What is the slope for these cordinates


(-8,11) , (17,4)

Answer:

14.4 i hope it helped you

The total distance the particle travels from t=0 seconds to t=4 seconds would be 11.33 meters.

Used the concept of integration that states,

In Maths, integration is a method of adding or summing up the parts to find the whole. It is a reverse process of differentiation, where we reduce the functions into parts.

Given that,

A particle moves along a line with a velocity v(t) = t² - t - 6, measured in meters per second.

Now the total distance the particle travels from t=0 seconds to t=4 seconds is,

D = ∫₀⁴ |(t² - t - 6)| dt

D =  ∫₀⁴ (t²) dt - ∫₀⁴ (t) dt -  ∫₀⁴ (6) dt

D = (t³/3)₀⁴ - (t²/2)₀⁴ - 6 (t)₀⁴

D =| (64/3) - (16/2) - 6 (4)|

D = | (64/3) - 8 - 24 |

D = | (64/3) - 32|

D = 11.33 meters

Therefore, the total distance is 11.33 meters.

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Answer:

900°

Step-by-step explanation:

The interior angles sum = 180° ( n - 2 )

~~~~~~~~

n = 7

180° ( 7 - 2 ) = 900°

Answer:

900 degrees

Step-by-step explanation:

just apply the formulas discussed in class !

The sum of interior angles in a triangle is 180°. To find the sum of interior angles of a polygon, multiply the number of triangles in the polygon by 180°.

The number of triangles in each polygon is two less than the number of sides.

The formula for calculating the sum of interior angles is:

(n−2)×180∘ (where n is the number of sides)

in our case we have 7 sides.

so, we could split this polygon into 5 triangles.

each of these triangles would have an angle sum of 180°.

so, the angle sum of the polygon is

5×180 = 900°

Given:

The population, P, of six towns with time t in years are given by the following exponential equations:

(i) [tex]P=1000(1.08)^t[/tex]

(ii) [tex]P = 600 (1.12)^2[/tex]

(iii) [tex]P =2500 (0.9)^t[/tex]

(iv) [tex]P=1200 (1.185)^t[/tex]

(v) [tex]P=800 (0.78)^t[/tex]

(vi) [tex]P=2000 (0.99)^t[/tex]

To find:

The town whose population is decreasing the fastest.

Solution:

The general form of an exponential function is:

[tex]P(t)=ab^t[/tex]

Where, a is the initial value, b is the growth or decay factor.

If b>1, then the function is increasing and if 0<b<1, then the function is decreasing.

The values of b for six towns are 1.08, 1.12, 0.9, 1.185, 0.78, 0.99 respectively. The minimum value of b is 0.78, so the population of (v) town  [tex]P=800 (0.78)^t[/tex] is decreasing the fastest.

Therefore, the correct option is b.

Answer:

$968.78

Step-by-step explanation:

multiply worked hours by her pay per hour

38.52×$25.15=

38.52×$25.15=$968.778

then you round it to the nearest hundredth

since the thousandth is greater than 5 the 8 will round the 7 to an 8

giving you $968.78

Answer: $977.50

Step-by-step explanation:

(38)(25.15)=955.70

(52)(25.15)/60=21.80

955.70 + 21.80 = 977.50

Answer:

[tex] \rm\cos({600}^{ \circ} ) =-1/2 [/tex]

Step-by-step explanation:

we would like to solve the following using double-angle formula:

[tex] \displaystyle \cos( {600}^{ \circ} ) [/tex]

there're 4 double Angle formulas of cos function which are given by:

[tex] \displaystyle \cos(2 \theta) = \begin{cases} i)\cos^{2} ( \theta) - { \sin}^{2}( \theta) \\ii) 2 { \cos}^{2}( \theta) - 1 \\iii) 1 - { \sin}^{2} \theta \\ iv)\dfrac{1 - { \tan}^{2} \theta}{1 + { \tan}^{2} \theta } \end{cases}[/tex]

since the question doesn't allude which one we need to utilize utilize so I would like to apply the second one, therefore

step-1: assign variables

to do so rewrite the given function:

[tex] \displaystyle \cos( {2(300)}^{ \circ} ) [/tex]

so,

Step-2: substitute:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2 \cos ^{2} {300}^{ \circ} - 1[/tex]

recall unit circle thus cos300 is ½:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2 \left( \dfrac{1}{2} \right)^2 - 1[/tex]

simplify square:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = 2\cdot \dfrac{1}{4} - 1[/tex]

reduce fraction:

[tex] \rm\cos(2 \cdot {300}^{ \circ} ) = \dfrac{1}{2} - 1[/tex]

simplify substraction and hence,

[tex] \rm\cos({600}^{ \circ} ) = \boxed{-\frac{1}{2}}[/tex]

Answer:

B

-10-10=20

10+10=20

20/20=0

Step-by-step explanation:

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Answer:

24

Step-by-step explanation:

The question is asking for the net area from x=3 to x=10.

It gives you the net area from x=3 to x=5 being -18.

It gives you the net area from x=5 to x=10, being 42.

Together those intervals make up the interval we want to find the net area for.

-18+42=42-18=24

Answer:

[tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt = 24[/tex]

General Formulas and Concepts:

Calculus

Integration

Integration Property [Splitting Integral]:                                                               [tex]\displaystyle \int\limits^c_a {f(x)} \, dx = \int\limits^b_a {f(x)} \, dx + \int\limits^c_b {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^{5}_3 {f(t)} \, dt = -18[/tex]

[tex]\displaystyle \int\limits^{10}_5 {f(t)} \, dt = 42[/tex]

[tex]\displaystyle \int\limits^{10}_3 {f(t)} \, dt[/tex]

Step 2: Integrate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Answer:

115 in.^2

Step-by-step explanation:

The total surface area is the sum of the areas of the square base and the 4 congruent triangular faces.

SA = b^2 + 4 * bh/2

SA = (5 in.)^2 + 4 * (5 in.)(9 in.)/2

SA = 25 in.^2 + 2 * 45 in.^2

SA = 115 in.^2

Answer:

y = 2 - [tex]x^{2}[/tex]

Step-by-step explanation:

[tex]x^{2}[/tex] results in a parabola (U-shape). Adding a negative in front of it flips the parabola to look like an upside-down U.

The 2 makes it shift up two decimal spots to (0,2).

Given:

Amplitude = 21

Vertical shift = 19 units down

To find:

The maximum and the minimum value.

Solution:

The general form of sine function is:

[tex]y=A\sin (Bx+C)+D[/tex]

Where, |A| is amplitude, [tex]\dfrac{2\pi}{B}[/tex] is period, [tex]-\dfrac{C}{B}[/tex] is phase shift and D is the vertical shift.

Here,

[tex]Maximum=D+A[/tex]

[tex]Minimum=D-A[/tex]

We have,

Amplitude: [tex]A = 21[/tex]

Vertical shift: [tex]D=-19[/tex]

Negative sign means shifts downwards.

Now,

[tex]Maximum=D+A[/tex]

[tex]Maximum=-19+21[/tex]

[tex]Maximum=2[/tex]

And,

[tex]Minimum=D-A[/tex]

[tex]Minimum=-19-21[/tex]

[tex]Minimum=-40[/tex]

Therefore, the minimum value is -40 and the maximum value is 2.

The statement that is true about the quadratic equation is (b) There are two complex solutions.

From the question, we have the following parameters that can be used in our computation:

y = 12 – 11x + 7

Express properly

So, we have

y = 12x² – 11x + 7

Next, we calculate the discriminant using

d = b² - 4ac

Where

a = 12

b = -11

c = 7

Substitute the known values in the above equation, so, we have the following representation

d = (-11)² - 4 * 12 * 7

Evaluate

d = -215

This value is less than 0

This means that it has complex solutions

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Answer:

1)9-7+x

2+x

2)8-2x+5x

8+3x

3)-x+3x-9

2x-9

4)4x-4x-6

-6

you have to group the like terms

I hope this helps and sorry if they are wrong

Answer:

Step-by-step explanation:

Because those lines are parallel, that means that the angle measuring 75 and the angle measuring 4x + 7 are alternate interior and by definition are congruent. Therefore,

75 = 4x + 7 and

68 = 4x so

x = 17

Answer:

B

Step-by-step explanation:

Answer:

C  

Step-by-step explanation:

Answer:

hi how are u I am fine by the way I hope that I dont know the answers

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