒ 25T = 200025 is a factor of both 25 and 2000, so it cancels out, and we are left with :⇒ T = 80There are 80 pieces of paper

what is 3 × 2/7 in lowest terms​

Answers

Answer:

6/7

Step-by-step explanation:

3x2/7 in the same as 3/1x2/7, which is 6/7

(simply multiply the denominator and numerator of the fraction)

Answer: hii <3

Exact Form:

6/7

Decimal Form:

0.857142

Step-by-step explanation:

Simplify the expression.

Hopefully this helps you

- Matthew

A box of chocolates contains five milk chocolates, five dark chocolates, and three white chocolates. You randomly select and eat three chocolates. The first piece is milk chocolate, the second is white chocolate, and the third is milk chocolate.

Answers

Answer:

2/7

Step-by-step explanation:

Total no. of chocolates in the box =14

No. of dark Chocolates=4

No. of white chocolates=5

No. of milk chocolates=5

Probability of getting a white chocolate

= No. of possible outcomes /Total No. of outcomes

=5/14

Probability of getting a dark chocolate =4/14=2/7

Expand & simplify
4
(
2
g
+
3
)

5
(
4
g

4
)

Answers

Answer:

-12g+32

Simplify and combine like terms.

pleaseee help (questions in photo) will mark brainliest

Answers

Answer:

270

Step-by-step explanation:

90, 180, 270, and 360 are standard position because they hold a part of a 90 angle

Answer:

Step-by-step explanation:

Standard position means that you will move clockwise about the origin to create the angle.

PLEASE HELP


Select the statements that are true.
O Correlation coefficients must be between 0 and 1.
Correlation coefficients must be between - 1 and 1
A correlation coefficient of r = 0.92 indicates a strong, positive correlation.
A correlation coefficient of r = 0.01 means there is no significant correlation.
A correlation coefficient of r = 0.17 indicates a strong, negative correlation.
Correlation coefficient is a numeric measure of the strength and the direction between two quantative variables.

Answers

Correlation measures the relationship between variables

The true statements are:

Correlation coefficients must be between - 1 and 1A correlation coefficient of r = 0.92 indicates a strong, positive correlation.Correlation coefficient is a numeric measure of the strength and the direction between two quantative variables.

How to determine the true statements?

For a correlation coefficient to be valid, the following, must be true:

The value of the correlation coefficient must be between -1 and 1Correlation greater than 0 are positive correlationCorrelation closer to 1 and -1 are strong correlation

Using the above highlights, the true statements are: (b) (c) and (e)

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A certain brand of laundry detergent is manufactured for $4.40 and then marked up 25% by the local store before selling. The store offers a 30% discount with the purchase of three or more bottles of the detergent. Showing all work, determine the total cost, before tax, of three bottles of detergent. (10 points)

Answers

Using proportions, it is found that the total cost of three bottles of detergent is of $11.55.

What is a proportion?

A proportion is a fraction of a total amount.

A certain brand of laundry detergent is manufactured for $4.40 and then marked up 25% by the local store before selling, hence the price of each bottle is given by:

P = 4.40 x 1.25 = $5.50.

The store offers a 30% discount with the purchase of three or more bottles of the detergent, hence the total cost is given by:

T = (3 x 5.50) x 0.7 = $11.55.

More can be learned about proportions at https://brainly.com/question/24372153

(-4,9), (8,-7)
The endpoints of a diameter of a circle are given. Write the standard equation of the circle.

Answers

Answer:

(x-2)^2+(y-1)^2 = 10^2

(x-2)^2+(y-1)^2 = 100

Step-by-step explanation:

distance between points is diameter

x^2=  (8--4)^2+(-7-9)^2

x^2=12^2+16^2

x^2=144+256

x^2=400

diameter x=20 so radius =10

center point =midpoint (-4+8)/2 and (-7+9)/2

center point =(2,1)

(x-2)^2+(y-1)^2 = 10^2

(x-2)^2+(y-1)^2 = 100

Solve this Distributed property 2(3x+5)

Answers

Answer: x = -.6

Step-by-step explanation:

2(3x+5) = 6x + 10

10 = -6x

x = -.6

In a sequence of numbers, a5 = 30, a6 = 34, a7 = 38, a8 = 42, and a9 = 46.

Which equation can be used to find the nth term of the sequence?

A.) a,n = 4n + 10
B.) a,n = 4n + 30
C.) a,n = 6n + 30
D.) a,n = 6n

Answers

Answer:

A.)

Step-by-step explanation:

Try each choice to see which one works.

A.)

a_n = 4n + 10

a_5 = 4(5) + 10 = 30

a_6 = 4(6) + 10 = 34

a_7 = 4(7) + 10 = 38

Answer: A.)


Given conversion factor what is the above line segment's unit
1 ft
measure in inches? Round your answer to the nearest tenth.
Answer here
Please help

Answers

Answer:

24

Step-by-step explanation:

[tex]Convert\ the\ unit\ for\ \frac{12in}{1ft}:\\ \downarrow\\ 24[/tex]

I hope this helps you

:)

Question 7 of 10
One spring, a group of students measured rainfall totals at their school. This
chart shows how many inches of rain the students measured each month.
How many more inches did it rain in May than in April?
RAINFALL
MONTH
March
April
May
5.7
3.2
7.3
Help me god

Answers

Answer:

9

Step-by-step explanation:

10

Find the value of f(5) for the function.

F(x)=6+3x

Answers

Answer:

21

Explanation:

To solve this problem, you substitute in the 5 for the x creating this equation: f(5)=6+3(5).

f(5)=15+6

f(5)=21

If f(x)= 2x^3-12x^2+20x-16 and f(4)= 0, then find all the zeros of f(x) algebraically

Answers

Answer:

x = 4 is the only real zero

Step-by-step explanation:

Find the zero's of f(x)

2x³ - 12x² + 20x - 16 = 0x³ - 6x² + 10x  - 8 = 0x³ - 4x² - 2x² + 8x + 2x - 8 = 0x²(x - 4) - 2x(x - 4) + 2(x - 4) = 0(x - 4)(x² - 2x + 2) = 0(x - 4)(x² - 2x + 1 + 1) = 0(x - 4)[(x - 1)² + 1] = 0x - 4 = 0 ⇒ x = 4, we already know this(x - 1)² + 1 = 0 ⇒ (x - 1)² = - 1, no real solution as the square is never negative

Answer:

[tex]x=4, \quad x=1+i,\quad x=1-i[/tex]

(one real zero and 2 complex zeros)

Step-by-step explanation:

Given polynomial:

[tex]f(x)= 2x^3-12x^2+20x-16[/tex]

According to the Factor Theorem, if f(4) = 0 then (x - 4) is a factor of the given polynomial.

[tex]\implies f(x)=(x-4)(ax^2+bx+c)[/tex]

Expand the brackets:

[tex]\implies f(x)=ax^3+bx^2+cx-4ax^2-4bx-4c[/tex]

[tex]\implies f(x)=ax^3+(b-4a)x^2+(c-4b)x-4c[/tex]

Compare coefficients with the given polynomial:

[tex]\implies a=2[/tex]

[tex]\implies -4c=-16 \implies c=4[/tex]

[tex]\implies (b-4a)=-12 \implies b-8=-12 \implies b=-4[/tex]

Substitute the found values of a, b and c:

[tex]\implies f(x)=(x-4)(2x^2-4x+4)[/tex]

To find the zeros of f(x), set the function to zero and solve for x:

[tex]\implies (x-4)(2x^2-4x+4)=0[/tex]

[tex]\textsf{Therefore},\: (x - 4) = 0\: \textsf{ and }\: (2x^2-4x+4)=0[/tex]

[tex]\textsf{To solve}\: (2x^2-4x+4)=0\: \textsf{ use the quadratic formula}[/tex]

Quadratic Formula

[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]

Therefore:

[tex]\implies x=\dfrac{-(-4) \pm \sqrt{(-4)^2-4(2)(4)} }{2(2)}[/tex]

[tex]\implies x=\dfrac{4 \pm \sqrt{-16}}{4}[/tex]

[tex]\implies x=\dfrac{4 \pm \sqrt{16 \cdot -1}}{4}[/tex]

[tex]\implies x=\dfrac{4 \pm \sqrt{16}\sqrt{-1}}{4}[/tex]

[tex]\implies x=\dfrac{4 \pm 4i}{4}[/tex]

[tex]\implies x=1 \pm i[/tex]

Therefore, the zeros of the function are:

[tex]x=4, \quad x=1+i,\quad x=1-i[/tex]

(one real zero and 2 complex zeros)

Suppose that you have a square pyramid like the one pictured. Which plane section will produce a trapezoid? Question 17 options: A) A cross section cut parallel with the bottom B) A cut parallel to the vertical axis, but off the vertical axis C) A cut parallel to the vertical axis, directly through the vertical axis D) Cutting off one of the bottom corners

Answers

Answer:

B

Step-by-step explanation:

Cut vertical but off vertcal axis.

A will produce a square and C and D will produce triangles.

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