What is normal air pressure

Answers

Answer 1
[tex]⇒[/tex]

Standard sea-level pressure, by definition, equals 760 mm (29.92 inches) of mercury, 14.70 pounds per square inch, 1,013.25 × 103 dynes per square centimetre, 1,013.25 millibars, one standard atmosphere, or 101.325 kilopascals.


Related Questions

PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!


Having good form is important when sitting but not when sleeping.
A.
True

B.
False

PLEASE NO LINKS

Answers

Answer:

B. false

Explanation:

Because good form is not going to mess up your sitting it might mess up the way you sleep Because you don't know if you going to hurt 8n the moring

You throw a can of cranberry sauce straight up in the air with an initial velocity of 12 m/s. What is the maximum height the baseball reaches above your head.

Answers

Answer:

Δx=7.35m

Explanation:

This is a free fall problem (g= -9.8 m/s²).

Displacement: ? <--- what you're trying to find (max height)

Initial Velocity: 12 m/s

Final Velocity: 0 m/s <-- since the can will land back in your hands

Time: Missing <-- not needed to solve

Acceleration: -9.8 m/s²

The equation that you will use is vf²=vi²+2aΔx

Now plug the information into the equation!

(0m/s)²=(12m/s)²+2(-9.8m/s²)Δx

Multiply the 2 with the acceleration (-9.8m/s²)

(0m/s)²=(12m/s)²-19.6m/s²Δx

Now you need to square the final and initial velocity

0m/s=144m/s-19.6m/s²Δx

Move 144 to the other side of the equal sign

-144m/s=-19.6m/s²Δx

Divide both sides by -19.6m/s²

7.346m=Δx

You can round it to the tenth or hundreth place, up to you!

For this example, I'll round to the hundredth...

Δx=7.35m

I would double check this answer or review it yourself to see if it's correct.

Good luck with your studies!

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Jose’s doctor recommends that he add more cardio to his exercise routine. Which exercise would be the BEST choice?
A.
ballet
B.
jogging
C.
bowling
D.
volleyball


PLEASE NO LINKS OR I WILL REPORT YOU

Answers

Jogging

Explanation:
I learned in PE

Answer:

jogging

Explanation:

Jogging is often defined as running at a pace less than 6 miles per hour (mph), and it has some significant benefits for people who want to improve their health without overdoing it.

l. amount of liquid


ll. initial mass of the bone


lll. temperature of liquid

A.
l and lll

B.
II and III

C.
ll only

D.
l only

Answers

A.l and lll

- BRAINLIEST answerer

Suppose that a cart is moving along a road at a constant velocity. Give two examples of ways to cause the cart to decelerate, explaining how the net force is affected. (2 points)

Answers

The cart moving at a constant velocity will decelerate when a braking force is applied or the road is made to become rougher.

Deceleration is also known as negative acceleration. It occurs when velocity decreases with time. There are two ways by which the cart moving at constant velocity can be made to decelerate. These two ways are;

By applying a braking force: A braking force causes the velocity to decrease with time. When a braking force is applied the frictional force exceeds the forward force hence the net force decreases.By increasing the roughness of the road: When the roughness of the road is increased, the frictional force also increases causing the net force on the cart to decrease hence it decelerates.

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A cyclist is coasting at 12 m/s when she comes to a muddy stretch with an effective coefficient of friction of 0.60. Will the cyclist be able to get out of the muddy stretch without having to pedal if it lasts 10 meters

Answers

The cyclist will make it since the distance  traveled by the cyclist is greater than the length of the muddy stretch.

The given parameters;

speed of the cyclist, u = 12 m/scoefficient of friction, μ = 0.6length of the muddy stretch, L = 10 m

The effective acceleration of the cyclist at the given coefficient of friction is calculated as follows;

[tex]a = \ \mu g\\\\a = 0.6 \times 9.8\\\\a = 5.88 \ m/s^2[/tex]

The distance traveled by the cyclist at the give speed and acceleration is calculated as;

[tex]v^2 = u^2 + 2as\\\\12^2 = 0 + 2(5.88)s \\\\ 11.76 s = 144\\\\ s = \frac{144}{11.76} \\\\a = 12.24 \ m[/tex]

Thus, we can conclude that the cyclist will make it since the distance  traveled by the cyclist is greater than the length of the muddy stretch.

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Saturn’s moon titan has a mass of 1.35 × 10^23 kg. if titan is 1.19 × 10^6 km from saturn, and saturn’s mass is 5.86 × 1026 kg, what is the gravitational force between saturn and its moon?

Answers

Answer:The gravitational force equation is Fg=(G*M*m)/r² where, G is the gravitational constant, G=6.67*10^-11 m³/kg*s², M is the mass of Saturn, M=5.86*10^26, m is the mass of Titan, m=1.35*10^23 and r is the distance, r=1.19*10^6 km=1.19*10^9 m. Now we simply input the numbers into the equation:

Fg=(6.67*10^-11)*(5.86*10^26)*(1.35*10^23)/(1.19*10^6)²

Fg=(5.277*10^39)/(1.41*10^18)=3.743*10^21 N  

The correct answer is the third one.

Explanation:

A block of mass =4.20 kg slides along a horizontal table with velocity 0=3.50 m/s . At =0 , it hits a spring with spring constant =26.00 N/m and it also begins to experience a friction force. The coefficient of friction is given by =0.250 . How far has the spring compressed by the time the block first momentarily comes to rest? Assume the positive direction is to the right.

Answers

The distance in which the spring is compressed is 1.065 m.

The given parameters;

mass of the block, m = 4.2 kgvelocity of the block, v = 3.5 m/sspring constant, k = 26 N/mcoefficient of friction, μ = 0.25

Apply the principle of conservation of energy to determine the distance in which the spring is compressed.

[tex]K.E = W + U\\\\\frac{1}{2} mv^2 = \mu Fx \ + \ \frac{1}{2} kx^2\\\\\frac{1}{2}(4.2)(3.5)^2 = 0.25(4.2 \times 9.8)(x) \ + \frac{1}{2} (26)(x^2)\\\\25.725 = 10.29x \ + \ 13x^2\\\\13x^2 + 10.29x - 25.725 = 0\\\\[/tex]

solve the quadratic equation using formula method;

a = 13, b = 10.29,  c = -25.725

[tex]x = \frac{-b \ \ +/- \ \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-(10.29) \ \ +/- \ \sqrt{(10.29)^2 \ - \ 4(13\times 25.725)} }{2(13)} \\\\x = 1.065 \ m, \ \ or \ -1.86 \ m[/tex]

choose positive distance, x = 1.065 m.

Thus, the distance in which the spring is compressed is 1.065 m.

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describe an experiment that can be used to determine the resistance of a metallic conductor

Answers

Answer:

resistance of the metal conductor at different temperature

Explanation:

An experiment used to determine the resistance of a metallic conductor is the resistance of a metallic conductor at different temperatures.

What is Resistance?

Resistance is the property of a conductor to oppose the flow of charges through it which is numerically given as the ratio of the potential difference across its length to the current flowing through it.

Resistance of a metallic conductor is the measure of its opposition to the flow of electric current. Resistance is known to be directly proportional to the temperature which means as the temperature is increased, its resistance increases too and vice versa.

Resistance has an inverse relationship with the cross sectional area of ​​a metallic conductor, so if the resistance increases the cross sectional area decreases and vice versa.

Thus, an experiment used to determine the resistance of a metallic conductor is the resistance of a metallic conductor at different temperatures.

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If acceleration of a body starting from the rest is 0.5m/s^2 how long will it take the body to travel 400m(if u are genius answer this)​

Answers

Answer:

10s

Explanation:

Calculate the charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts.

Answers

The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb

Potential difference is the amount of work needed to move a unit charge from one point to another. It is given by:

V = E/Q

Where V is potential difference, E is energy and Q is charge. Given that:

V = 15 V, E = 5.25 kJ = 5.25 * 10³ J.

V = E/Q

15 = 5.25 * 10³ /Q

Q = 350 Coulomb

The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb

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Gold density = 19.30,
Silver density = 10.49,
Lead density = 11.34.

They have the same mass but are made of different metals. Each one is lowered into a beaker of water. Use the data above to decide which one will cause the biggest rise in water level.

A) Gold
B) Silver
C) Lead
D) All will cause the same rise in water level​

Answers

Density of gold=19.30g/cm^^3Density of silver=10.49g/cm^3Density of lead=11.34g/cm^3

Density of water=1g/cm^3

Now all metals has greater mass in comparison to water.

Higher the mass higher the rise

[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]

[tex]\\ \sf\longmapsto Density\propto Mass[/tex]

Higher the density higher the mass

Gold has higher mass hence it will cause the biggest rise.

Option A

Silver will cause biggest rise in water

What is density ?

Density of an object is a measure of its mass per unit volume.

density = mass / volume

since all have same mass , so metal which have higher volume will cause the biggest rise in water level .

since , density is inversely proportional to volume , hence material having low density will have higher volume

hence , silver will cause biggest rise in water

correct option B) Silver

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Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing.

How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.

From edge

Answers

Answer:

like 23 or something

Explanation:

A fairly efficient steam turbine engine fired by coal is used to drive an electric generator. The generator operates between 2100°C and 385°C.

(a) Determine the maximum possible efficiency of the engine.


Answer: 72.3 %


Formula:

e = 1 - (Tc / Th) = 1 - (Qc / Qh) = ( W / Qh)


Explanation: Unsure??


(b) The engine absorbs 1.15 105 J from the hot reservoir every second. If the actual efficiency of the engine is 40.3%, determine the mechanical power the engine delivers.


Answer: 46 kW


Explanation:

Energy absorbed by the engine (J) * actual efficiency of the engine (%) = mechanical power the engine delivers (kW)


How does 1 - (385/2100) = 72.3 % ?
What do I Plug in to make e = 72.3 %

Answers

Use kelvin not celsius

C + 273 = K

This will fix my problem of the equation not making sense.

A two-dimensional crystal has a rectangular unit cell, with spacings between the centers of the atoms of 0.5 nm in one direction (e.g., the x direction), and 0.4 nm in the other direction (e.g., the y direction). Presuming that the crystal has 1000 unit cells in each direction, sketch a representative portion of the reciprocal lattice on a scale drawing, showing the dimensions, units, and directions (i.e., kx and ky)

Answers

So directly the cell density value in a rectangle is:

[tex]5*10^{17} cells/cm^{2}[/tex]

In this exercise, we must first calculate the area of ​​the rectangle, remembering that you need to convert from nm to cm is:

[tex]A=B*H\\A=(0.4*10^{-7})*(0.5*10^{-7})= 2*10^{-15}[/tex]

Next, let's calculate the density from the calculated area:

[tex]\frac{N}{A} = \frac{1000}{2*10^{-15} } = 5*10^{17}[/tex]

In this way, the calculation represents that there is:

[tex]5*10^{17} cells/cm^{2}[/tex]

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What decides free energy.

Answers

Answer: when free energy is extensive property that means its magnitude depends on the amount  of a substance.

Explanation:

srry if im wrong :( .

Answer:

state of the system

Explanation:

If the depth of water in a well is 10m, what is the pressure exerted by it the bottom of the well ? ( Use g = 10 m/s2)
show the process as well​

Answers

Answer:

The precise answer depends on the density and therefore the temperature of the water, but we can obtain a reasonable approximation by assuming that the density of the water is 1000 kilograms per cubic meter (kg/m³).

Since the depth of the water in the well is 10 m, the volume of water directly above an area A of a square meters (m²) at the bottom of the well is 10×a m³.

Since the density of the water is 1,000 kg/m³, the mass of water directly above area A is (1,000 kg/m³) × (10×a m³) = (1000×10×a kg) = 10,000×a kg.

Since g = 9.8 m/s², the force of gravity acting on the water directly above area A is (9.8 m/s²) × (10,000×a kg) = 9.8×10,000×a N (newtons) = 98,000×a N.

So the pressure of water acting on area A is (98,000×a N)/(a m²) = (98,000×a)/a N/m² = 98,000 pascals (pa). And since A could be any given area at the bottom of the well, this is the pressure at any point at the bottom of the well.

So the pressure at the bottom of the well is 98,000 pascals (or 98,000/101,325 standard atmospheres = 560/579 atmospheres ~ 0.967 standard atmospheres).

Please comment below if you have any questions.

The wavelength is 1. 87 x 10-7 m. What is the frequency?.

Answers

Answer:

11.7 im pretty sure. i did the work so it should be correct

In the experiment shown below, which is greater, the force of gravity on the pith balls (Fg) or the electrostatic force between them (Fq)?

Answers

Answer:

Electronic force

Explanation:

Maybe because its warmer and may have more force

What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod

Answers

Answer:

C) 5ML^2

Explanation:

2 Spheres of mass M

Bug's mass 3M

Rod length 2L, radius L

Find Rotational Inertia I

I=Σmr^2

I=(3M+M+M)L^2

I=5ML^2

The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².

Rotational inertia of the system

The rotational inertia of the system is determined by summing all the masses together and multiply with the radius.

I(t) = Σmr²

Where;

m is the massr is the radius

I(t) = Inertia of the 2 spheres + inertia of the bug

I(t) = (M + M)L²  + (3M)L²

I(t) = 2ML² + 3ML²

I(t) = 5ML²

Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².

Complete question is below:

There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.

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If the acceleration of an object increases, what effect does this have on the Force and Mass?
A Force Increases, Mass Increases
B Force Decreases, Mass Decreases
C Force increases, Mass remains the same
D Force Decreases, Mass remains the same​

Answers

Answer:

Force Increases and Mass remains the same.

Explanation:

In general, a _______ intake manifold produces high torque at _______ engine rpm because of the increased amount of time between the air pulses due to the inertia of the long column of air.

Answers

There are two major types of intake manifold. In general, A long intake manifold produces high torque at lower engine rpm because of the increased time between the air pulses.

Intake Air Heating is made up of different methods that manufacturers do use to heat intake manifolds.

This Heating system on vehicles are often with emission controls, air cleaners use a thermostatic valve to control how much hot air enters the air cleaner.

Conclusively there are two forms of intake manifold. They are the long and short intake manifold.

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Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, stick together and move off after the collision. How does the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision?.

Answers

The value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].

According to the principle of conservation of linear momentum, the total momentum before and after collision is conversed.

[tex]m_av_a_1 + m_bv_b_1 = v(m_a + m_b)[/tex]

where;

[tex]v_a_1 \ \ and \ \ v_b_1[/tex] are the initial velocity of the cars before collisionv is the final velocity of the cars after collision

since the train car A is at rest, [tex]v_a _1 = 0[/tex]

[tex]m_bv_b_1 = v(m_a + m_b)[/tex]

The relationship between the final velocity and initial velocity of the cars is given as;

[tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex]

Thus, the value of the final velocity of train cars A and B after the collision compare to the initial velocity of train car B before the collision is [tex]v = \frac{ \ m_bv_b_1}{m_a \ + \ m_b}[/tex].

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Answer: the answer is the third option. Edge 2021

Explanation: i just answered the problem

A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?

Answers

Answer:

35N

Explanation:

force=mass×gravity

the mass is 5 and the gravity is 7 therefore:

force=7×5

=35N

I hope this helps

Explain why position is a dependent variable in a position versus time graph.

Answers

Answer:

Explanation:

The position depends on the time.  The longer the time, the further the distance.

Plzzzzzzzzz
Help
Will give brainlessness

Answers

Answer:

1. A

2. A; distance is scalar, displacement is vector

3. C ; position is on the y-axis

True or False: Objects fall at a constant speed.

Answers

Answer:

Explanation:

true

The answer going to be true

if a substance changes from a vapor to a liquid it ____ HELP FAST

Answers

Answer:

Explanation:

Condensing is the word used to indicate the change of state of a substance from vapor to liquid, as in this case. During condensation, the substance releases thermal energy to the environment, therefore the kinetic energy of the molecules in the vapor decreases until they become closer to each other and they start to be affected by the intermolecular forces and so the substance becomes a liquid.

What is the net force on a 4,000-kg car
that doubles its velocity from 15 m/s west
to 30 m/s west over 10 seconds?

Answers

Answer:

6000 N toward west

Explanation:

F = ma

a = 30-15/10 = 1.5 m/s^2 towards west

m = 4000 kg

F = 4000 x 1.5 = 6000 N towards west

The amount of heat that is needed to raise the temperature of 1
kg of some material by 1°C is called the of the material.
a. specific heat
b. state
c. temperature
d. charge

Answers

Answer:

a. specific heat

Explanation:

a. specific heat

A. Specific heat

Explanation:

The specific amount of heat produced to an object of specific mass is known as specific heat.
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