what is the base? Look at picture.

Answer:

the function that is graphed is y=½CSC(x)

Answer:

30 cm

Step-by-step explanation:

Since the length of tangents drawn from a point are equal, the perimeter is 3+3+9+9+3+3=30

Answer:

30 centimeter

Answer:

0.5

0.25

Step-by-step explanation:

The equation for the exponential function is f(x) = 0.5(0.25)ˣ after applying the concept of the function.

It is defined as a function that rapidly increases and the value of the exponential function is always positive. It denotes with exponent y = aˣ

where a is a constant and a>1

It is given that:

A 2-column table has 2 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is labeled f (x) with entries 8, 2, 0.5, 0.125, and 0.03125.

x     f(x)

-2     8

-1      2

0      0.5

1       0.125

2       0.03125

Let the function is:

f(x) = a(b)ˣ

Plug x = 0 and f(x) = 0.5

0.5 = a

Plug x = -1 and f(x) = 2

2 = 0.5(1/b)

b = 0.5/2 = 0.25

f(x) = 0.5(0.25)ˣ

Thus, the equation for the exponential function is f(x) = 0.5(0.25)ˣ after applying the concept of the function.

Learn more about the exponential function here:

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Answer:

c is the answer why cause I did it

C, just look at the "Total" for each single information.

the values in the inner grid combine multiple informations.

The table shows these data correctly entered in a two-way frequency is table C.

Two-way frequency tables show the potential connections between two sets of categorical data visually. The table's four (or more) inside cells contain the frequency (count) data, which is displayed above and to the left of the table's designated categories.

We have been the information 25 students play an instrument 20 are in a band 30 are not in a band.

So, the two way table is:

                                     Band            Not in Band       Total

Play instrument                20                   5                     25

Do not play instrument     0                     25                 25

Total                                  20                    30                50

So, Table C is Correct.

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9514 1404 393

Answer:

  (g·h)(-3) = 2.8

Step-by-step explanation:

Given:

  g(x) = (x +1)/(x -2)

  h(x) = 4 -x

Find:

  (g·h)(x) = g(x) × h(x)   for x = -3

Solution:

  g(-3) = (-3+1)/(-3-2) = -2/-5 = 2/5

  h(-3) = 4 -(-3) = 4 +3 = 7

Then the product is ...

  g(-3)·h(-3) = (2/5)(7) = 14/5 = 2.8

  (g·h)(-3) = 2.8

Answer:

the correct answer is, 4

Answer:

D. -4x(x - 2)(x+3)

Step-by-step explanation:

We are given the following trinomial:

[tex]-4x^3 - 4x^2 + 24x[/tex]

-4x is the common term, so:

[tex]-4x(\frac{-4x^3}{-4x} - \frac{4x^2}{-4x^3} + \frac{24x}{-4x}) = -4x(x^2+x-6)[/tex]

The second degree polynomial can also be factored, finding it's roots.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

x² + x - 6

Quadratic equation with [tex]a = 1, b = 1, c = -6[/tex]

So

[tex]\Delta = 1^{2} - 4(1)(-6) = 25[/tex]

[tex]x_{1} = \frac{-1 + \sqrt{25}}{2} = 2[/tex]

[tex]x_{2} = \frac{-1 - \sqrt{25}}{2} = -3[/tex]

So

[tex]x^2 + x - 6 = (x - 2)(x - (-3)) = (x - 2)(x + 3)[/tex]

The complete factorization is:

[tex]-4x(x^2+x-6) = -4x(x - 2)(x + 3)[/tex]

Thus the correct answer is given by option d.

Answer:

X * 0.8 = $64

x = $80

Step-by-step explanation:

9514 1404 393

Answer:

  y = 2x +4

Step-by-step explanation:

The slope can be found using the slope formula:

  m = (y2 -y1)/(x2 -x1)

  m = (12 -(-6))/(4 -(-5)) = 18/9 = 2

The y-intercept can be found from ...

  b = y -mx

  b = 12 -(2)(4) = 4

Then the slope-intercept equation for the line is ...

  y = mx +b

  y = 2x +4

Answer:

y=2x+4

Step-by-step explanation:

Hi there!

We want to find the equation of the line that passes through the points (-5, -6) and (4, 12)

The most common way to write the equation of the line is in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

First, let's find the slope of the line

The formula for the slope calculated from two points is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex], where ([tex]x_1[/tex], [tex]y_1[/tex]) and ([tex]x_2[/tex], [tex]y_2[/tex]) are points

We have everything needed to calculate the slope, but let's label the values of the points to avoid any confusion

[tex]x_1[/tex]=-5

[tex]y_1[/tex]=-6

[tex]x_2[/tex]=4

[tex]y_2[/tex]=12

Now substitute into the formula (remember: the formula has SUBTRACTION in it)

m=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m=[tex]\frac{12--6}{4--5}[/tex]

Simplify

m=[tex]\frac{12+6}{4+5}[/tex]

Add

m=[tex]\frac{18}{9}[/tex]

Divide

m=2

So the slope of the line is 2

Here is the equation so far:

y=2x+b

We need to find b

As the line will pass through both (-5, -6) and (4, 12), we can use the values of either one to solve for b

Let's take (4, 12) for instance

Substitute 4 as x and 12 as y

12=2(4)+b

Multiply

12=8+b

Subtract 8 from both sides

4=b

Substitute 4 as b in the equation

y=2x+4

Hope this helps!

Answer:

The slope of a line that goes through both [tex](-2,\, 7)[/tex] and [tex](2,\, -5)[/tex] would be [tex](-3)[/tex].

Step-by-step explanation:

The slope of a line is the ratio between rise and run between these two points.

The rise between two points is the change to the corresponding [tex]y[/tex] coordinates. Between [tex](-2,\, 7)[/tex] and [tex](2,\, -5)[/tex], the rise would be [tex](-5) - 7 = (-12)[/tex] (subtract the first [tex]y\![/tex]-coordinate from the second.)

The run between two points is the change to the corresponding [tex]y[/tex] coordinates. Between [tex](-2,\, 7)[/tex] and [tex](2,\, -5)[/tex], the rise would be [tex]2 - (-2) = 4[/tex] (likewise, subtract the first [tex]x[/tex]-coordinate from the second.)

Hence, the slope of this line would be:

[tex]\begin{aligned} \frac{\text{rise}}{\text{run}} &= \frac{-12}{4} = -3\end{aligned}[/tex].

Answer:

[tex]\displaystyle m = \frac{3}{4}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify points from graph.

Point (4, 0)

Point (0, -3)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Answer:

4% and 5% respectively

Step-by-step explanation:

Let the intrest rate be x in the first account at x% and (x+1)% in the second account.

ATQ, 100=(x)*1500/100+(x+1)*800/100

x=4.

Answer: x=52.6°

Step-by-step explanation:

To find the value of x, we have to use our SOHCAHTOA. We can eliminate sine and cosine because both uses hypotenuse, which is not labelled. Therefore, we use tangent.

[tex]tan(x)=\frac{17}{13}[/tex]

To find x, we want to use inverse tangent.

[tex]x=tan^{-1}(\frac{17}{13} )[/tex]      [plug into calculator]

[tex]x=52.6[/tex]

Now, we know that x=52.6°.

Answer:

Step-by-step explanation:

Answer:

[tex] \frac{ \sqrt{3} }{3} [/tex]

Step-by-step explanation:

[tex]\frac{1}{3} \div \sqrt{3} [/tex]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following data:

This year :

35, 45, 53, 57, 61, 65, 67, 69, 70, 71, 71, 72, 73, 74, 75, 77, 80, 81, 82, 83, 87, 90, 93, 95, 99

Mean = ΣX / n = 1825 / 25 = 73

The mode = 71 ( most frequently occurring)

Median = 1/2(n+1)th term = 1/(26) = 13th term

Median = 73

10 years ago :

51, 55, 56, 59, 65, 67, 68, 69, 69, 74, 75, 76, 77, 77, 79, 79, 79, 86, 87, 89, 90, 91, 91, 95, 98

Mean = ΣX / n = 1902 / 25 = 76.08

The mode = 79 ( most frequently occurring)

Median = 1/2(n+1)th term = 1/(26) = 13th term

Median = 77

According to the computed statistics, we can conclude that, today is worse than the past as the average score which is almost similar to the median value is higher 10 years ago and the modal score is better 10 years ago as well.

Answer:

csc = 6/5= 1.2

cot = √(11)/5= 0.6633

sin = 5÷6= 0.83333

Step-by-step explanation:

The following configurations are evaluated, as given or stated within the interrogate:

P(Q) = 0.6

P(R) = 0.9

When the variable constant of Q and R transition into independent events within the function notation, the product of the individual values, as equated to those particular independent variables, is required.

For example:

If P(Q) = 0.6 and P(R) = 0.9, and Q and R fuse, then find the product of 0.9 and 0.6 is obligated:

0.9 * 0.6 = 0.54

Thus, given the independent events, P(Q and R) is equivalent to 0.54.

ASK YOUR SIR BRO I DONT KNOW

Answer:

3/85

Step-by-step explanation:

that's the answer above

Answer:

<5

Step-by-step explanation:

exterior angles + the corresponding interior angle of the triangle = 180º or a straight angle

the only exterior angle shown in the diagram is <5, which corresponds to the interior <2

hope this helps!

Answer:

<5

Step-by-step explanation:

everything else is matched up perfectly so it has to be <5

Answer:

x = 20

y = 10

Answered by Gauthmat

Answer:

[tex] \sin(θ) = \frac{19}{41} \\ θ = 27.6 \\ θ = 28[/tex]

Answer:

χ² = 19

Pvalue = 0.0008 ( 4 decimal places)

WE reject the H0 and conclude that probability of complaint is not the same for the 5 industries

Step-by-step explanation:

H0 : probability of complaint is the same for the 5 industries.

H1: probability of complaint is not the same for the 5 industries.

Category ____ observed frequency

Bank _______ 26

Cable _______44

Car _________42

Cell _________60

Collection ____ 28

Total ________200

The test statistic ;

χ² = (O - E)² / E

O = Observed Frequency ; E = Expected Frequency

Expected Frequency, E = (1 / n) * total

n = number of industries = 5

Expected frequency, E = (1/5)*200 = 40

Expected frequency is the same for all, thus E for all 5 industries = 40

χ² = Σ(O - E)² / E;

χ² = (26-40)² / 40 + (44-40)² / 40 + (42-40)² / 40 + (60-40)² / 40 + (28-40)² / 40

χ² = 19

At α = 0.05 ; df = n-1 = 4 ; χ²critical = 0.000786

Since Pvalue < α ; WE reject the H0 and conclude that probability of complaint is not the same for the 5 industries.

Answer:

6x10^4

Step-by-step explanation:

Answer:

864

Step-by-step explanation:

do the square root of the total number

Answer:

12*(3)^x

Step-by-step explanation:

Let the exponential function be y=a*b^x. Given y(0)=12, a=12. Next y(2)=36, b=3

Answer:

Your answer is f(x)=4(3)x

Step-by-step explanation:

Mark me brainliest :)

Answer:

8 sqrt(5)

Step-by-step explanation:

sqrt(45) + sqrt(125)

Rewriting

sqrt(9*5) + sqrt( 25 *5)

we know sqrt(ab) = sqrt(a) sqrt(b)

sqrt(9) sqrt(5) + sqrt(25) sqrt(5)

3 sqrt(5)+5 sqrt(5)

Add like terms

8 sqrt(5)

Answer:

A.    [tex] 8\sqrt{5} [/tex]

Step-by-step explanation:

[tex] \sqrt{45} + \sqrt{125} = [/tex]

[tex] = \sqrt{9 \times 5} + \sqrt{25 \times 5} [/tex]

[tex] = 3\sqrt{5} + 5\sqrt{5} [/tex]

[tex] = 8\sqrt{5} [/tex]

Let S and T denote the two finite sums,

S = 1 + x + x ² + x ³ + … + x ᴺ

T = 1 - x + x ² - x ³ + … + (-x) ᴺ

• If both S = 8 and T = 8 as N goes to infinity:

Then

xS = x + x ² + x ³ + x ⁴ + … + x ᴺ⁺¹

-xT = -x + x ² - x ³ + x ⁴ + … + (-x) ᴺ⁺¹

so that

S - xS = 1 - x ᴺ⁺¹   ==>   S = (1 - x ᴺ⁺¹)/(1 - x)

and similarly,

T = (1 - (-x) ᴺ⁺¹)/(1 + x)

For both sums, so long as |x| < 1, we have

lim [N → ∞] S = 1/(1 - x)

lim [N → ∞] T = 1/(1 + x)

Then if both sums converge to 8, this happens for

S : 1/(1 - x) = 8   ==>   x = 7/8

T : 1/(1 + x) = 8   ==>   x = -7/8

• If the sum S + T = 8 as N goes to infinity:

From the previous results, we have

1/(1 - x) + 1/(1 + x) = 8   ==>   x = ±√3/2

Answer:

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.

Step-by-step explanation:

For each parachute, there are only two possible outcomes. Either there is damage, or there is not. The probability of there being damage on a parachute is independent of any other parachute, which means that the binomial probability distribution is used to solve this question.

To find the probability of damage on a parachute, the normal distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Probability of a parachute having damage.

The opening altitude actually has a normal distribution with mean value 185 and standard deviation 32 m, which means that [tex]\mu = 185, \sigma = 32[/tex]

Equipment damage will occur if the parachute opens at an altitude of less than 100 m, which means that the probability of damage is the p-value of  Z when X = 100. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{100 - 185}{32}[/tex]

[tex]Z = -2.66[/tex]

[tex]Z = -2.66[/tex] has a p-value of 0.0039.

What is the probability that there is equipment damage to the payload of at least one of five independently dropped parachutes?

0.0039 probability of a parachute having damage, which means that [tex]p = 0.0039[/tex]

5 parachutes, which means that [tex]n = 5[/tex]

This probability is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{5,0}.(0.0039)^{0}.(0.9961)^{5} = 0.9807[/tex]

Then

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.9807 = 0.0193[/tex]

0.0193 = 1.93% probability that there is equipment damage to the payload of at least one of five independently dropped parachutes.