Which expressions are polynomials?
Select each correct answer.

Which Expressions Are Polynomials?Select Each Correct Answer.

Answers

Answer 1

Answer:

b and d option are correct

Answer 2

Answer:

B, D

Step-by-step explanation:

B, D

x cannot be in a root.  (A)

x cannot be in the denominator.  (C)


Related Questions

Find the number that makes the ratio equivalent to 1:9.
7:

Answers

Answer:

7:63

Step-by-step explanation:

It's a 1 to 9 ratio, which means the second number is 9 times bigger.

To make it equivalent, you need to make 7 9 times bigger as well.

7x9=63

Answer: 7:63

The perimeter of a rectangle is $98,$ and the length of one of its diagonals is $41.$ Find the area of the rectangle.

Answers

Answer:

[tex]328units^2[/tex]

Step-by-step explanation:

First off,  I do want to say that you could word this more easily.

98 is the perimeter. length is 41. width is 8.

the area is length*width for rectangles.

98-41=57

57-41=16

16/2=8

8*41=328 units^2

What is the percent if 200 is the total and 150 is the part?

Answers

Answer:

75%

Step-by-step explanation:

75% of 200 is 150

Answer:

75% since [tex]50 + 50 + 50 = 150[/tex] which is [tex]3[/tex] quarters of [tex]200[/tex]

Please mark brainliest.

What is the vertex of the graph of the function f(x) = x² + 8x - 2?
(-4,18)
(0,-2)
(-8, -2)
(-4,-18)

Answers

Answer:

(4, -18)

Step-by-step explanation:

First  Use this formula for the x -axis  -b/2a  

-8/2(1) is -4

Then plug in -4 to the equation

(-4)^2+8(-4)-2 = -18

help me with this math question​

Answers

x= 0.84106.. + 27n, r = 7 - 0.84106.. + 27n

[tex]\text{Given that,} \sin x = \dfrac{\sqrt 5}3,~~ \text{and}~~~ \sin y =\dfrac{\sqrt 2}2\\\\\\~~~~~~~\sin x = \dfrac{\sqrt 5}3\\\\\implies \sin^2 x = \dfrac 59\\\\\implies 1- \cos^2 x = \dfrac 59\\\\\implies \cos^2 x =1- \dfrac59 \\\\\implies \cos^2 x = \dfrac 49\\\\\implies \cos x = \dfrac 23~~~~~~~;[\text{In quadrant I, all ratios are positive.}]\\\\\\\\[/tex]

[tex]~~~~~~\sin y =\dfrac{\sqrt{2}}2\\ \\\implies \sin y = \dfrac 1{\sqrt 2}\\\\\implies \sin^2 y = \dfrac 12\\\\\implies 1-\cos^2 y = \dfrac 12\\\\\implies \cos^2 y = 1-\dfrac 12=\dfrac 12\\\\\implies \cos y = \dfrac 1{\sqrt 2}\\\\\\[/tex]

[tex]\text{Now,}\\\\\cos(x+y) = \cos x \cos y - \sin x \sin y\\\\\\~~~~~~~~~~~~~~=\dfrac 23 \cdot \dfrac 1{\sqrt 2}- \dfrac{\sqrt 5}3 \cdot \dfrac 1{\sqrt 2}\\\\\\~~~~~~~~~~~~~~=\dfrac{2- \sqrt 5}{3\sqrt 2}\\\\\\~~~~~~~~~~~~~~=\dfrac{\sqrt2\left(2 -\sqrt 5 \right)}6[/tex]

A spherical ball holds about 523 cubic
centimeters of air. Find the radius of the ball
to the nearest whole number. Use 3.14 for TT. ANSWER FAST

Answers

Answer:

r=4.998

Step-by-step explanation:

The equation for volume of a sphere is [tex]V = \frac{4}{3} \pi r^3[/tex].

We can subsatute 523 in for V and then solve for r by multiplying both sides by 3 and then dividing both sides by 4pi.  Then, take the cube root of each side and you will get r.

A factor delivered 284 boxes of books to stores. There are 20 books in each box. How many books did the factor deliver?​

Answers

Answer:

284*20

Step-by-step explanation:

since there are 284 boxes of each 20 books, 1box = 20 books then 284 boxes = (284*20) books

If factor delivered 284 boxes of books to stores and 20 books in each box then the total number of books deliver by factor are 5680.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

Given that a factor delivered 284 boxes of books to stores.

There are 20 books in each box.

We have to find the number of books the factor deliver

To find this we have to multiply the number of boxes with the number of books in a box

Number of books deliver = 284×20

Two hundred eighty four times of twenty

Number of books deliver =5680

Hence, if factor delivered 284 boxes of books to stores and 20 books in each box then the total number of books deliver by factor are 5680.

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If y = sin(x)
Prove that dy/dx = y cot(x)

Answers

[tex]y=sin(x)\implies \cfrac{dy}{dx}=\boxed{cos(x)} \\\\[-0.35em] ~\dotfill\\\\ ycot(x)\implies \stackrel{y}{~~\begin{matrix} sin(x) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cfrac{cos(x)}{~~\begin{matrix} sin(x) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\implies \boxed{cos(x)}[/tex]

May you help me please I am stressed and struggling

Answers

Answer:

The answer would be 2x+4+3x+4, 5x+8, and 2(2x+4) +x

Step-by-step explanation:

Step 1. Simplify 2x+4+3x+4 into 5x (combine the x's) +8 (combine the 2 4's)
Step 2. Simplify 2(2x+4)= x into 4x + 8 + x (<-- distribute the 2 to the 2x and 4) and 4x+x would equal 5x meaning 5x + 8.
I hope that this helps! :)

PLEASE HELP IF ABLE TO xx

Answers

Answer:

y = 120°

Step-by-step explanation:

If AC ≅ AD and BC ≅ BD then the shape of the figure is a kite.

Therefore, ∠D ≅ ∠C

Sum of interior angles in a kite = 360°

⇒ ∠A + ∠B + ∠C + ∠D = 360°

⇒ 120° + ∠B + 100° + 100° = 360°

⇒ ∠B = 40°

Sum of interior angles of a triangle = 180°

⇒ ∠B + ∠BDY + ∠y = 180°

⇒ 40° + 20° + ∠y = 180°

⇒ ∠y = 120°

A store sells t-shirts and pants combinations for $50. If the pants cost $10 more
than the t-shirts, find the cost of each.
( help me please)

Answers

Answer:

the shirt should be $20 and the pants $30

9
Manuel bought supplies for a school project for $11.29. He paid with a $20 bill. How much change did he get back?
OA $31.29
OB. $8.71
OC. $7.71
OD. $8.81
Reset
Next

Answers

Answer:

B

Step-by-step explanation:

$20-$11.29= 8.71 change he wil get back

The sum of two numbers is 5/9.if one of the numbers is 1/3 find the other

Answers

Answer:

2/9

Step-by-step explanation:

The sum of two numbers is 5/9 can be expressed as:

[tex]\displaystyle \large{x+y=\dfrac{5}{9}}[/tex]

One of the numbers is 1/3. Find the other - this means that either x or y is 1/3 but that doesn’t matter as we can either let x = 1/3 or y = 1/3 via property:

[tex]\displaystyle \large{x+y = y+x}[/tex]

Hence, let x = 1/3:

[tex]\displaystyle \large{\dfrac{1}{3}+y=\dfrac{5}{9}}[/tex]

Solve for y - subtract both sides by 1/3:

[tex]\displaystyle \large{\dfrac{1}{3}-\dfrac{1}{3}+y=\dfrac{5}{9}-\dfrac{1}{3}}\\\displaystyle \large{y=\dfrac{5}{9}-\dfrac{1}{3}}[/tex]

We know that we can only evaluate the fractions if both have same denominator so what we have to do is to multiply 1/3 by 3 for both top and bottom:

[tex]\displaystyle \large{y=\dfrac{5}{9}-\dfrac{1\cdot 3}{3\cdot 3}}\\\displaystyle \large{y=\dfrac{5}{9}-\dfrac{3}{9}}\\\displaystyle \large{y=\dfrac{2}{9}}[/tex]

Therefore, the other number is 2/9

Answer:

The other number is 2/9

Step-by-step explanation:

"a" is the other number

The equation:

[tex]a+\frac{1}{3} =\frac{5}{9}[/tex]

Then

[tex]a=\frac{5}{9} -\frac{1}{3} =\frac{15-9}{27} =\frac{6}{27}[/tex]

simplifying the fraction:

[tex]a = \frac{2}{9}[/tex]

Hope this helps

Where is the blue dot on the number line?

Answers

Answer:

-2.1

Step-by-step explanation:

its a 0.1 step.

hope you understand

a) Factorise
x2 - 422

Answers

Answer:

(x + 42)(x - 42)

Step-by-step explanation:

Keep this in mind :

a² - b² = (a + b)(a - b)

In this case,

a = xb = 42

So, by factorizing,

x² - 42² = (x + 42)(x - 42)

★a²-b²=(a+b)(a-b)

So

x²-42²

a=x ,b=42

(x+42)(x-42)

Done!

Three sides of a quadrilateral are the same length, q. The length of the fourth side is 7 inches. The perimeter of the quadrilateral is 40 inches. Write an equation that represents the situation. PLEASE HURRY, I DONT HAVE MUCH TIME, WILL MARK BRAINLIEST.

Answers

Answer:

Equations: 40-7=33 and 33÷11=3

Step-by-step explanation:

40-7=33

Since there are 3 sides,(q) then you do 33 divided by 3=11.

Equations: 40-7=33

And

33÷11=3

If f(x)=2x-3 then find the expression given by f(a+h)-f(a)/h

Answers

[tex]\text{Given that,}~ f(x) =2x-3\\\\\dfrac{f(a+h) - f(a)}{h}\\\\=\dfrac{(2(a+h)-3)-(2a-3)}{h}\\\\=\dfrac{2a+2h-3-2a+3}h}\\\\=\dfrac{2h}{h}\\\\=2[/tex]

PLEASE HELP WILL GIVE BRAINLIEST!!!!​

Answers

The equation is

4x - 3 = 5
4x - 3 + 3 = 5 + 3
4x = 8
4x / 4 = 8 / 4
x = 2

Pythagorean Theorem
(Rounding)
Find the length of the third side. If necessary, round to the nearest tenth.

SOMEONE PLEASE HELP ME ILL GIVE YOU BRAINLIST ANSWER AND POINTS!!!!

IMAGE DOWN BELOW!!

Answers

the answer is 10.6 :)
Answer: a = 10.6

Pythag is a squared + b squared = c squared
We have c and b so we can sub those in to get a squared + 12 squared = 16 squared
Which equals a squared + 144 = 256
Then we - 144 from both sides to get a squared = 112
Then we square root 112 to get a = 10.6
Hope that helps

Joe is 1.6 m tall. His shadow is 2 m long when he stands 3 m
from the base of a floodlight. What is the height of the floodlight?

Answers

Answer:

Step-by-step explanation:

Find the surface area of the can of milk at the right. [tex] \bold{Use \: π = 3.14}[/tex][tex] \red{*}[/tex]

Answers

Answer:

The Surface area of milk can is 43.96cm²

Solution:

The milk can is in the shape of a cylinder.

The surface area of cylinder is defined as the sum of curved surface and the two circular bases of the cylinder;

‎ㅤ‎ㅤ‎ㅤ➙ (curved surface ) + 2(base area )

‎ㅤ‎ㅤ‎ㅤ➙ 2πrh + 2πr²

‎ㅤ‎ㅤ‎ㅤ➙ 2πr( h + r )

Here, in this question we have;

radius ( r ) = 2/2 = 1 cm

height ( h ) = 6 cm

Therefore, Surface Area ( S.A ) :

S.A = 2πr( r + h )

S.A = 2 × π × 1 ( 1 + 6 )

S.A = 2π ( 7 )

S.A = 2 × 3.14 × 7

S.A = 14 × 3.14

S.A = 43.96cm²

Answer:

Surface area of cylindrical milk can is 43.96cm²

Step-by-step explanation:

Given :-

height of can of milk :- 6cm diameter :- 2 cm , radius :- 1cm

To find:-

Surface area of milk can

Solution:-

formula for surface area cylindrical milk can :-

2πr(h+r)

putting the known values ,

2 × 3.14 × 1 (6+1) cm²

Surface area :- 43.96 cm²

Please help mee l don’t understand new topic please

Answers

Answer to first four-

first one- 2f+2f=60

4f=60

f=15

second one-18+2d=38

2d=20

d=10

(short side is 9)

third one-2a+a+5+a+5=26

4a+10=26

a=4

long side is 9

short side is 8

fourth one-3xy+3xy+xy=63

7xy=63

xy=9

long side is 27

HELP ASAP BEING TIMED! If Triangle J K L is congruent to Triangle B C A, which statement must be true?

A)Segment J K is congruent to Segment A B

B)Segment J K is congruent to Segment K L

C)Segment J L is congruent to Segment B A

D)Segment J L is congruent to Segment B C

Answers

Answer:

Choice C

Step-by-step explanation:

This is like a matching question. Here's what I mean by this. We know Triangle BCA and Triange JKL are congruent. So, what we have to do is match the side lengths together.

So the first side of BCA matches with JKL, the second side of BCA matches with JKL, the third side of BCA matches with JKL.

So first side:

BC is congruent  to JK

So second side:

CA is congruent  to KL

So third side:

JL is congruent  to BA

The third side is one of our answer choices.

That answer choice is C.

Answer:

c

Step-by-step explanation:

Brittany has a black skirt, a violet skirt, a white skirt, and a red skirt. She has a yellow top, a pink top, and a green top. She wants to wear a skirt and a top. What are all the possible outcomes? How many possible outcomes are in the sample space?

7 possible outcomes: BB, VV, WW, RR, YY, PP, GG
12 possible outcomes: BY, BP, BG, VY, VP, VG, WY, WP, WG, RY, RP, RG
7 possible outcomes: B, V, W, R, Y, P, G
12 possible outcomes: BY, BP, BG, BV, BW, BR, VY, VP, VG, VB, VW, VR

Answers

Answer:

B

Step-by-step explanation:

12:

BY, BP, BG, VY, VP, VG, WY, WP, WG, RY, RP, RG

A mute for a brass instrument is formed by taking a solid cone with a radius of 10 centimeters and an altitude of 20 centimeters and cutting off the top. The cut is made along a plane that is perpendicular to the altitude of the cone and intersects the altitude 6 centimeters from the vertex. Round your answers to the nearest hundredth.

What is the surface area of the original cone?
What is the surface area of the cone that is removed?
What is the surface area of the mute?

Answers

By using the formula for the area of a cone, we will get:

i)  942 cm^2ii)  84.78cm^2iii)  885.48cm^2

How to get the surface areas?

First, let's find the area of the original cone. Remember that for a cone of radius R and height H, the surface area is:

A  = pi*R^2 + pi*R*H

Then for the original cone where:

R = 10cm

H = 20cm

The area is:

A = 3.14*(10cm)^2 + 3.14*10cm*20cm = 942 cm^2

Now, we remove a smaller cone at 6 cm from the vertex, so we are removing a cone with height of 6 cm, and the radius of this cone is given by:

R' = R*(H'/H) = 10cm*(6cm/20cm) = 3cm

So the area of the removed cone is:

A' = 3.14*( (3cm)^2 + 3cm*6cm) = 84.78cm^2

The final area of the mute will be equal to the difference between the area of the original cone and the area of the removed cone, plus the area of the top cross-section (a circle of radius of 3cm)

A'' = 942 cm^2 - 84.78cm^2 + 3.14*(3cm)^2 = 885.48cm^2

If you want to learn more about areas, you can read

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Name two sides that appear to be perpendicular

Answers

Step-by-step explanation:

Adjacent sides of a square and a rectangle are always perpendicular to each other. Sides of the right-angled triangle enclosing the right angle are perpendicular to each other.

Use trigonometry to work out the size of angle y.
+
+
11 cm
у
6 cm

Answers

Answer:

17+y

Step-by-step explanation:

What is the sum of 2/5 and 1/8

Answers

21/40 is the answer because you need to multiply the denominators to get the same lowest value. in this instance, that is 40 because 5•8 = 40 and 8•5 = 40

HELP PLEASE!!!

What is the slope of the line that is perpendicular to the line -12x = 35 - 5y?

Answers

Answer:

y = 12/5 = x + 7

hope this helped

lol

What additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS? Check all that apply. ∠Z ≅ ∠G and XZ ≅ FG ∠Z ≅ ∠G and ∠Y ≅ ∠E XZ ≅ FG and ZY ≅ GE XY ≅ EF and ZY ≅ FG ∠Z ≅ ∠G and XY ≅ FE

Answers

Answer:

∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE  are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.

The additional information to prove that ΔXYZ ≅ ΔFEG using ASA or AAS

is ∠Z ≅ ∠G and XY ≅ FE

Option E is the correct answer.

What is a triangle?

It is a two-dimensional figure which has three sides and the sum of the three angles is equal to 180 degrees.

We have,

ΔXYZ ≅ ΔFEG

We see that,

∠X and ∠F are equal

To prove that ΔXYZ ≅ ΔFEG using ASA or AAS.

We need one more congruent angle and one corresponding side.

∠Z ≅ ∠G and XY ≅ FE can be used to prove this.

Now,

∠X = ∠F (angle)  (given)

∠Z ≅ ∠G (angle)

XY ≅ FE (side)

ΔXYZ ≅ ΔFEG

Thus,

The additional information is:

∠Z ≅ ∠G and XY ≅ FE

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